Processing math: 100%
Skip to main content
Library homepage
 

Text Color

Text Size

 

Margin Size

 

Font Type

Enable Dyslexic Font
Mathematics LibreTexts

4.4E: Exercises for Section 4.4

( \newcommand{\kernel}{\mathrm{null}\,}\)

1) Consider two athletes running at variable speeds v1(t) and v2(t). The runners start and finish a race at exactly the same time. Explain why the two runners must be going the same speed at some point.

2) Two mountain climbers start their climb at base camp, taking two different routes, one steeper than the other, and arrive at the peak at exactly the same time. Is it necessarily true that, at some point, both climbers increased in altitude at the same rate?

Answer
Yes. It is implied by the Mean Value Theorem for Integrals.

3) To get on a certain toll road a driver has to take a card that lists the mile entrance point. The card also has a timestamp. When going to pay the toll at the exit, the driver is surprised to receive a speeding ticket along with the toll. Explain how this can happen.

4) Set F(x)=x1(1t)dt. Find F(2) and the average value of F over [1,2].

Answer
F(2)=1; average value of F over [1,2] is 1/2.

In exercises 5 - 16, use the Fundamental Theorem of Calculus, Part 1, to find each derivative.

5) ddx[x1et2dt]

6) ddx[x1ecostdt]

Answer
ddx[x1ecostdt]=ecost

7) ddx[x39y2dy]

8) ddx[x3ds16s2]

Answer
ddx[x3ds16s2]=116x2

9) ddx[2xxtdt]

10) ddx[x0tdt]

Answer
ddx[x0tdt]=xddx(x)=12

11) ddx[sinx01t2dt]

12) ddx[1cosx1t2dt]

Answer
ddx[1cosx1t2dt]=1cos2xddx(cosx)=|sinx|sinx

13) ddx[x1t21+t4dt]

14) ddx[x21t1+tdt]

Answer
ddx[x21t1+tdt]=2x|x|1+x2

15) ddx[lnx0etdt]

16) ddx[ex1lnu2du]

Answer
ddx[ex1lnu2du]=ln(e2x)ddx(ex)=2xex

17) The graph of y=x0f(t)dt, where f is a piecewise constant function, is shown here.

A function with linear segments which goes through the points (0, 0), (1, 3), (2, 2), (3, 0), (4, 3), (5, 3), and (6, 2). The area under the function and above the x axis is shaded.

a. Over which intervals is f positive? Over which intervals is it negative? Over which intervals, if any, is it equal to zero?

b. What are the maximum and minimum values of f?

c. What is the average value of f?

18) The graph of y=x0f(t)dt, where f is a piecewise constant function, is shown here.

A graph of a function with linear segments that goes through the points (0, 0), (1, -1), (2, 1), (3, 1), (4, -2), (5, -2), and (6, 0). The area over the function but under the x axis over the interval [0, 1.5] and [3.25, 6] is shaded. The area under the function but over the x axis over the interval [1.5, 3.25] is shaded.

a. Over which intervals is f positive? Over which intervals is it negative? Over which intervals, if any, is it equal to zero?

b. What are the maximum and minimum values of f?

c. What is the average value of f?

Answer
a. f is positive over [1,2] and [5,6], negative over [0,1] and [3,4], and zero over [2,3] and [4,5].
b. The maximum value is 2 and the minimum is 3.
c. The average value is 0.

19) The graph of y=x0(t)dt, where is a piecewise linear function, is shown here.

A graph of a function which goes through the points (0, 0), (1, -1), (2, 1), (3, 3), (4, 3.5), (5, 4), and (6, 2). The area over the function and under the x axis over [0, 1.8] is shaded, and the area under the function and over the x axis is shaded.

a. Over which intervals is positive? Over which intervals is it negative? Over which, if any, is it zero?

b. Over which intervals is increasing? Over which is it decreasing? Over which, if any, is it constant?

c. What is the average value of ?

20) The graph of y=x0(t)dt, where is a piecewise linear function, is shown here.

