1.E: Algebra Fundamentals (Exercises)
- Page ID
- 6391
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\(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)Exercise \(\PageIndex{1}\)
Reduce to lowest terms.
- \(\frac{56}{120}\)
- \(\frac{54}{60}\)
- \(\frac{155}{90}\)
- \(\frac{315}{120}\)
- Answer
-
1. \(\frac{7}{15}\)
3. \(\frac{31}{18}\)
Exercise \(\PageIndex{2}\)
Simplify.
- \(- \left( - \frac { 1 } { 2 } \right)\)
- \(- \left( - \left( - \frac { 5 } { 8 } \right) \right)\)
- \(- ( - ( - a ) )\)
- \(- ( - ( - ( - a ) ) )\)
- Answer
-
1. \(\frac{1}{2}\)
3. \(-a\)
Exercise \(\PageIndex{3}\)
Graph the solution set and give the interval notation equivalent.
- \(x \geq - 10\)
- \(x < 0\)
- \(- 8 \leq x < 0\)
- \(- 10 < x \leq 4\)
- \(x < 3 \text { and } x \geq - 1\)
- \(x < 0 \text { and } x > 1\)
- \(x < - 2 \text { or } x > - 6\)
- \(x \leq - 1 \text { or } x > 3\)
- Answer
-
1. \([ - 10 , \infty )\);
Figure 1.E.1
3. \([ - 8,0 )\);
Figure 1.E.2
5. \([ - 1,3 )\);
Figure 1.E.3
7. \(\mathbb { R }\)
Figure 1.E.4
Exercise \(\PageIndex{4}\)
Determine the inequality that corresponds to the set expressed using interval notation.
- \([ - 8 , \infty )\)
- \(( - \infty , - 7 )\)
- \([ 12,32 ]\)
- \([ - 10,0 )\)
- \(( - \infty , 1 ] \cup ( 5 , \infty )\)
- \(( - \infty , - 10 ) \cup ( - 5 , \infty )\)
- \(( - 4 , \infty )\)
- \(( - \infty , 0 )\)
- Answer
-
1. \(x \geq - 8\)
3. \(12 \leq x \leq 32\)
5. \(x \leq 1 \text { or } x > 5\)
7. \(x > - 4\)
Exercise \(\PageIndex{5}\)
Simplify.
- \(- \left| - \frac { 3 } { 4 } \right|\)
- \(- \left| - \left( - \frac { 2 } { 3 } \right) \right|\)
- \(- ( - | - 4 | )\)
- \(- ( - ( - | - 3 | ) )\)
- Answer
-
1. \(-\frac{3}{4}\)
3. \(4\)
Exercise \(\PageIndex{6}\)
Determine the values represented by \(a\).
- \(| a | = 6\)
- \(| a | = 1\)
- \(| a | = - 5\)
- \(| a | = a\)
- Answer
-
1. \(a = \pm 6\)
2. \(\varnothing\)
Exercise \(\PageIndex{7}\)
Perform the operations.
- \(\frac { 1 } { 4 } - \frac { 1 } { 5 } + \frac { 3 } { 20 }\)
- \(\frac { 2 } { 3 } - \left( - \frac { 3 } { 4 } \right) - \frac { 5 } { 12 }\)
- \(\frac { 5 } { 3 } \left( - \frac { 6 } { 7 } \right) \div \left( \frac { 5 } { 14 } \right)\)
- \(\left( - \frac { 8 } { 9 } \right) \div \frac { 16 } { 27 } \left( \frac { 2 } { 15 } \right)\)
- \(\left( - \frac { 2 } { 3 } \right) ^ { 3 }\)
- \(\left( - \frac { 3 } { 4 } \right) ^ { 2 }\)
- \(( - 7 ) ^ { 2 } - 8 ^ { 2 }\)
- \(- 4 ^ { 2 } + ( - 4 ) ^ { 3 }\)
- \(10 - 8 \left( ( 3 - 5 ) ^ { 2 } - 2 \right)\)
- \(4 + 5 \left( 3 - ( 2 - 3 ) ^ { 2 } \right)\)
- \(- 3 ^ { 2 } - \left( 7 - ( - 4 + 2 ) ^ { 3 } \right)\)
- \(( - 4 + 1 ) ^ { 2 } - ( 3 - 6 ) ^ { 3 }\)
- \(\frac { 10 - 3 ( - 2 ) ^ { 3 } } { 3 ^ { 2 } - ( - 4 ) ^ { 2 } }\)
- \(\frac { 6 \left[ ( - 5 ) ^ { 2 } - ( - 3 ) ^ { 2 } \right] } { 4 - 6 ( - 2 ) ^ { 2 } }\)
- \(7 - 3 \left| 6 - ( - 3 - 2 ) ^ { 2 } \right|\)
- \(- 6 ^ { 2 } + 5 \left| 3 - 2 ( - 2 ) ^ { 2 } \right|\)
- \(\frac { 12 - \left| 6 - 2 ( - 4 ) ^ { 2 } \right| } { 3 - | - 4 | }\)
- \(\frac { - ( 5 - 2 | - 3 | ) ^ { 3 } } { \left| 4 - ( - 3 ) ^ { 2 } \right| - 3 ^ { 2 } }\)
- Answer
-
1. \(\frac{1}{5}\)
3. \(-4\)
5. \(-\frac{8}{27}\)
7. \(-15\)
9. \(-6\)
11. \(-24\)
13. \(-\frac{34}{7}\)
15. \(-50\)
17. \(14\)
Exercise \(\PageIndex{8}\)
Simplify.
