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Mathematics LibreTexts

8.4 Vectors

A woman leaves home, walks 3 miles north, then 2 miles southeast.  How far is she from home, and in which direction would she need to walk to return home?  How far has she walked by the time she gets home?

This question may seem familiar – indeed we did a similar problem with a boat in the first section of this chapter.  In that section, we solved the problem using triangles.  In this section, we will investigate another way to approach the problem using vectors, a geometric entity that indicates both a distance and a direction.  We will begin our investigation using a purely geometric view of vectors.

A Geometric View of Vectors

 

Vector

A vector is an object that has both a length and a direction.

 

Geometrically, a vector can be represented by an arrow that has a fixed length and indicates a direction.  If, starting at the point A, a vector, which means “carrier” in Latin, moves toward point B, we writeFile:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image002.gif to represent the vector.

 

A vector may also be indicated using a single letter in boldface type, like u, or by capping the letter representing the vector with an arrow, like File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image004.gif.

 

 

Example 1

Find a vector that represents the movement from the point P(-1, 2) to the point Q(3,3)

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image006.jpg

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image007.gifBy drawing an arrow from the first point to the second, we can construct a vector File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image009.gif.

 

 

Using this geometric representation of vectors, we can visualize the addition and scaling of vectors. 

 

To add vectors, we envision a sum of two movements.  To find File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image011.gif, we first draw the vector File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image004.gif, then from the end of File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image004.gif we drawn the vector File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image013.gif.  This corresponds to the notion that first we move along the first vector, and then from that end position we move along the second vector.  The sum File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image011.gif is the new vector that travels directly from the beginning of File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image004.gif to the end of File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image013.gifin a straight path.

Adding Vectors Geometrically

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image016.gifTo add vectors geometrically, draw File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image013.gif starting from the end of File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image004.gif.  The sum File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image011.gif is the vector from the beginning of File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image004.gif to the end of File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image013.gif.

 

 

 

 

Example 2

Given the two vectors shown below, draw File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image011.gif

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image017.gif

 

 

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image018.gif

 

 

We draw File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image013.gif starting from the end of File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image004.gif, then draw in the sum File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image011.gif from the beginning of File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image004.gif to the end of File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image013.gif.

 

Notice that path of the walking woman from the beginning of the section could be visualized as the sum of two vectors.  The resulting sum vector would indicate her end position relative to home.

 

Try it Now

  1. Draw a vector, File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image013.gif, that travels from the origin to the point (3, 5).

 

Note that although vectors can exist anywhere in the plane, if we put the starting point at the origin it is easy to understand its size and direction relative to other vectors.

To scale vectors by a constant, such as File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image021.gif, we can imagine adding File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image023.gif.  The result will be a vector three times as long in the same direction as the original vector.  If we were to scale a vector by a negative number, such as File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image025.gif, we can envision this as the opposite of File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image004.gif; the vector so that File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image027.gif returns us to the starting point.  This vector File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image025.gif would point in the opposite direction as File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image004.gif but have the same length.

 

Another way to think about scaling a vector is to maintain its direction and multiply its length by a constant, so that File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image021.gifwould point in the same direction but will be 3 times as long.

Scaling a Vector Geometrically

To geometrically scale a vector by a constant, scale the length of the vector by the constant.

 

Scaling a vector by a negative constant will reverse the direction of the vector.

 

 

Example 3

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image029.gifGiven the vector shown, draw File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image021.gif, File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image025.gif, and File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image031.gif.

 

 

The vector File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image021.gif will be three times as long.  The vector File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image025.gif will have the same length but point in the opposite direction.  The vector File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image031.gif will point in the opposite direction and be twice as long.

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image036.gif

 

 

 

 

 

 

 

By combining scaling and addition, we can find the difference between vectors geometrically as well, since File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image038.gif.

 

 

Example 4

Given the vectors shown, draw File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image040.gif

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image041.gif

 

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image044.gif

 

 

 

From the end of File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image004.gif we draw File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image046.gif, then draw in the result.

 

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image049.gif

Notice that the sum and difference of two vectors are the two diagonals of a parallelogram with the vectors File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image004.gif and File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image013.gif as edges.

 

 

 

 

Try it Now

  1. Using vector File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image013.giffrom Try it Now #1, draw File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image052.gif.