A graph of a function that goes through the points (0, 0), (1, 1), (2, 0), (3, -1), (4.5, 0), (5, 1), and (6, 2). The area under the function and over the x axis over the intervals [0, 2] and [4.5, 6] is shaded. The area over the function and under the x axis over the interval [2, 2.5] is shaded.

a. Over which intervals is positive? Over which intervals is it negative? Over which, if any, is it zero?

b. Over which intervals is increasing? Over which is it decreasing? Over which intervals, if any, is it constant?

c. What is the average value of ?

Answer
a. is positive over [0,1] and [3,6], and negative over [1,3].
b. It is increasing over [0,1] and [3,5], and it is constant over [1,3] and [5,6].
c. Its average value is 13.

In exercises 21 - 26, use a calculator to estimate the area under the curve by computing T10, the average of the left- and right-endpoint Riemann sums using N=10 rectangles. Then, using the Fundamental Theorem of Calculus, Part 2, determine the exact area.

21) [T] y=x2 over [0,4]

22) [T] y=x3+6x2+x5 over [4,2]

Answer
T10=49.08,32(x3+6x2+x5)dx=48

23) [T] y=x3 over [0,6]

24) [T] y=x+x2 over [1,9]

Answer
T10=260.836,91(x+x2)dx=260

25) [T] (ex)dx over [0,2]

26) [T] 4x2dx over [1,4]

Answer
T10=3.058,414x2dx=3

In exercises 27 - 40, evaluate each definite integral using the Fundamental Theorem of Calculus, Part 2.

27) 21(x23x)dx

28) 32(x2+3x5)dx

Answer
F(x)=x33+3x225x,F(3)F(2)=356

29) 32(t+2)(t3)dt

30) 32(t29)(4t2)dt

Answer
F(x)=t55+13t3336t,F(3)F(2)=6215

31) 21x9dx

32) 10x99dx

Answer
F(x)=x100100,F(1)F(0)=1100

33) 84(4t5/23t3/2)dt

34) 41/4(x21x2)dx

Answer
F(x)=x33+1x,F(4)F(14)=112564

35) 212x3dx

36) 4112xdx

Answer
F(x)=x,F(4)F(1)=1

37) 412tt2dt

38) 161dtt1/4

Answer
F(t)=43t3/4,F(16)F(1)=283

39) 21(1t21t3)dt

40) 12(1t21t3)dt

Answer
F(t)=1t+12t2,F(1)F(2)=78

In exercises 41-42, use the evaluation theorem to express the integral as a function F(x).

41) xat2dt

42) x1etdt

Answer
F(x)=exe

In exercises 43-44, identify the roots of the integrand to remove absolute values, then evaluate using the Fundamental Theorem of Calculus, Part 2.

43) 32|x|dx

44) 42t22t3dt

Answer
12(t22t3)dt31(t22t3)dt+43(t22t3)dt=463

45) Suppose that for a particular company, the spending on construction projects between 2010 (t=1) to 2019 (t=20) is modeled by the function S(t)=25t, where S is measured in thousands of dollars per year and t is measured in years. What is the average spending per year on construction projects between 2010 and 2019?

46) Suppose the rate of gasoline consumption for a family over a one year period (t=0 to t=12) can be modeled by the function t2+12t+25 gal/mo.What is the average monthly consumption, and for which value(s) of t is the rate at time t equal to the average rate?

Answer
The average value is 49 gal/mo, and the rate is equal to the average value at approximately time t=2.54 and t=9.46.

47) Explain why, if f is continuous over [a,b], there is at least one point c[a,b] such that f(c)=1babaf(t)dt.

48) Explain why, if f is continuous over [a,b] and is not equal to a constant, there is at least one point M[a,b] such that f(M)=1babaf(t)dt and at least one point m[a,b] such that f(m)<1babaf(t)dt.

Answer
If f is not constant, then its average is strictly smaller than the maximum and larger than the minimum, which are attained over [a,b] by the extreme value theorem.

This page titled 4.4E: Exercises for Section 4.4 is shared under a CC BY-NC-SA 1.0 license and was authored, remixed, and/or curated by Karen Cliffe.

Support Center

How can we help?