- \(3 \sqrt { 8 }\)
- \(5 \sqrt { 18 }\)
- \(6 \sqrt { 0 }\)
- \(\sqrt { - 6 }\)
- \(\sqrt { \frac { 75 } { 16 } }\)
- \(\sqrt { \frac { 80 } { 49 } }\)
- \(\sqrt [ 3 ] { 40 }\)
- \(\sqrt [ 3 ] { 81 }\)
- \(\sqrt [ 3 ] { - 81 }\)
- \(\sqrt [ 3 ] { - 32 }\)
- \(\sqrt [ 3 ] { \frac { 250 } { 27 } }\)
- \(\sqrt [ 3 ] { \frac { 1 } { 125 } }\)
- Answer
-
1. \(6 \sqrt { 2 }\)
3. \(0\)
5. \(\frac { 5 \sqrt { 3 } } { 4 }\)
7. \(2 \sqrt [ 3 ] { 5 }\)
9. \(- 3 \sqrt [ 3 ] { 3 }\)
11. \(\frac { 5 \sqrt [ 3 ] { 2 } } { 3 }\)
Exercise \(\PageIndex{9}\)
Use a calculator to approximate the following to the nearest thousandth.
- \(\sqrt { 12 }\)
- \(3 \sqrt { 14 }\)
- \(\sqrt [ 3 ] { 18 }\)
- \(7 \sqrt [ 3 ] { 25 }\)
- Find the length of the diagonal of a square with sides measuring \(8\) centimeters.
- Find the length of the diagonal of a rectangle with sides measuring \(6\) centimeters and \(12\) centimeters.
- Answer
-
1. \(3.464\)
3. \(2.621\)
5. \(8 \sqrt { 2 }\) centimeters
Exercise \(\PageIndex{10}\)
Multiply
- \(\frac { 2 } { 3 } \left( 9 x ^ { 2 } + 3 x - 6 \right)\)
- \(- 5 \left( \frac { 1 } { 5 } y ^ { 2 } - \frac { 3 } { 5 } y + \frac { 1 } { 2 } \right)\)
- \(\left( a ^ { 2 } - 5 a b - 2 b ^ { 2 } \right) ( - 3 )\)
- \(\left( 2 m ^ { 2 } - 3 m n + n ^ { 2 } \right) \cdot 6\)
- Answer
-
1. \(6 x ^ { 2 } + 2 x - 4\)
3. \(- 3 a ^ { 2 } + 15 a b + 6 b ^ { 2 }\)
Exercise \(\PageIndex{11}\)
Combine like terms.
- \(5 x ^ { 2 } y - 3 x y ^ { 2 } - 4 x ^ { 2 } y - 7 x y ^ { 2 }\)
- \(9 x ^ { 2 } y ^ { 2 } + 8 x y + 3 - 5 x ^ { 2 } y ^ { 2 } - 8 x y - 2\)
- \(a ^ { 2 } b ^ { 2 } - 7 a b + 6 - a ^ { 2 } b ^ { 2 } + 12 a b - 5\)
- \(5 m ^ { 2 } n - 3 m n + 2 m n ^ { 2 } - 2 n m - 4 m ^ { 2 } n + m n ^ { 2 }\)
- Answer
-
1. \(x ^ { 2 } y - 10 x y ^ { 2 }\)
3. \(5 a b + 1\)
Exercise \(\PageIndex{12}\)
Simplify.