Component Form of Vectors

While the geometric interpretation of vectors gives us an intuitive understanding of vectors, it does not provide us a convenient way to do calculations.  For that, we need a handy way to represent vectors.  Since a vector involves a length and direction, it would be logical to want to represent a vector using a length and an angle θ, usually measured from standard position. 

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image053.gif

 

Magnitude and Direction of a Vector

A vector File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image004.gif can be described by its magnitude, or length, File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image055.gif, and an angle θ.

A vector with length 1 is called unit vector.

 

 

While this is very reasonable, and a common way to describe vectors, it is often more convenient for calculations to represent a vector by horizontal and vertical components.

 

 

Component Form of a Vector

The component form of a vector represents the vector using two components.  File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image057.gif indicates the vector represents a displacement of x units horizontally and y units vertically. 

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image058.gif

 

Notice how we can see the magnitude of the vector as the length of the hypotenuse of a right triangle, or in polar form as the radius, r.

Alternate Notation for Vector Components

Sometimes you may see vectors written as the combination of unit vectors File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image060.gif and File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image062.gif, where  File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image060.gif points the right and File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image062.gif points up.  In other words, File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image066.gif and File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image068.gif.

 

In this notation, the vector File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image070.gif would be written as File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image072.gif since both indicate a displacement of 3 units to the right, and 4 units down.

 

 

While it can be convenient to think of the vector File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image057.gif as an arrow from the origin to the point (x, y), be sure to remember that most vectors can be situated anywhere in the plane, and simply indicate a displacement (change in position) rather than a position.

It is common to need to convert from a magnitude and angle to the component form of the vector and vice versa.  Happily, this process is identical to converting from polar coordinates to Cartesian coordinates, or from the polar form of complex numbers to the a+bi form.

 

Example 5

Find the component form of a vector with length 7 at an angle of 135 degrees.

 

Using the conversion formulas File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image075.gif and File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image077.gif, we can find the components

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image079.gif

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image081.gif

 

This vector can be written in component form as File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image083.gif.

 

 

Example 6

Find the magnitude and angle File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image085.gif representing the vector File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image087.gif.

 

First we can find the magnitude by remembering the relationship between x, y and r:

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image089.gif

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image091.gif

 

Second we can find the angle.  Using the tangent,

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image093.gif

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image095.gif, or written as a coterminal positive angle, 326.31°, because we know our point lies in the 4th quadrant.

 

 

 

Try it Now

  1. Using vector File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image013.giffrom Try it Now #1, the vector that travels from the origin to the point (3, 5), find the components, magnitude and angle File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image085.gif that represent this vector.

 

 

In addition to representing distance movements, vectors are commonly used in physics and engineering to represent any quantity that has both direction and magnitude, including velocities and forces.

 

 

Example 7

An object is launched with initial velocity 200 meters per second at an angle of 30 degrees.  Find the initial horizontal and vertical velocities.

 

By viewing the initial velocity as a vector, we can resolve the vector into horizontal and vertical components.   

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image096.gifFile:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image098.gif m/sec

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image100.gif m/sec

 

This tells us that, absent wind resistance, the object will travel horizontally at about 173 meters each second.  Gravity will cause the vertical velocity to change over time – we’ll leave a discussion of that to physics or calculus classes.

 

 

Adding and Scaling Vectors in Component Form

To add vectors in component form, we can simply add the corresponding components.  To scale a vector by a constant, we scale each component by that constant.

 

 

Combining Vectors in Component Form

To add, subtract, or scale vectors in component form

If File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image102.gif, File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image104.gif, and c is any constant, then

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image106.gif

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image108.gif

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image110.gif

 

 

Example 8

Given File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image087.gif and File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image113.gif, find a new vector File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image115.gif

Using the vectors given,

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image115.gif

    File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image118.gif                      Scale each vector

    File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image120.gif                         Subtract corresponding components

    File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image122.gif

 

By representing vectors in component form, we can find the resulting displacement vector after a multitude of movements without needing to draw a lot of complicated non-right triangles.  For a simple example, we revisit the problem from the opening of the section.  The general procedure we will follow is:

  1. Convert vectors to component form
  2. Add the components of the vectors
  3. Convert back to length and direction if needed to suit the context of the question

 

 

Example 9

A woman leaves home, walks 3 miles north, then 2 miles southeast.  How far is she from home, and what direction would she need to walk to return home?  How far has she walked by the time she gets home?

