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Mathematics LibreTexts

6.3 Ranges

Definition 6.3.1.  Let \(T:V\to W \) be a linear map. The range of \(T \), denoted by \(\range(T) \), is the subset of vectors in \(W \) that are in the image of \(T \). I.e.,

\[  \range(T) = \{ Tv \mid v\in V\} = \{ w\in W \mid \rm{~ there~ exists~} v \in V \rm{~ such~ that~} Tv=w\}.\]

Example 6.3.2.  The range of the differentiation map \(T:\mathbb{F}[z] \to \mathbb{F}[z] \) is \(\range(T) =\mathbb{F}[z]\) since, for every polynomial \(q\in \mathbb{F}[z] \), there is a \(p\in \mathbb{F}[z] \) such that \(p'=q \).

Example 6.3.3.  The range of the linear map \(T(x,y)=(x-2y,3x+y) \) is \(\mathbb{R}^2 \) since, for any \((z_1,z_2)\in \mathbb{R}^2 \), we have \(T(x,y)=(z_1,z_2) \) if \((x,y)=\frac{1}{7}(z_1+2z_2,-3z_1+z_2) \).

Proposition 6.3.4. Let \(T:V\to W \) be a linear map. Then \(\range(T) \) is a subspace of \(W \).


We need to show that \(0\in \range(T) \) and that \(\range(T) \) is closed under addition and scalar multiplication. We already showed that \(T0=0 \) so that \(0\in \range(T) \).

     For closure under addition, let \(w_1,w_2\in \range(T) \). Then there exist \(v_1,v_2\in V\) such that \(Tv_1=w_1 \) and \(Tv_2=w_2 \). Hence
    T(v_1+v_2) = Tv_1 + Tv_2 = w_1 + w_2,
and so \(w_1+w_2\in \range(T) \).

       For closure under scalar multiplication, let \(w\in \range(T) \) and \(a\in \mathbb{F} \). Then there exists a \(v\in V \) such that \(Tv=w \). Thus
and so \(aw \in \range(T) \).

Definition 6.3.5.  A linear map \(T:V\to W \) is called surjective if \(\range(T)=W \). A linear map \(T:V\to W \) is called bijective if \(T \) is both injective and surjective.

Example 6.3.6.  

  1. The differentiation map \(T:\mathbb{F}[z] \to \mathbb{F}[z] \) is surjective since \(\range(T) = \mathbb{F}[z] \). However, if we restrict ourselves to polynomials of degree at most \(m \), then the differentiation map \(T:\mathbb{F}_m[z] \to \mathbb{F}_m[z] \) is not surjective since polynomials of degree \(m \) are not in thecrange of \(T \).
  2. The identity map \(I:V\to V \) is surjective.
  3. The linear map \(T:\mathbb{F}[z] \to \mathbb{F}[z] \) given by \(T(p(z)) = z^2 p(z) \) is not surjective since, for example, there are no linear polynomials in the range of \(T \).
  4. The linear map \(T(x,y)=(x-2y,3x+y) \) is surjective since \(\range(T)=\mathbb{R}^{2} \), as we calculated in Example 6.3.3.



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