Skip to main content
Mathematics LibreTexts

5.5E: Exercises

  • Page ID
    104859

    \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)

    \( \newcommand{\dsum}{\displaystyle\sum\limits} \)

    \( \newcommand{\dint}{\displaystyle\int\limits} \)

    \( \newcommand{\dlim}{\displaystyle\lim\limits} \)

    \( \newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\)

    ( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\)

    \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)

    \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\)

    \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)

    \( \newcommand{\Span}{\mathrm{span}}\)

    \( \newcommand{\id}{\mathrm{id}}\)

    \( \newcommand{\Span}{\mathrm{span}}\)

    \( \newcommand{\kernel}{\mathrm{null}\,}\)

    \( \newcommand{\range}{\mathrm{range}\,}\)

    \( \newcommand{\RealPart}{\mathrm{Re}}\)

    \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)

    \( \newcommand{\Argument}{\mathrm{Arg}}\)

    \( \newcommand{\norm}[1]{\| #1 \|}\)

    \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)

    \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\AA}{\unicode[.8,0]{x212B}}\)

    \( \newcommand{\vectorA}[1]{\vec{#1}}      % arrow\)

    \( \newcommand{\vectorAt}[1]{\vec{\text{#1}}}      % arrow\)

    \( \newcommand{\vectorB}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vectorC}[1]{\textbf{#1}} \)

    \( \newcommand{\vectorD}[1]{\overrightarrow{#1}} \)

    \( \newcommand{\vectorDt}[1]{\overrightarrow{\text{#1}}} \)

    \( \newcommand{\vectE}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{\mathbf {#1}}}} \)

    \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \(\newcommand{\longvect}{\overrightarrow}\)

    \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)

    \(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)

    Practice Makes Perfect

    Add and Subtract with Common Denominator

    In the following exercises, add or subtract.

    1. \(\dfrac{2}{15}+\dfrac{7}{15}\)
    2. \(\dfrac{3c}{4c−5}+\dfrac{5}{4c−5}\)
    3. \(\dfrac{2r^2}{2r−1}+\dfrac{15r−8}{2r−1}\)
    4. \(\dfrac{2w^2}{w^2−16}+\dfrac{8w}{w^2−16}\)
    5. \(\dfrac{9a^2}{3a−7}−\dfrac{49}{3a−7}\)
    6. \(\dfrac{3m^2}{6m−30}−\dfrac{21m−30}{6m−30}\)
    7. \(\dfrac{6p^2+3p+4}{p^2+4p−5}−\dfrac{5p^2+p+7}{p^2+4p−5}\)
    8. \(\dfrac{5r^2+7r−33}{r^2−49}−\dfrac{4r^2+5r+30}{r^2−49}\)
    Answer
    1. \(\dfrac{3}{5}\)
    2. \(\dfrac{3c+5}{4c−5}\)
    3. \(r+8\)
    4. \(\dfrac{2w}{w−4}\)
    5. \(3a+7\)
    6. \(\dfrac{m−2}{2}\)
    7. \(\dfrac{p+3}{p+5}\)
    8. \(\dfrac{r+9}{r+7}\)
    Add and Subtract with Opposite Denominators

    In the following exercises, add or subtract.

    1. \(\dfrac{10v}{2v−1}+\dfrac{2v+4}{1−2v}\)
    2. \(\dfrac{10x^2+16x−7}{8x−3}+\dfrac{2x^2+3x−1}{3−8x}\)
    3. \(\dfrac{z^2+6z}{z^2−25}−\dfrac{3z+20}{25−z^2}\)
    4. \(\dfrac{2b^2+30b−13}{b^2−49}−\dfrac{2b^2−5b−8}{49−b^2}\)
    Answer
    1. \(4\)
    2. \(x+2\)
    3. \(\dfrac{z+4}{z−5}\)
    4. \(\dfrac{4b−3}{b−7}\)
    Add and Subtract with Unlike Denominators.

    In the following exercises, perform the indicated operations.

