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5.3: Decimal Operations (Part 1)

  • Page ID
    4999
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    Learning Objectives
    • Add and subtract decimals
    • Multiply decimals
    • Divide decimals
    • Use decimals in money applications
    be prepared!

    Before you get started, take this readiness quiz.

    1. Simplify \(\dfrac{70}{100}\). If you missed this problem, review Example 4.3.1.
    2. Multiply \(\dfrac{3}{10} \cdot \dfrac{9}{10}\). If you missed this problem, review Example 4.3.7.
    3. Divide −36 ÷ (−9). If you missed this problem, review Example 3.7.3.

    Add and Subtract Decimals

    Let’s take one more look at the lunch order from the start of Decimals, this time noticing how the numbers were added together.

    \[\begin{split} & $3.45 \quad Sandwich \\ & $1.25 \quad Water \\ + & $0.33 \quad Tax \\ \hline & $5.03 \quad Total \end{split}\]

    All three items (sandwich, water, tax) were priced in dollars and cents, so we lined up the dollars under the dollars and the cents under the cents, with the decimal points lined up between them. Then we just added each column, as if we were adding whole numbers. By lining up decimals this way, we can add or subtract the corresponding place values just as we did with whole numbers.

    HOW TO: ADD OR SUBTRACT DECIMALS

    Step 1. Write the numbers vertically so the decimal points line up.

    Step 2. Use zeros as place holders, as needed.

    Step 3. Add or subtract the numbers as if they were whole numbers. Then place the decimal in the answer under the decimal points in the given numbers.

    Example \(\PageIndex{1}\):

    Add: 3.7 + 12.4.

    Solution

    Write the numbers vertically so the decimal points line up. $$\begin{split} 3.&7 \\ + 12.&4 \\ \hline \end{split}$$
    Place holders are not needed since both numbers have the same number of decimal places.  
    Add the numbers as if they were whole numbers. Then place the decimal in the answer under the decimal points in the given numbers. $$\begin{split} \stackrel{1}{3}.&7 \\ + 12.&4 \\ \hline 16.&1 \end{split}$$
    Exercise \(\PageIndex{1}\):

    Add: 5.7 + 11.9.

    Answer

    \(17.6\)

    Exercise \(\PageIndex{2}\):

    Add: 18.32 + 14.79.

    Answer

    \(13.11\)

    Example \(\PageIndex{2}\):

    Add: 23.5 + 41.38.

    Solution

    Write the numbers vertically so the decimal points line up. $$\begin{split} 23.&5 \\ + 41.&38 \\ \hline \end{split}$$
    Place 0 as a place holder after the 5 in 23.5, so that both numbers have two decimal places. $$\begin{split} 23.&5 \textcolor{red}{0} \\ + 41.&38 \\ \hline \end{split}$$
    Add the numbers as if they were whole numbers. Then place the decimal in the answer under the decimal points in the given numbers. $$\begin{split} 23.&50 \\ + 41.&38 \\ \hline 64.&88 \end{split}$$
    Exercise \(\PageIndex{3}\):

    Add: 4.8 + 11.69.

    Answer

    \(16.49\)

    Exercise \(\PageIndex{4}\):

    Add: 5.123 + 18.47.

    Answer

    \(23.593\)

    How much change would you get if you handed the cashier a $20 bill for a $14.65 purchase? We will show the steps to calculate this in the next example.

    Example \(\PageIndex{3}\):

    Subtract: 20 − 14.65.

    Solution

    Write the numbers vertically so the decimal points line up. Remember 20 is a whole number, so place the decimal point after the 0. $$\begin{split} 20.& \\ - 14.&65 \\ \hline \end{split}$$
    Place two zeros after the decimal point in 20, as place holders so that both numbers have two decimal places.

    \[\begin{split} 20.& \textcolor{red}{00} \\ - 14.&65 \\ \hline \end{split}\]

    Subtract the numbers as if they were whole numbers. Then place the decimal in the answer under the decimal points in the given numbers. $$\begin{split} \stackrel{1}{\cancel{2}} \stackrel{\stackrel{9}{\cancel{10}}}{\cancel{0}} &.\stackrel{\stackrel{9}{\cancel{10}}}{\cancel{0}} \stackrel{\stackrel{9}{\cancel{10}}}{\cancel{0}} \\ - 1\; \; 4\; \; &.\; 6\; \; 5 \\ \hline 5\; \; &.\; 3\; \; 5\end{split}$$
    Exercise \(\PageIndex{5}\):

    Subtract: 10 − 9.58.

    Answer

    \(0.42\)

    Exercise \(\PageIndex{6}\):

    Subtract: 50 − 37.42.

    Answer

    \(12.58\)

    Example \(\PageIndex{4}\):

    Subtract: 2.51 − 7.4.

    Solution

    If we subtract 7.4 from 2.51, the answer will be negative since 7.4 > 2.51. To subtract easily, we can subtract 2.51 from 7.4. Then we will place the negative sign in the result.

