11.42: A.6.4- Section 6.4 Answers
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1. If e=1, then Y2=ρ(ρ−2X); if e≠1(X+eρ1−e2)2+Y21−e2=ρ2(1−e2)2 if; e<1 let X0=−eρ1−e2,a=ρ1−e2,b=ρ1−e2
2. Let h=r20θ′0; then ρ=h2k,e=[(ρr0−1)2+(ρr′0h)2]1/2. If e=0, then θ0 is undefined, but also irrelevant if e≠0 then ϕ=θ0−α, where −π≤α<πcosα=1e(ρr0−1) and sinα=pr′0eh.
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4. f(r)=−mh2(6cr4+1r3)
5. f(r)=−mh2(γ2+1)r3
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