 

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image123.gifLet’s begin by understanding the question in a little more depth.  When we use vectors to describe a traveling direction, we often position things so north points in the upward direction, east points to the right, and so on, as pictured here.

 

Consequently, travelling NW, SW, NE or SE, means we are travelling through the quadrant bordered by the given directions at a 45 degree angle.

 

With this in mind, we begin by converting each vector to components. 

A walk 3 miles north would, in components, be File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image125.gif

A walk of 2 miles southeast would be at an angle of 45° South of East, or measuring from standard position the angle would be 315°. 

 

Converting to components, we choose to use the standard position angle so that we do not have to worry about whether the signs are negative or positive; they will work out automatically.

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image127.gif

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image128.gif

Adding these vectors gives the sum of the movements in component form

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image130.gif

 

To find how far she is from home and the direction she would need to walk to return home, we could find the magnitude and angle of this vector.

 

Length = File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image132.gif

 

 

To find the angle, we can use the tangent

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image134.gif

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image136.gif north of east

 

Of course, this is the angle from her starting point to her ending point.  To return home, she would need to head the opposite direction, which we could either describe as 180°+48.273° = 228.273° measured in standard position, or as 48.273° south of west (or 41.727° west of south). 

 

She has walked a total distance of 3 + 2 + 2.125 = 7.125 miles.

 

Keep in mind that total distance travelled is not the same as the length of the resulting displacement vector or the “return” vector.

 

 

Try it Now

  1. In a scavenger hunt, directions are given to find a buried treasure.  From a starting point at a flag pole you must walk 30 feet east, turn 30 degrees to the north and travel 50 feet, and then turn due south and travel 75 feet.  Sketch a picture of these vectors, find their components, and calculate how far and in what direction you must travel to go directly to the treasure from the flag pole without following the map.

 

 

While using vectors is not much faster than using law of cosines with only two movements, when combining three or more movements, forces, or other vector quantities, using vectors quickly becomes much more efficient than trying to use triangles.

 

 

Example 10

Three forces are acting on an object as shown below, each measured in Newtons (N).  What force must be exerted to keep the object in equilibrium (where the sum of the forces is zero)?

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image137.gif

 

We start by resolving each vector into components.

 

The first vector with magnitude 6 Newtons at an angle of 30 degrees will have components

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image139.gif

 

The second vector is only in the horizontal direction, so can be written as File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image141.gif.

 

The third vector with magnitude 4 Newtons at an angle of 300 degrees will have components

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image143.gif

 

To keep the object in equilibrium, we need to find a force vector File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image145.gif so the sum of the four vectors is the zero vector, File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image147.gif

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image149.gif       Add component-wise

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image151.gif               Simplify

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image153.gif                          Solve

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image155.gif

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image157.gif

 

This vector gives in components the force that would need to be applied to keep the object in equilibrium.  If desired, we could find the magnitude of this force and direction it would need to be applied in.

Magnitude = File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image159.gifN

Angle:

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image161.gif

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image163.gif

This is in the wrong quadrant, so we adjust by finding the next angle with the same tangent value by adding a full period of tangent:

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image165.gif

 

To keep the object in equilibrium, a force of 0.504 Newtons would need to be applied at an angle of 112.911°.

 

 

 

Important Topics of This Section

Vectors, magnitude (length) & direction

Addition of vectors

Scaling of vectors

Components of vectors

Vectors as velocity

Vectors as forces

Adding & Scaling vectors in component form

Total distance travelled vs. total displacement

 

 

Try it Now Answers

  1.  

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image167.gif

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image168.gif

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image013.gif

File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image169.gif File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image171.jpg    2. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image172.jpg
  1. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image174.gif

 

 
  File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image175.gif
 
  1.  

 

 

 

 

 

 

 

 


File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image177.gif

Magnitude = 88.73 feet at an angle of 34.3° south of east.


Section 8.4 Exercises

 

Write the vector shown in component form.

1. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image179.jpg                2. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image181.jpg

 

Given the vectors shown, sketch File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image183.gif, File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image185.gif, and File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image187.gif.

3. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image189.jpg                4. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image191.jpg

 

Write each vector below as a combination of the vectors File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image004.gif and File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image013.gif from question #3.

5. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image195.jpg                6. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image197.jpg

 

From the given magnitude and direction in standard position, write the vector in component form.

7. Magnitude: 6, Direction: 45°                      8. Magnitude: 10, Direction: 120°                 

9. Magnitude: 8, Direction: 220°                    10. Magnitude: 7, Direction: 305°

 

Find the magnitude and direction of the vector.

11. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image199.gif                     12. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image201.gif                  13. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image203.gif                     14. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image205.gif                    

15. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image207.gif                  16. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image209.gif               17. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image211.gif                  18. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image213.gif     

19. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image215.gif               20. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image217.gif

 

Using the vectors given, compute File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image183.gif, File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image185.gif, and File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image221.gif.

21. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image223.gif                                22. File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image225.gif

  1. A woman leaves home and walks 3 miles west, then 2 miles southwest.  How far from home is she, and in what direction must she walk to head directly home?

 

  1. A boat leaves the marina and sails 6 miles north, then 2 miles northeast.  How far from the marina is the boat, and in what direction must it sail to head directly back to the marina?

 

  1. A person starts walking from home and walks 4 miles east, 2 miles southeast, 5 miles south, 4 miles southwest, and 2 miles east.  How far have they walked?  If they walked straight home, how far would they have to walk?

 

  1. A person starts walking from home and walks 4 miles east, 7 miles southeast, 6 miles south, 5 miles southwest, and 3 miles east.  How far have they walked?  If they walked straight home, how far would they have to walk?

 

  1. Three forces act on an object: File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image227.gif.  Find the net force acting on the object.

 

  1. Three forces act on an object: File:/C:\Users\DELMAR~1\AppData\Local\Temp\msohtmlclip1\01\clip_image229.gif.  Find the net force acting on the object.

 

  1. A person starts walking from home and walks 3 miles at 20° north of west, then 5 miles at 10° west of south, then 4 miles at 15° north of east.  If they walked straight home, how far would they have to walk, and in what direction?

 

  1. A person starts walking from home and walks 6 miles at 40° north of east, then 2 miles at 15° east of south, then 5 miles at 30° south of west.  If they walked straight home, how far would they have to walk, and in what direction?

 

  1. An airplane is heading north at an airspeed of 600 km/hr, but there is a wind blowing from the southwest at 80 km/hr.  How many degrees off course will the plane end up flying, and what is the plane’s speed relative to the ground?

 

  1. An airplane is heading north at an airspeed of 500 km/hr, but there is a wind blowing from the northwest at 50 km/hr.  How many degrees off course will the plane end up flying, and what is the plane’s speed relative to the ground?

 

  1. An airplane needs to head due north, but there is a wind blowing from the southwest at 60 km/hr.  The plane flies with an airspeed of 550 km/hr.  To end up flying due north, the pilot will need to fly the plane how many degrees west of north?

 

  1. An airplane needs to head due north, but there is a wind blowing from the northwest at 80 km/hr.  The plane flies with an airspeed of 500 km/hr.  To end up flying due north, the pilot will need to fly the plane how many degrees west of north?

 

  1. As part of a video game, the point (5, 7) is rotated counterclockwise about the origin through an angle of 35 degrees.  Find the new coordinates of this point.

 

  1. As part of a video game, the point (7, 3) is rotated counterclockwise about the origin through an angle of 40 degrees.  Find the new coordinates of this point.

 

  1. Two children are throwing a ball back and forth straight across the back seat of a car. The ball is being thrown 10 mph relative to the car, and the car is travelling 25 mph down the road.  If one child doesn't catch the ball and it flies out the window, in what direction does the ball fly (ignoring wind resistance)?

 

  1. Two children are throwing a ball back and forth straight across the back seat of a car. The ball is being thrown 8 mph relative to the car, and the car is travelling 45 mph down the road.  If one child doesn't catch the ball and it flies out the window, in what direction does the ball fly (ignoring wind resistance)?

 

 

Contributors

  • David Lippman (Pierce College)
  • Melonie Rasmussen (Pierce College)