9.3.1: Solution of Initial Value Problems (Exercises)
- Page ID
- 103544
\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)
\( \newcommand{\dsum}{\displaystyle\sum\limits} \)
\( \newcommand{\dint}{\displaystyle\int\limits} \)
\( \newcommand{\dlim}{\displaystyle\lim\limits} \)
\( \newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\)
( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\)
\( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)
\( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\)
\( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)
\( \newcommand{\Span}{\mathrm{span}}\)
\( \newcommand{\id}{\mathrm{id}}\)
\( \newcommand{\Span}{\mathrm{span}}\)
\( \newcommand{\kernel}{\mathrm{null}\,}\)
\( \newcommand{\range}{\mathrm{range}\,}\)
\( \newcommand{\RealPart}{\mathrm{Re}}\)
\( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)
\( \newcommand{\Argument}{\mathrm{Arg}}\)
\( \newcommand{\norm}[1]{\| #1 \|}\)
\( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)
\( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\AA}{\unicode[.8,0]{x212B}}\)
\( \newcommand{\vectorA}[1]{\vec{#1}} % arrow\)
\( \newcommand{\vectorAt}[1]{\vec{\text{#1}}} % arrow\)
\( \newcommand{\vectorB}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\( \newcommand{\vectorC}[1]{\textbf{#1}} \)
\( \newcommand{\vectorD}[1]{\overrightarrow{#1}} \)
\( \newcommand{\vectorDt}[1]{\overrightarrow{\text{#1}}} \)
\( \newcommand{\vectE}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{\mathbf {#1}}}} \)
\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\(\newcommand{\longvect}{\overrightarrow}\)
\( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)
\(\newcommand{\ket}[1]{\left| #1 \right>}\)
\(\newcommand{\bra}[1]{\left< #1 \right|}\)
\(\newcommand{\braket}[2]{\left< #1 \vphantom{#2} \right| \left. #2 \vphantom{#1} \right>}\)
\(\newcommand{\braopket}[3]{\left< #1 \vphantom{#2}\vphantom{#3} \right| #2 \vphantom{#1}\vphantom{#3} \left| #3 \vphantom{#1}\vphantom{#2} \right>}\)
\(\newcommand{\qmvec}[1]{\mathbf{\vec{#1}}}\)
\(\newcommand{\op}[1]{\hat{\mathbf{#1}}}\)
\(\newcommand{\expect}[1]{\langle #1 \rangle}\)
\(\newcommand{\dfn}[1]{\emph{\textbf{#1}}}\)
In Exercises 1-35 use the Laplace transform to solve the initial value problem.
1. \(y'-y=1, \quad y(0)=0\)
2. \(2y'+y=0, \quad y(0)=-3\)
3. \(y'+6y=e^{4t}, \quad y(0)=2\)
4. \(y'-y=2\cos 5t, \quad y(0)=0\)
5. \(y''+5y'+4y=0, \quad y(0)=1,\quad y'(0)=0\)
6. \(y''-4y'=6e^{3t}-3e^{-t}, \quad y(0)=1,\quad y'(0)=-1\)
7. \(y''+y=\sqrt2\sin\sqrt2 t, \quad y(0)=10,\quad y'(0)=0\)
8. \(y''+9y=e^t, \quad y(0)=0,\quad y'(0)=0\)
9. \(2y'''+3y''-3y'-2y=e^{-t}, \quad y(0)=0,\quad y'(0)=0, \quad y''(0)=1\)
10. \(y'''+2y''-y'-2y=\sin 3t, \quad y(0)=0,\quad y'(0)=0, \quad y''(0)=1\)
11. \(y''+3y'+2y=e^t, \quad y(0)=1,\quad y'(0)=-6\)
12. \(y''-y'-6y=2, \quad y(0)=1,\quad y'(0)=0\)
13. \(y''+y'-2y=2e^{3t}, \quad y(0)=-1,\quad y'(0)=4\)
14. \(y''-4y=2 e^{3t}, \quad y(0)=1,\quad y'(0)=-1\)
15. \(y''+y'-2y=e^{3t}, \quad y(0)=1,\quad y'(0)=-1\)
16. \(y''+3y'+2y=6e^t, \quad y(0)=1,\quad y'(0)=-1\)
17. \(y''+y=\sin2t, \quad y(0)=0,\quad y'(0)=1\)
18. \(y''-3y'+2y=2e^{3t}, \quad y(0)=1,\quad y'(0)=-1\)
19. \(y''-3y'+2y=e^{4t}, \quad y(0)=1,\quad y'(0)=-2\)
20. \(y''-3y'+2y=e^{3t}, \quad y(0)=-1,\quad y'(0)=-4\)
21. \(y''+3y'+2y=2e^t, \quad y(0)=0,\quad y'(0)=-1\)
22. \(y''+y'-2y=-4, \quad y(0)=2,\quad y'(0)=3\)
23. \(y''+4y=4, \quad y(0)=0,\quad y'(0)=1\)
24. \(y''-y'-6y=2, \quad y(0)=1,\quad y'(0)=0\)
25. \(y''+3y'+2y=e^t, \quad y(0)=0,\quad y'(0)=1\)
26. \(y''-y=1, \quad y(0)=1,\quad y'(0)=0\)
27. \(y''+4y=3\sin t, \quad y(0)=1,\quad y'(0)=-1\)
28. \(y''+y'=2e^{3t}, \quad y(0)=-1,\quad y'(0)=4\)
29. \(y''+y=1, \quad y(0)=2,\quad y'(0)=0\)
30. \(y''+y=t, \quad y(0)=0,\quad y'(0)=2\)
31. \(y''+y=t-3\sin2t, \quad y(0)=1,\quad y'(0)=-3\)
32. \(y''+5y'+6y=2e^{-t}, \quad y(0)=1,\quad y'(0)=3\)
33. \(y''-2y'-3y=10\cos t, \quad y(0)=2,\quad y'(0)=7\)
34. \(2y''-3y'-2y=4e^t, \quad y(0)=1,\; y'(0)=-2\)
35. \(6y''-y'-y=3e^{2t}, \quad y(0)=0,\; y'(0)=0\)


