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Mathematics LibreTexts

5.C: Surface Area

  • Page ID
    31464
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    Overview

    The purpose of this lesson is to learn how to find the surface area of a solid.

    This lesson will address the following CCRS Standard(s) for Geometry:

    • 7.G.6: Solve real-world and mathematical problems involving area, volume and surface area of two- and three- dimensional objects composed of triangles, quadrilaterals, polygons, cubes, and right prisms

    Directions

    1. Take notes while watching videos below
    2. Go to http://wamap.org and log into our course to complete assignment 5.B with 80% or better.

    Do

    Complete assignment 5.B with 80% or better at http://wamap.org

    Summary

    In this lesson we have learned:

    • If P is the perimeter of the base of a prism (or circumference of the base of a cylinder), and B is the area of the base, then the surface area of the prism (or cylinder) is LaTeX: A=2B+Pl (where l is the slant height)
    • If P is the perimeter of the base of a pyramid (or circumference of the base of a cone), and B is the area of the base, then the surface area of the pyramid (or cone) is LaTeX: A=B+\frac{1}{2}Pl (where l is the slant height)
    • The surface area of a sphere is LaTeX: A=4\pi r^2</mi> <msup> <mi>r</mi> <mn>2</mn> </msup> </math>' data-equation-content="A=4\pi r^2">
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