4.8E: AntiDerivative & Indefinite Integral Exercises
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4.8: Antiderivatives
For the following exercises, find the antiderivative F(x) of each function f(x).
470) f(x)=1x2+x
471) f(x)=ex−3x2+sinx
- Answer:
- F(x)=ex−x3−cos(x)+C
472) f(x)=ex+3x−x2
473) f(x)=x−1+4sin(2x)
- Answer:
- F(x)=x22−x−2cos(2x)+C
474) f(x)=5x4+4x5
475) f(x)=x+12x2
- Answer:
- F(x)=12x2+4x3+C
476) f(x)=1√x
477) f(x)=(√x)3
- Answer:
- F(x)=25(√x)5+C
478) f(x)=x1/3+(2x)1/3
479) f(x)=x1/3x2/3
- Answer:
- (F(x)=32x2/3+C
480) f(x)=2sin(x)+sin(2x)
481) f(x)=sec2(x)+1
- Answer:
- (F(x)=x+tan(x)+C\)
482) f(x)=sinxcosx
483) f(x)=sin2(x)cos(x)
- Answer:
- F(x)=13sin3(x)+C
484) f(x)=0
485) f(x)=12csc2(x)+1x2
- Answer:
- F(x)=−12cot(x)−1x+C
486) f(x)=cscxcotx+3x
487) f(x)=4cscxcotx−secxtanx
- Answer:
- F(x)=−secx−4cscx+C
488) f(x)=8secx(secx−4tanx)
489) f(x)=12e−4x+sinx
- Answer:
- F(x)=−18e−4x−cosx+C
For the following exercises, evaluate the integral.
490) ∫(−1)dx
491) ∫sinxdx
- Answer:
- −cosx+C
492) ∫(4x+√x)dx
493) ∫3x2+2x2dx
- Answer:
- 3x−2x+C
494) ∫(secxtanx+4x)dx
495) ∫(4√x+4√x)dx
- Answer:
- 83x3/2+45x5/4+C
496) ∫(x−1/3−x2/3)dx
497) ∫14x3+2x+1x3dx
- Answer:
- 14x−2x−12x2+C
498) ∫(ex+e−x)dx
For the following exercises, solve the initial value problem.
499) f′(x)=x−3,f(1)=1
- Answer:
- f(x)=−12x2+32
500) f′(x)=√x+x2,f(0)=2
501) f′(x)=cosx+sec2(x),f(π4)=2+√22
- Answer:
- f(x)=sinx+tanx+1
502) f′(x)=x3−8x2+16x+1,f(0)=0
503) f′(x)=2x2−x22,f(1)=0
- Answer:
- f(x)=−16x3−2x+136
J4.8.1) not here yet
- Answer:
- 8
J4.8.2) not here yet
J4.8.3) not here yet
- Answer:
- 8
For the following exercises, find two possible functions f given the second- or third-order derivatives
504) f″
505) f''(x)=e^{−x}
Solution: Answers may vary; one possible answer is f(x)=e^{−x}
506) f''(x)=1+x
507) f'''(x)=cosx
Solution: Answers may vary; one possible answer is f(x)=−sinx
508) f'''(x)=8e^{−2x}−sinx
509) A car is being driven at a rate of 40 mph when the brakes are applied. The car decelerates at a constant rate of 10 ft/sec^2. How long before the car stops?
Solution: 5.867 sec
510) In the preceding problem, calculate how far the car travels in the time it takes to stop.
511) You are merging onto the freeway, accelerating at a constant rate of 12 ft/sec2. How long does it take you to reach merging speed at 60 mph?
Solution: 7.333 sec
512) Based on the previous problem, how far does the car travel to reach merging speed?
513) A car company wants to ensure its newest model can stop in 8 sec when traveling at 75 mph. If we assume constant deceleration, find the value of deceleration that accomplishes this.
Solution: 13.75 ft/sec^2
514) A car company wants to ensure its newest model can stop in less than 450 ft when traveling at 60 mph. If we assume constant deceleration, find the value of deceleration that accomplishes this.
For the following exercises, find the antiderivative of the function, assuming F(0)=0.
515) [T] f(x)=x^2+2
Solution: F(x)=\frac{1}{3}x^3+2x
516) [T] f(x)=4x−\sqrt{x}
517) [T] f(x)=sinx+2x
Solution: F(x)=x^2−cosx+1
518) [T] f(x)=e^x
519) [T] f(x)=\frac{1}{(x+1)^2}
Solution: F(x)=−\frac{1}{(x+1)}+1
520) [T] f(x)=e^{−2x}+3x^2
For the following exercises, determine whether the statement is true or false. Either prove it is true or find a counterexample if it is false.
521) If f(x) is the antiderivative of v(x), then 2f(x) is the antiderivative of 2v(x).
Solution: True
522) If f(x) is the antiderivative of v(x), then f(2x) is the antiderivative of v(2x).
523) If f(x) is the antiderivative of v(x), then f(x)+1 is the antiderivative of v(x)+1.
Solution: False
524) If f(x) is the antiderivative of v(x), then (f(x))^2 is the antiderivative of (v(x))^2.