- \(5 x ^ { 2 } + 4 x - 3 \left( 2 x ^ { 2 } - 4 x - 1 \right)\)
- \(\left( 6 x ^ { 2 } y ^ { 2 } + 3 x y - 1 \right) - \left( 7 x ^ { 2 } y ^ { 2 } - 3 x y + 2 \right)\)
- \(a ^ { 2 } - b ^ { 2 } - \left( 2 a ^ { 2 } + a b - 3 b ^ { 2 } \right)\)
- \(m ^ { 2 } + m n - 6 \left( m ^ { 2 } - 3 n ^ { 2 } \right)\)
- Answer
-
1. \(- x ^ { 2 } + 16 x + 3\)
3. \(- a ^ { 2 } - a b + 2 b ^ { 2 }\)
Exercise \(\PageIndex{13}\)
Evaluate.
- \(x ^ { 2 } - 3 x + 1 \text { where } x = - \frac { 1 } { 2 }\)
- \(x ^ { 2 } - x - 1 \text { where } x = - \frac { 2 } { 3 }\)
- \(a ^ { 4 } - b ^ { 4 } \text { where } a = - 3 \text { and } b = - 1\)
- \(a ^ { 2 } - 3 a b + 5 b ^ { 2 } \text { where } a = 4 \text { and } b = - 2\)
- \(( 2 x + 1 ) ( x - 3 ) \text { where } x = - 3\)
- \(( 3 x + 1 ) ( x + 5 ) \text { where } x = - 5\)
- \(\sqrt { b ^ { 2 } - 4 a c } \text { where } a = 2 , b = - 4 , \text { and } c = - 1\)
- \(\sqrt { b ^ { 2 } - 4 a c } \text { where } a = 3 , b = - 6 , \text { and } c = - 2\)
- \(\pi r ^ { 2 } h \text { where } r = 2 \sqrt { 3 } \text { and } h = 5\)
- \(\frac { 4 } { 3 } \pi r ^ { 3 } \text { where } r = 2 \sqrt [ 3 ] { 6 }\)
- What is the simple interest earned on a \(4\) year investment of \($4,500\) at an annual interest rate of \(4 \frac{3}{4}\)%?
- James traveled at an average speed of \(48\) miles per hour for \(2 \frac{1}{4}\) hours. How far did he travel?
- The period of a pendulum \(T\) in seconds is given by the formula \(T = 2 \pi \sqrt { \frac { L } { 32 } }\) where \(L\) represents its length in feet. Approximate the period of a pendulum with length \(2\) feet. Round off to the nearest tenth of a foot.
- The average distance \(d\), in miles, a person can see an object is given by the formula \(d = \frac { \sqrt { 6 h } } { 2 }\) where \(h\) represents the person’s height above the ground, measured in feet. What average distance can a person see an object from a height of \(10\) feet? Round off to the nearest tenth of a mile.
- Answer
-
1. \(\frac{11}{4}\)
3. \(80\)
5. \(30\)
7. \(2 \sqrt { 6 }\)
9. \(60 \pi\)
11. \(\$ 855\)
13. \(1.6\) seconds
Exercise \(\PageIndex{14}\)
Multiply.
