1.1E: Exercises
- Page ID
- 104795
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\(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)Practice Makes Perfect
Add and Subtract IntegersIn the following exercises, simplify each expression.
Compute the following
- \(1+4\)
- \(3+9\)
- \(9-6\)
- \(8-3\)
- \(9-14\)
- \(1-8\)
- \(−17−42\)
- \(−58−(−67)\)
- \(64+(−17)−9\)
- \(48+(−16)\)
- \(34+(−19)\)
- \(−14+(−12)+4\)
- \(−17+(−18)+6\)
- \(19+2(−3+8)\)
- \(24+3(−5+9)\)
- \((2−7)−(3−8)\)
- \(32−[5−(15−20)]\)
- Answer
-
- 5
- 12
- 3
- 5
- -5
- -7
- \(-59\)
- \(9\)
- \(38\)
- 32
- 15
- \(-22\)
- \(-29\)
- \(29\)
- \(36\)
- 0
- 22
multiply or divide:
- \(−4 \cdot 8\)
- \(13(−5)\)
- \(−24÷6\)
- \(−52÷(−4)\)
- \(−3 \cdot 9\)
- \(9(−7)\)
- \(35÷(−7)\)
- \(−84÷(−6)\)
- \(−3(−5)(6)\)
- \(−4(−6)(3)\)
- \((8−11)(9−12)\)
- \((6−11)(8−13)\)
- \(26−3(2−7)\)
- \(23−2(4−6)\)
- \(65÷(−5)+(−28)÷(−7)\)
- \(52÷(−4)+(−32)÷(−8)\)
- \(9−2[3−8(−2)]\)
- \(11−3[7−4(−2)]\)
- Answer
-
- \(−32\)
- \(−65\)
- \(−4\)
- \(13\)
- \(−27\)
- \(−63\)
- \(−5\)
- \(14\)
- \(90\)
- \(72\)
- \(9\)
- \(25\)
- \(41\)
- \(27\)
- \(-9\)
- \(-9\)
- \(-29\)
- \(-34\)
For each of the expressions below, identify the appropriate inequality or equality that makes the statement true.
- \(-8\_\_−|8|\)
- \(13\_\_−13\)
- \(−(−1)\_\_|−1|\)
- \(-(−10)\_\_−|-10|\)
- \(-2 \_\_|−2|\)
- \(0 \_\_|0|\)
- \(−9 \_\_|−9|\)
- Answer
-
- =
- >
- =
- >
- <
- =
- <
Simplify the following expressions:
- \(2−|10+2(6−5)|\)
- \(−2|7+5(-3 + 5)|+3(4)\)
- \(4+4|1+8(−5+4)|\)
- \(3|4 - 12| - 2(4 + 7)\)
- \(−|1+3(6−7) + (9 - 2)|\)
- \(−2|3+(6−7) + (9 - 10)|\)
- \(3|1+4(-2 + 1)|-3(5)\)
- \(-|3 - 4| + |4 - 5| - |5 - 6|\)
- \(| 3 - 6| - |6 - 9| + |9 - 12|\)
- \((3 - 4)|4 + 9|\)
- \((7 - 2)|- 11 + 3|\)
- Answer
-
- -10
- -22
- 32
- 2
- -5
- -2
- -6
- -1
- 3
- -13
- 40
- Explain why the sum of −8 and 2 is negative, but the sum of 8 and −2 is positive.
- Give an example from your life experience of adding two negative numbers.
- Answer
-
Answers will vary