7.2: Spherical Coordinates
- Page ID
- 8340
Spherical coordinates are defined from Cartesian coordinates as
\[\begin{aligned} r &= \sqrt{x^2+y^2+z^2} \\[4pt] \phi &= \arctan(y/x) \\[4pt] \theta &=\arctan\left(\frac{\sqrt{x^2+y^2}}{z}\right)\end{aligned} \nonumber \]
or alternatively
\[\begin{aligned} x &= r \cos\phi\sin\theta,\\[4pt] y &= r \sin\phi\sin\theta \\[4pt] z &=r \cos\theta\end{aligned} \nonumber \]
as indicated schematically in Fig. \(\PageIndex{1}\).
Using the chain rule we find
\[\begin{aligned} \frac{\partial}{\partial x}{~} &= \frac{\partial r}{\partial x}\frac{\partial}{\partial r}{~} + \frac{\partial \phi}{\partial x}\frac{\partial}{\partial \phi}{~} + \frac{\partial \theta}{\partial x}\frac{\partial}{\partial \theta}{~}\nonumber\\[4pt] &= \frac{x}{r} \frac{\partial}{\partial r}{~}-\frac{y}{x^2+y^2}\frac{\partial}{\partial \phi}{~} +\frac{xz}{r^2\sqrt{x^2+y^2}}\frac{\partial}{\partial \theta}{~} \nonumber\\[4pt] &= \sin\theta\cos\phi\frac{\partial}{\partial r}{~}-\frac{\sin\phi}{r\sin\theta} \frac{\partial}{\partial \phi}{~} +\frac{\cos\phi\cos\theta}{r} \frac{\partial}{\partial \theta}{~},\\[4pt] \frac{\partial}{\partial y}{~} &= \frac{\partial r}{\partial y}\frac{\partial}{\partial r}{~}+\frac{\partial \phi}{\partial y}\frac{\partial}{\partial \phi}{~}+\frac{\partial \theta}{\partial y}\frac{\partial}{\partial \theta}{~}\nonumber\\[4pt] &= \frac{y}{r} \frac{\partial}{\partial r}{~}+\frac{x}{x^2+y^2}\frac{\partial}{\partial \phi}{~} +\frac{yz}{r^2\sqrt{x^2+y^2}}\frac{\partial}{\partial \theta}{~} \nonumber\\[4pt] &= \sin\theta\sin\phi\frac{\partial}{\partial r}{~}+\frac{\cos\phi}{r\sin\theta} \frac{\partial}{\partial \phi}{~} +\frac{\sin\phi\cos\theta}{r} \frac{\partial}{\partial \theta}{~},\\[4pt] \frac{\partial}{\partial z}{~} &= \frac{\partial r}{\partial z}\frac{\partial}{\partial r}{~}+\frac{\partial \phi}{\partial z}\frac{\partial}{\partial \phi}{~}+\frac{\partial \theta}{\partial z}\frac{\partial }{\partial \theta}{~}\nonumber\\[4pt] &= \frac{z}{r} \frac{\partial }{\partial r}{~} -\frac{\sqrt{x^2+y^2}}{r^2}\frac{\partial }{\partial \theta}{~} \nonumber\\[4pt] &= \sin\theta\sin\phi\frac{\partial }{\partial r}{~}-\frac{\sin\theta}{r} \frac{\partial }{\partial \theta}{~}.\\[4pt]\end{aligned} \nonumber \]
once again we can write \({\nabla}\) in terms of these coordinates.
\[\begin{aligned} {\nabla} &=& \hat{e}_r \frac{\partial}{\partial r}{~}+\hat{e}_\phi \frac{1}{r\sin\theta}\frac{\partial}{\partial \phi}{~} + \hat{e}_\theta \frac{1}{r}\frac{\partial}{\partial \theta}{~}\end{aligned} \nonumber \] where the unit vectors \[\begin{aligned} \hat{e}_r &=& (\sin\theta\cos\phi,\sin\theta\sin\phi,\cos\theta), \nonumber\\[4pt] \hat{e}_\phi &=& (-\sin\phi,\cos\phi,0), \nonumber\\[4pt] \hat{e}_\theta &=& (\cos\phi\cos\theta,\sin\phi\cos\theta,-\sin\theta).\end{aligned} \nonumber \]
are an orthonormal set. We say that spherical coordinates are orthogonal.
We can use this to evaluate \(\Delta={\nabla}^2\),
\[\Delta = \frac{1}{r^2}\frac{\partial}{\partial r}{~}\left(r^2 \frac{\partial}{\partial r}{~}\right) +\frac{1}{r^2} \frac{1}{\sin\theta} \frac{\partial}{\partial \theta}{~} \left( \sin\theta\frac{\partial}{\partial \theta}{~} \right) + \frac{1}{r^2}\frac{\partial^2}{\partial \phi^2}{~} \nonumber \]
Finally, for integration over these variables we need to know the volume of the small cuboid contained between \(r\) and \(r+\delta r\), \(\theta\) and \(\theta + \delta\theta\) and \(\phi\) and \(\phi+\delta\phi\).
The length of the sides due to each of these changes is \(\delta r\), \(r \delta \theta\) and \(r \sin \theta \delta \theta\), respectively (these are the Jacobians for the conversion of Cartesian coordinates to polar and spherical coordinates, respectively). We thus conclude that
\[\int_V f(x,y,z) dx dy dz = \int_V f(r,\theta,\phi) r^2\sin\theta \,dr \,d\theta \,d\phi. \nonumber \]