- \(\frac { x ^ { 10 } \cdot x ^ { 2 } } { x ^ { 5 } }\)
- \(\frac { x ^ { 6 } \left( x ^ { 2 } \right) ^ { 4 } } { x ^ { 3 } }\)
- \(- 7 x ^ { 2 } y z ^ { 3 } \cdot 3 x ^ { 4 } y ^ { 2 } z\)
- \(3 a ^ { 2 } b ^ { 3 } c \left( - 4 a ^ { 2 } b c ^ { 4 } \right) ^ { 2 }\)
- \(\frac { - 10 a ^ { 5 } b ^ { 0 } c ^ { - 4 } } { 25 a ^ { - 2 } b ^ { 2 } c ^ { - 3 } }\)
- \(\frac { - 12 x ^ { - 6 } y ^ { - 2 } z } { 36 x ^ { - 3 } y ^ { 4 } z ^ { 6 } }\)
- \(\left( - 2 x ^ { - 5 } y ^ { - 3 } z \right) ^ { - 4 }\)
- \(\left( 3 x ^ { 6 } y ^ { - 3 } z ^ { 0 } \right) ^ { - 3 }\)
- \(\left( \frac { - 5 a ^ { 2 } b ^ { 3 } } { c ^ { 5 } } \right) ^ { 2 }\)
- \(\left( \frac { - 3 m ^ { 5 } } { 5 n ^ { 2 } } \right) ^ { 3 }\)
- \(\left( \frac { - 2 a ^ { - 2 } b ^ { 3 } c } { 3 a b ^ { - 2 } c ^ { 0 } } \right) ^ { - 3 }\)
- \(\left( \frac { 6 a ^ { 3 } b ^ { - 3 } c } { 2 a ^ { 7 } b ^ { 0 } c ^ { - 4 } } \right) ^ { - 2 }\)
- Answer
-
1. \(x ^ { 7 }\)
3. \(- 21 x ^ { 6 } y ^ { 3 } z ^ { 4 }\)
5. \(- \frac { 2 a ^ { 7 } } { 5 b ^ { 2 } c }\)
7. \(\frac { x ^ { 20 } y ^ { 12 } } { 16 z ^ { 4 } }\)
9. \(\frac { 25 a ^ { 4 } b ^ { 6 } } { c ^ { 10 } }\)
11. \(- \frac { 27 a ^ { 9 } } { 8 b ^ { 15 } c ^ { 3 } }\)
Exercise \(\PageIndex{15}\)
Perform the operations.
- \(\left( 4.3 \times 10 ^ { 22 } \right) \left( 3.1 \times 10 ^ { - 8 } \right)\)
- \(\left( 6.8 \times 10 ^ { - 33 } \right) \left( 1.6 \times 10 ^ { 7 } \right)\)
- \(\frac { 1.4 \times 10 ^ { - 32 } } { 2 \times 10 ^ { - 10 } }\)
- \(\frac { 1.15 \times 10 ^ { 26 } } { 2.3 \times 10 ^ { - 7 } }\)
- The value of a new tablet computer in dollars can be estimated using the formula \(v = 450(t + 1)^{ −1}\) where \(t\) represents the number of years after it is purchased. Use the formula to estimate the value of the tablet computer \(2 \frac{1}{2}\) years after it was purchased.
- The speed of light is approximately \(6.7 × 10^{8}\) miles per hour. Express this speed in miles per minute and determine the distance light travels in \(4\) minutes.
- Answer
-
1. \(1.333 \times 10 ^ { 15 }\)
3. \(7 \times 10 ^ { - 23 }\)
5. \(\$ 128.57\)
Exercise \(\PageIndex{16}\)
Simplify.
- \(\left( x ^ { 2 } + 3 x - 5 \right) - \left( 2 x ^ { 2 } + 5 x - 7 \right)\)
- \(\left( 6 x ^ { 2 } - 3 x + 5 \right) + \left( 9 x ^ { 2 } + 3 x - 4 \right)\)
- \(\left( a ^ { 2 } b ^ { 2 } - a b + 6 \right) - ( a b + 9 ) + \left( a ^ { 2 } b ^ { 2 } - 10 \right)\)
- \(\left( x ^ { 2 } - 2 y ^ { 2 } \right) - \left( x ^ { 2 } + 3 x y - y ^ { 2 } \right) - \left( 3 x y + y ^ { 2 } \right)\)
- \(- \frac { 3 } { 4 } \left( 16 x ^ { 2 } + 8 x - 4 \right)\)
- \(6 \left( \frac { 4 } { 3 } x ^ { 2 } - \frac { 3 } { 2 } x + \frac { 5 } { 6 } \right)\)
- \(( 2 x + 5 ) ( x - 4 )\)