    Write the numbers vertically so the decimal points line up. $$\begin{split} 7.&4 \\ - 2.&51 \\ \hline \end{split}$$
    Place zero after the 4 in 7.4 as a place holder, so that both numbers have two decimal places. $$\begin{split} 7.&4 \textcolor{red}{0} \\ - 2.&51 \\ \hline \end{split}$$
    Subtract and place the decimal in the answer. $$\begin{split} 7.&40 \\ - 2.&51 \\ \hline 4.&89 \end{split}$$
    Remember that we are really subtracting 2.51 − 7.4 so the answer is negative. 2.51 − 7.4 = − 4.89
    Exercise \(\PageIndex{7}\):

    Subtract: 4.77 − 6.3.

    Answer

    \(-1.53\)

    Exercise \(\PageIndex{8}\):

    Subtract: 8.12 − 11.7.

    Answer

    \(-3.58\)

    Multiply Decimals

    Multiplying decimals is very much like multiplying whole numbers—we just have to determine where to place the decimal point. The procedure for multiplying decimals will make sense if we first review multiplying fractions.

    Do you remember how to multiply fractions? To multiply fractions, you multiply the numerators and then multiply the denominators. So let’s see what we would get as the product of decimals by converting them to fractions first. We will do two examples side-by-side in Table 5.22. Look for a pattern.

    Table \(\PageIndex{1}\)
    A B
      (0.3)(0.7) (0.2)(0.46)
    Convert to fractions. $$\left(\dfrac{3}{10}\right) \left(\dfrac{7}{10}\right)$$ $$\left(\dfrac{2}{10}\right) \left(\dfrac{46}{100}\right)$$
    Multiply. $$\dfrac{21}{100}$$ $$\dfrac{92}{1000}$$
    Convert back to decimals 0.21 0.092

    There is a pattern that we can use. In A, we multiplied two numbers that each had one decimal place, and the product had two decimal places. In B, we multiplied a number with one decimal place by a number with two decimal places, and the product had three decimal places.

    How many decimal places would you expect for the product of (0.01)(0.004)? If you said “five”, you recognized the pattern. When we multiply two numbers with decimals, we count all the decimal places in the factors—in this case two plus three—to get the number of decimal places in the product—in this case five.

    The top line says 0.01 times 0.004 equals 0.00004. Below the 0.01, it says 2 places. Below the 0.004, it says 3 places. Below the 0.00004, it says 5 places. The bottom line says 1 over 100 times 4 over 1000 equals 4 over 100,000.

    Once we know how to determine the number of digits after the decimal point, we can multiply decimal numbers without converting them to fractions first. The number of decimal places in the product is the sum of the number of decimal places in the factors.

    The rules for multiplying positive and negative numbers apply to decimals, too, of course.

    Definition: Multiplying Two Numbers

    When multiplying two numbers,

    • if their signs are the same, the product is positive.
    • if their signs are different, the product is negative.

    When you multiply signed decimals, first determine the sign of the product and then multiply as if the numbers were both positive. Finally, write the product with the appropriate sign.

    HOW TO: MULTIPLY DECIMAL NUMBERS

    Step 1. Determine the sign of the product.

    Step 2. Write the numbers in vertical format, lining up the numbers on the right.

    Step 3. Multiply the numbers as if they were whole numbers, temporarily ignoring the decimal points.

    Step 4. Place the decimal point. The number of decimal places in the product is the sum of the number of decimal places in the factors. If needed, use zeros as placeholders.

    Step 5. Write the product with the appropriate sign.

    Example \(\PageIndex{5}\):

    Multiply: (3.9)(4.075).

    Solution

    Determine the sign of the product. The signs are the same. The product will be positive.
    Write the numbers in vertical format, lining up the numbers on the right. $$\begin{split} 4.07&5 \\ \times 3.&9 \\ \hline \end{split}$$
    Multiply the numbers as if they were whole numbers, temporarily ignoring the decimal points. $$\begin{split} 4.07&5 \\ \times 3.&9 \\ \hline 3667&5 \\ 12225&\; \\ \hline 15892&5 \end{split}$$
    Place the decimal point. Add the number of decimal places in the factors (1 + 3). Place the decimal point 4 places from the right. $$\begin{split} 4.07&5 \quad \textcolor{blue}{3\; places} \\ \times 3.&9 \quad \textcolor{blue}{1\; place}\\ \hline 3667&5 \\ 12225&\; \\ \hline 15892&5 \quad \textcolor{blue}{4\; places} \end{split}$$
    The product is positive. (3.9)(4.075) = 15.8925
    Exercise \(\PageIndex{9}\):

    Multiply: 4.5(6.107).

    Answer

    \(27.4815\)

    Exercise \(\PageIndex{10}\):

    Multiply: 10.79(8.12).

    Answer

    \(87.6148\)

    Example \(\PageIndex{6}\):

    Multiply: (−8.2)(5.19).

