4.1: Problems from Math 2560 and 3600
- Page ID
- 136385
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From http://homepage.math.uiowa.edu/~idar..._34_F10ANS.txt
1.) Define: The LaPlace transform of \(f = {\cal L}(f) = \underline{\hskip 1.6in}\)
\u\u
[4]~~ 1a.) ${\cal L}(0) = \underline{~~0~~}$
\u
[10]~~ 1b.) ${\cal L}^{-1}({2 \over (s-4)^2 + 5}) = \underline{~~{2 \over \sqrt{5}} e^{4t}sin(t\sqrt{5})~~}$
${\cal L}^{-1}({2 \over (s-4)^2 + 5}) =$
${2 \over \sqrt{5}} {\cal L}^{-1}({\sqrt{5} \over (s-4)^2 + 5}) =$
${2 \over \sqrt{5}} e^{4t}sin(t\sqrt{5})$
1.) Define: The LaPlace transform of \(f = {\cal L}(f) = \underline{\hskip 1.6in} \vskip 10pt \)
[4]~~ 1a.) \( {\cal L}(0) = \underline{~~0~~} \vskip 10pt \)<\p>
[10]~~ 1b.) ${\cal L}^{-1}({2 \over (s-4)^2 + 5}) = \underline{~~{2 \over \sqrt{5}} e^{4t}sin(t\sqrt{5})~~}$ ${\cal L}^{-1}({2 \over (s-4)^2 + 5}) =$ ${2 \over \sqrt{5}} {\cal L}^{-1}({\sqrt{5} \over (s-4)^2 + 5}) =$ ${2 \over \sqrt{5}} e^{4t}sin(t\sqrt{5})$