- \(( 3 x - 2 ) \left( x ^ { 2 } - 5 x + 2 \right)\)
- \(\left( x ^ { 2 } - 2 x + 5 \right) \left( 2 x ^ { 2 } - x + 4 \right)\)
- \(\left( a ^ { 2 } + b ^ { 2 } \right) \left( a ^ { 2 } - b ^ { 2 } \right)\)
- \(( 2 a + b ) \left( 4 a ^ { 2 } - 2 a b + b ^ { 2 } \right)\)
- \(( 2 x - 3 ) ^ { 2 }\)
- \(( 3 x - 1 ) ^ { 3 }\)
- \(( 2 x + 3 ) ^ { 4 }\)
- \(\left( x ^ { 2 } - y ^ { 2 } \right) ^ { 2 }\)
- \(\left( x ^ { 2 } y ^ { 2 } + 1 \right) ^ { 2 }\)
- \(\frac { 27 a ^ { 2 } b - 9 a b + 81 a b ^ { 2 } } { 3 a b }\)
- \(\frac { 125 x ^ { 3 } y ^ { 3 } - 25 x ^ { 2 } y ^ { 2 } + 5 x y ^ { 2 } } { 5 x y ^ { 2 } }\)
- \(\frac { 2 x ^ { 3 } - 7 x ^ { 2 } + 7 x - 2 } { 2 x - 1 }\)
- \(\frac { 12 x ^ { 3 } + 5 x ^ { 2 } - 7 x - 3 } { 4 x + 3 }\)
- \(\frac { 5 x ^ { 3 } - 21 x ^ { 2 } + 6 x - 3 } { x - 4 }\)
- \(\frac { x ^ { 4 } + x ^ { 3 } - 3 x ^ { 2 } + 10 x - 1 } { x + 3 }\)
- \(\frac { a ^ { 4 } - a ^ { 3 } + 4 a ^ { 2 } - 2 a + 4 } { a ^ { 2 } + 2 }\)
- \(\frac { 8 a ^ { 4 } - 10 } { a ^ { 2 } - 2 }\)
- Answer
-
1. \(- x ^ { 2 } - 2 x + 2\)
3. \(2 a ^ { 2 } b ^ { 2 } - 2 a b - 13\)
5. \(- 12 x ^ { 2 } - 6 x + 3\)
7. \(2 x ^ { 2 } - 3 x - 20\)
9. \(2 x ^ { 4 } - 5 x ^ { 3 } + 16 x ^ { 2 } - 13 x + 20\)
11. \(8 a ^ { 3 } + b ^ { 3 }\)
13. \(27 x ^ { 3 } - 27 x ^ { 2 } + 9 x - 1\)
15. \(x ^ { 4 } - 2 x ^ { 2 } y ^ { 2 } + y ^ { 4 }\)
17. \(9 a + 27 b - 3\)
19. \(x ^ { 2 } - 3 x + 2\)
21. \(5 x ^ { 2 } - x + 2 + \frac { 5 } { x - 4 }\)
23. \(a ^ { 2 } - a + 2\)
Exercise \(\PageIndex{17}\)
Solve.
- \(6 x - 8 = 2\)
- \(12 x - 5 = 3\)
- \(\frac { 5 } { 4 } x - 3 = \frac { 1 } { 2 }\)
- \(\frac { 5 } { 6 } x - \frac { 1 } { 4 } = \frac { 3 } { 2 }\)
- \(\frac { 9 x + 2 } { 3 } = \frac { 5 } { 6 }\)
- \(\frac { 3 x - 8 } { 10 } = \frac { 5 } { 2 }\)
- \(3 a - 5 - 2 a = 4 a - 6\)
- \(8 - 5 y + 2 = 4 - 7 y\)
- \(5 x - 6 - 8 x = 1 - 3 x\)
- \(17 - 6 x - 10 = 5 x + 7 - 11 x\)
- \(5 ( 3 x + 3 ) - ( 10 x - 4 ) = 4\)
- \(6 - 2 ( 3 x - 1 ) = - 4 ( 1 - 3 x )\)
- \(9 - 3 ( 2 x + 3 ) + 6 x = 0\)
- \(- 5 ( x + 2 ) - ( 4 - 5 x ) = 1\)
- \(\frac { 5 } { 9 } ( 6 y + 27 ) = 2 - \frac { 1 } { 3 } ( 2 y + 3 )\)
- \(4 - \frac { 4 } { 5 } ( 3 a + 10 ) = \frac { 1 } { 10 } ( 4 - 2 a )\)
- Solve for \(s : A = \pi r ^ { 2 } + \pi r s\)
- Solve for \(x : y = m x + b\)
- A larger integer is \(3\) more than twice another. If their sum divided by \(2\) is \(9\), find the integers.
- The sum of three consecutive odd integers is \(171\). Find the integers.
- The length of a rectangle is \(3\) meters less than twice its width. If the perimeter measures \(66\) meters, find the length and width.
- How long will it take \($500\) to earn \($124\) in simple interest earning \(6.2\)% annual interest?