    Solution

    The signs are different. The product will be negative.
    Write in vertical format, lining up the numbers on the right. $$\begin{split} 5.&19 \\ \times 8.&2 \\ \hline \end{split}$$
    Multiply. $$\begin{split} 5.&19 \\ \times 8.&2 \\ \hline 10&38 \\ 415&2\; \\ \hline 425&58 \end{split}$$
    CNX_BMath_Figure_05_02_020_img-01.png $$\begin{split} 5.&19 \\ \times 8.&2 \\ \hline 10&38 \\ 415&2\; \\ \hline 42.5&58 \end{split}$$
    The product is negative. (−8.2)(5.19) = −42.558
    Exercise \(\PageIndex{11}\):

    Multiply: (4.63)(−2.9).

    Answer

    \(-13.427\)

    Exercise \(\PageIndex{12}\):

    Multiply: (−7.78)(4.9).

    Answer

    \(-38.122\)

    In the next example, we’ll need to add several placeholder zeros to properly place the decimal point.

    Example \(\PageIndex{7}\):

    Multiply: (0.03)(0.045).

    Solution

    The product is positive. (0.03)(0.045)
    Write in vertical format, lining up the numbers on the right. $$\begin{split} 0.04&5 \\ \times 0.0&3 \\ \hline \end{split}$$
    Multiply. $$\begin{split} 0.04&5 \\ \times 0.0&3 \\ \hline 13&5 \end{split}$$

    CNX_BMath_Figure_05_02_021_img-01.png

    Add zeros as needed to get the 5 places.

    CNX_BMath_Figure_05_02_021_img-04.png
    The product is positive. (0.03)(0.045) = 0.00135
    Exercise \(\PageIndex{13}\):

    Multiply: (0.04)(0.087).

    Answer

    \(0.00348\)

    Exercise \(\PageIndex{14}\):

    Multiply: (0.09)(0.067).

    Answer

    \(0.00603\)

    Multiply by Powers of 10

    In many fields, especially in the sciences, it is common to multiply decimals by powers of 10. Let’s see what happens when we multiply 1.9436 by some powers of 10.

    The top row says 1.9436 times 10, then 1.9436 times 100, then 1.9436 times 1000. Below each is a vertical multiplication problem. These show that 1.9436 times 10 is 19.4360, 1.9436 times 100 is 194.3600, and 1.9436 times 1000 is 1943.6000.

    Look at the results without the final zeros. Do you notice a pattern?

    \[\begin{split} 1.9436(10) & = 19.436 \\ 1.9436(100) & = 194.36 \\ 1.9436(1000) & = 1943.6 \end{split}\]

    The number of places that the decimal point moved is the same as the number of zeros in the power of ten. Table 5.26 summarizes the results.

    Table \(\PageIndex{2}\)
    Multiply by Number of zeros Number of places decimal point moves
    10 1 1 place to the right
    100 2 2 places to the right
    1,000 3 3 places to the right
    10,000 4 4 places to the right

    We can use this pattern as a shortcut to multiply by powers of ten instead of multiplying using the vertical format. We can count the zeros in the power of 10 and then move the decimal point that same of places to the right. So, for example, to multiply 45.86 by 100, move the decimal point 2 places to the right.

    45.86 times 100 is shown to equal 4586. There is an arrow from the decimal going over 2 places from after the 5 to after the 6.

    Sometimes when we need to move the decimal point, there are not enough decimal places. In that case, we use zeros as placeholders. For example, let’s multiply 2.4 by 100. We need to move the decimal point 2 places to the right. Since there is only one digit to the right of the decimal point, we must write a 0 in the hundredths place.

    2.4 times 100 is shown to equal 240. There is an arrow from the decimal going over 2 places from after the 2 to after the 0.

    HOW TO: MULTIPLY A DECIMAL BY A POWER OF 10

    Step 1. Move the decimal point to the right the same number of places as the number of zeros in the power of 10.

    Step 2. Write zeros at the end of the number as placeholders if needed.

    Example \(\PageIndex{8}\):

    Multiply 5.63 by factors of (a) 10 (b) 100 (c) 1000.

    Solution

    By looking at the number of zeros in the multiple of ten, we see the number of places we need to move the decimal to the right.

    (a) 5.63(10)

    There is 1 zero in 10, so move the decimal point 1 place to the right. CNX_BMath_Figure_05_02_023a_img-01.png
      56.3

    (b) 5.63(100)

    There are 2 zeros in 100, so move the decimal point 2 places to the right. CNX_BMath_Figure_05_02_023b_img-01.png
      563

    (c) 5.63(1000)

    There are 3 zeros in 1000, so move the decimal point 3 places to the right. CNX_BMath_Figure_05_02_023c_img-01.png
    A zero must be added at the end. 5,630
    Exercise \(\PageIndex{15}\):

    Multiply 2.58 by factors of (a) 10 (b) 100 (c) 1000.

    Answer a

    \(25.8\)

    Answer b

    \(258\)

    Answer c

    \(2,580\)

    Exercise \(\PageIndex{16}\):

    Multiply 14.2 by factors of (a) 10 (b) 100 (c) 1000.

    Answer a

    \(142\)

    Answer b

    \(1,420\)

    Answer c

    \(14,200\)

    Contributors and Attributions


    This page titled 5.3: Decimal Operations (Part 1) is shared under a CC BY 4.0 license and was authored, remixed, and/or curated by OpenStax.

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