
# 1.5: Surface Area of Revolution

### Surface Area of Revolution

The area of a frustum is

$A = 2\pi r(length).$

If we revolve a curve around the x-axis, we have that the surface area of revolution is given by

$\text{Area} = 2\pi \int _a^b y \sqrt{1+\left( \dfrac{dy}{dx} \right)^2} dx.$

Example 1

Set up an integral that gives the surface area of revolution about the x axis of the curve

$y = x^2$

from 2 to 3.

Solution

We find

$\left(\dfrac{dy}{dx} \right)^2=(2x)^2 = 4x^2.$

Now use the area formula:

$A = 2\pi\int_2^3 x^2\sqrt{1+4x^2} dx.$

We will learn later how to work out this integral.  However a computer gives that

$A \approx 208.09.$

### Contributors

• Integrated by Justin Marshall.