- It took Sally \(3 \frac{1}{2}\) hours to drive the \(147\) miles home from her grandmother’s house. What was her average speed?
- Jeannine invested her bonus of \($8,300\) in two accounts. One account earned \(3 \frac{1}{2}\) % simple interest and the other earned \(4 \frac{3}{4}\) % simple interest. If her total interest for one year was \($341.75\), how much did she invest in each account?
- Answer
-
1. \(\frac{5}{3}\)
3. \(\frac{14}{5}\)
5. \(\frac{1}{18}\)
7. \(\frac{1}{3}\)
9. \(\varnothing\)
11. \(-3\)
13. \(\mathbb { R }\)
15. \(-\frac{7}{2}\)
17. \(s = \frac { A - \pi r ^ { 2 } } { \pi r }\)
19. \(5,13\)
21. Length: \(21\) meters; Width: \(12\) meters
23. \(42\) miles per hour
Exercise \(\PageIndex{18}\)
Solve. Graph all solutions on a number line and provide the corresponding interval notation.
- \(5 x - 7 < 18\)
- \(2 x - 1 > 2\)
- \(9 - x \leq 3\)
- \(3 - 7 x \geq 10\)
- \(61 - 3 ( x + 3 ) > 13\)
- \(7 - 3 ( 2 x - 1 ) \geq 6\)
- \(\frac { 1 } { 3 } ( 9 x + 15 ) - \frac { 1 } { 2 } ( 6 x - 1 ) < 0\)
- \(\frac { 2 } { 3 } ( 12 x - 1 ) + \frac { 1 } { 4 } ( 1 - 32 x ) < 0\)
- \(20 + 4 ( 2 a - 3 ) \geq \frac { 1 } { 2 } a + 2\)
- \(\frac { 1 } { 3 } \left( 2 x + \frac { 3 } { 2 } \right) - \frac { 1 } { 4 } x < \frac { 1 } { 2 } \left( 1 - \frac { 1 } { 2 } x \right)\)
- \(- 4 \leq 3 x + 5 < 11\)
- \(5 < 2 x + 15 \leq 13\)
- \(- 1 < 4 ( x + 1 ) - 1 < 9\)
- \(0 \leq 3 ( 2 x - 3 ) + 1 \leq 10\)
- \(- 1 < \frac { 2 x - 5 } { 4 } < 1\)
- \(- 2 \leq \frac { 3 - x } { 3 } < 1\)
- \(2 x + 3 < 13 \text { and } 4 x - 1 > 10\)
- \(3 x - 1 \leq 8 \text { and } 2 x + 5 \geq 23\)
- \(5 x - 3 < - 2 \text { or } 5 x - 3 > 2\)
- \(1 - 3 x \leq - 1 \text { or } 1 - 3 x \geq 1\)
- \(5 x + 6 < 6 \text { or } 9 x - 2 > - 11\)
- \(2 ( 3 x - 1 ) < - 16 \text { or } 3 ( 1 - 2 x ) < - 15\)
- Jerry scored \(90, 85, 92\), and \(76\) on the first four algebra exams. What must he score on the fifth exam so that his average is at least \(80\)?
- If \(6\) degrees less than \(3\) times an angle is between \(90\) degrees and \(180\) degrees, then what are the bounds of the original angle?
- Answer
-
1. \(( - \infty , 5 )\);
Figure 1.E.5
3. \([ 6 , \infty )\);
Figure 1.E.6
5. \(( - \infty , 13 )\);
Figure 1.E.7
7. \(\varnothing\);
Figure 1.E.8
9. \(\left[ - \frac { 4 } { 5 } , \infty \right)\);
Figure 1.E.9
11. \([ - 3,2 )\);
Figure 1.E.10
13. \(\left( - 1 , \frac { 3 } { 2 } \right)\);
Figure 1.E.11
15. \(\left( \frac { 1 } { 2 } , \frac { 9 } { 2 } \right)\);
Figure 1.E.12
17. \(\left( \frac { 11 } { 4 } , 5 \right)\);
Figure 1.E.13
19. \(\left( - \infty , \frac { 1 } { 5 } \right) \cup ( 1 , \infty )\);
Figure 1.E.14
21. \(\mathbb { R }\);
Figure 1.E.15
23. Jerry must score at least \(57\) on the fifth exam.
Sample Exam
Exercise \(\PageIndex{19}\)
Simplify.