    1. \(\dfrac{7}{10x^2y}+\dfrac{4}{15xy^2}\)
    2. \(\dfrac{3}{r+4}+\dfrac{2}{r−5}\)
    3. \(\dfrac{5}{3w−2}+\dfrac{2}{w+1}\)
    4. \(\dfrac{2y}{y+3}+\dfrac{3}{y−1}\)
    5. \(\dfrac{5b}{a^2b−2a^2}+\dfrac{2b}{b^2−4}\)
    6. \(\dfrac{−3m}{3m−3}+\dfrac{5m}{m^2+3m−4}\)
    7. \(\dfrac{3r}{r^2+7r+6}+\dfrac{9}{r^2+4r+3}\)
    8. \(\dfrac{t}{t−6}−\dfrac{t−2}{t+6}\)
    9. \(\dfrac{5a}{a+3}−\dfrac{a+2}{a+6}\)
    10. \(\dfrac{6}{m+6}−\dfrac{12m}{m^2−36}\)
    11. \(\dfrac{−9p−17}{p^2−4p−21}−\dfrac{p+1}{7−p}\)
    12. \(\dfrac{−2r−16}{r^2+6r−16}−\dfrac{5}{2−r}\)
    13. \(\dfrac{2x+7}{10x−1}+3\)
    14. \(\dfrac{3}{x^2−3x−4}−\dfrac{2}{x^2−5x+4}\)
    15. \(\dfrac{5}{x^2+8x−9}−\dfrac{4}{x^2+10x+9}\)
    16. \(\dfrac{5a}{a−2}+\dfrac{9}{a}−\dfrac{2a+18}{a^2−2a}\)
    17. \(\dfrac{c}{c+2}+\dfrac{5}{c−2}−\dfrac{10c}{c^2−4}\)
    18. \(\dfrac{3d}{d+2}+\dfrac{4}{d}−\dfrac{d+8}{d^2+2d}\)
    Answer
    1. \(\dfrac{21y+8x}{30x^2y^2}\)
    2. \(\dfrac{5r−7}{(r+4)(r−5)}\)
    3. \(\dfrac{11w+1}{(3w−2)(w+1)}\)
    4. \(\dfrac{2y^2+y+9}{(y+3)(y−1)}\)
    5. \(\dfrac{b(5b+10+2a^2)}{a^2(b−2)(b+2)}\)
    6. \(-\dfrac{m}{m+4}\)
    7. \(\dfrac{3(r^2+6r+18)}{(r+1)(r+6)(r+3)}\)
    8. \(\dfrac{2(7t−6)}{(t−6)(t+6)}\)
    9. \(\dfrac{4a^2+25a−6}{(a+3)(a+6)}\)
    10. \(\dfrac{−6}{m−6}\)
    11. \(\dfrac{p+2}{p+3}\)
    12. \(\dfrac{3}{r−2}\)
    13. \(\dfrac{4(8x+1)}{10x−1}\)
    14. \(\dfrac{x−5}{(x−4)(x+1)(x−1)}\)
    15. \(\dfrac{1}{(x−1)(x+1)}\)
    16. \(\dfrac{5a^2+7a−36}{a(a−2)}\)
    17. \(\dfrac{c−5}{c+2}\)
    18. \(\dfrac{3(d+1)}{d+2}\)
    Writing Exercises
    1. Donald thinks that \(\dfrac{3}{x}+\dfrac{4}{x}\) is \(\dfrac{7}{2x}\). Is Donald correct? Explain.
    2. Explain how you find the Least Common Denominator of \(x^2+5x+4\) and \(x^2−16\).
    3. Simplify the expression \(\dfrac{4}{n^2+6n+9}−\dfrac{1}{n^2−9}\) and explain all your steps.
    Answer

    Answers will vary


    This page titled 5.5E: Exercises is shared under a CC BY-NC-SA 4.0 license and was authored, remixed, and/or curated by Stanislav A. Trunov and Elizabeth J. Hale via source content that was edited to the style and standards of the LibreTexts platform.