- \(5 - 3 \left( 12 - \left| 2 - 5 ^ { 2 } \right| \right)\)
- \(\left( - \frac { 1 } { 2 } \right) ^ { 2 } - \left( 3 - 2 \left| - \frac { 3 } { 4 } \right| \right) ^ { 3 }\)
- \(- 7 \sqrt { 60 }\)
- \(5 \sqrt [ 3 ] { - 32 }\)
- Find the diagonal of a square with sides measuring \(6\) centimeters.
- Answer
-
1. \(38\)
3. \(- 14 \sqrt { 15 }\)
5. \(6 \sqrt { 2 }\) centimeters
Exercise \(\PageIndex{20}\)
Simplify
- \(- 5 x ^ { 2 } y z ^ { - 1 } \left( 3 x ^ { 3 } y ^ { - 2 } z \right)\)
- \(\left( \frac { - 2 a ^ { - 4 } b ^ { 2 } c } { a ^ { - 3 } b ^ { 0 } c ^ { 2 } } \right) ^ { - 3 }\)
- \(2 \left( 3 a ^ { 2 } b ^ { 2 } + 2 a b - 1 \right) - a ^ { 2 } b ^ { 2 } + 2 a b - 1\)
- \(\left( x ^ { 2 } - 6 x + 9 \right) - \left( 3 x ^ { 2 } - 7 x + 2 \right)\)
- \(( 2 x - 3 ) ^ { 3 }\)
- \(( 3 a - b ) \left( 9 a ^ { 2 } + 3 a b + b ^ { 2 } \right)\)
- \(\frac { 6 x ^ { 4 } - 17 x ^ { 3 } + 16 x ^ { 2 } - 18 x + 13 } { 2 x - 3 }\)
- Answer
-
2. \(- \frac { a ^ { 3 } c ^ { 3 } } { 8 b ^ { 6 } }\)
4. \(- 2 x ^ { 2 } + x + 7\)
6. \(27 a ^ { 3 } - b ^ { 3 }\)
Exercise \(\PageIndex{21}\)
Solve.
- \(\frac { 4 } { 5 } x - \frac { 2 } { 15 } = 2\)
- \(\frac { 3 } { 4 } ( 8 x - 12 ) - \frac { 1 } { 2 } ( 2 x - 10 ) = 16\)
- \(12 - 5 ( 3 x - 1 ) = 2 ( 4 x + 3 )\)
- \(\frac { 1 } { 2 } ( 12 x - 2 ) + 5 = 4 \left( \frac { 3 } { 2 } x - 8 \right)\)
- Solve for \(y : a x + b y = c\)
- Answer
-
1. \(\frac{8}{3}\)
3. \(\frac{11}{23}\)
5. \(y = \frac { c - a x } { b }\)
Exercise \(\PageIndex{22}\)
Solve. Graph the solutions on a number line and give the corresponding interval notation.
- \(2 ( 3 x - 5 ) - ( 7 x - 3 ) \geq 0\)
- \(2 ( 4 x - 1 ) - 4 ( 5 + 2 x ) < - 10\)
- \(- 6 \leq \frac { 1 } { 4 } ( 2 x - 8 ) < 4\)
- \(3 x - 7 > 14 \text { or } 3 x - 7 < - 14\)
- Answer
-
2. \(\mathbb { R }\);
Figure 1.E.16
4. \(\left( - \infty , - \frac { 7 } { 3 } \right) \cup ( 7 , \infty )\);
Figure 1.E.17
Exercise \(\PageIndex{23}\)
Use algebra to solve the following.
- Degrees Fahrenheit \(F\) is given by the formula \(F = \frac{9}{5} C + 32\) where C represents degrees Celsius. What is the Fahrenheit equivalent to \(35\)° Celsius?
- The length of a rectangle is \(5\) inches less than its width. If the perimeter is \(134\) inches, find the length and width of the rectangle.
- Melanie invested \(4,500\) in two separate accounts. She invested part in a CD that earned \(3.2\)% simple interest and the rest in a savings account that earned \(2.8\)% simple interest. If the total simple interest for one year was \($138.80\), how much did she invest in each account?
- A rental car costs \($45.00\) per day plus \($0.48\) per mile driven. If the total cost of a one-day rental is to be at most \($105\), how many miles can be driven?
- Answer
-
2. Length: \(31\) inches; width: \(36\) inches
4. The car can be driven at most \(125\) miles.