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4.3: Working with Events
https://math.libretexts.org/Courses/Rio_Hondo/Math_150%3A_Survey_of_Mathematics/04%3A_Probability/4.03%3A_Working_with_Events
where \(P(A \text { and } B)\) is the probability of events \(A\) and \(B\) both occurring, \(P(A)\) is the probability of event \(A\) occurring, and \(P(B)\) is the probability of event \(B\) occurri...where \(P(A \text { and } B)\) is the probability of events \(A\) and \(B\) both occurring, \(P(A)\) is the probability of event \(A\) occurring, and \(P(B)\) is the probability of event \(B\) occurring If you look back at the coin and die example from earlier, you can see how the number of outcomes of the first event multiplied by the number of outcomes in the second event multiplied to equal the total number of possible outcomes in the combined event.
9.3: Working with Events
https://math.libretexts.org/Courses/Chabot_College/Math_in_Society_(Zhang)/09%3A_Probability/9.03%3A_Working_with_Events
where \(P(A \text { and } B)\) is the probability of events \(A\) and \(B\) both occurring, \(P(A)\) is the probability of event \(A\) occurring, and \(P(B)\) is the probability of event \(B\) occurri...where \(P(A \text { and } B)\) is the probability of events \(A\) and \(B\) both occurring, \(P(A)\) is the probability of event \(A\) occurring, and \(P(B)\) is the probability of event \(B\) occurring If you look back at the coin and die example from earlier, you can see how the number of outcomes of the first event multiplied by the number of outcomes in the second event multiplied to equal the total number of possible outcomes in the combined event.
3.6: Working with Events
https://math.libretexts.org/Courses/Cerritos_College/Mathematics_for_Technology/03%3A_Module_3-_Probability_and_Statistics/3.06%3A_Working_with_Events
where \(P(A \text { and } B)\) is the probability of events \(A\) and \(B\) both occurring, \(P(A)\) is the probability of event \(A\) occurring, and \(P(B)\) is the probability of event \(B\) occurri...where \(P(A \text { and } B)\) is the probability of events \(A\) and \(B\) both occurring, \(P(A)\) is the probability of event \(A\) occurring, and \(P(B)\) is the probability of event \(B\) occurring If you look back at the coin and die example from earlier, you can see how the number of outcomes of the first event multiplied by the number of outcomes in the second event multiplied to equal the total number of possible outcomes in the combined event.
6.2: Probability Rules with "Not," "Or" and "And"
https://math.libretexts.org/Courses/Fullerton_College/Math_100%3A_Liberal_Arts_Math_(Claassen_and_Ikeda)/06%3A_Probability/6.02%3A_Probability_Rules_with_Not_Or_and_And
The complement of event \(A\) is the event “\(A\) does not happen.” It is the set of outcomes in the sample space \(S\) that are not in event \(A\). Say we look at the event of drawing a single card f...The complement of event \(A\) is the event “\(A\) does not happen.” It is the set of outcomes in the sample space \(S\) that are not in event \(A\). Say we look at the event of drawing a single card from a deck and the outcome of drawing a "red card or a jack". If you count the number of options for red cards and the number of options for a jack, you are counting the red jacks twice.
3.3: Working with Events
https://math.libretexts.org/Courses/Northwest_Florida_State_College/MGF_1131%3A_Mathematics_in_Context/03%3A_Probability/3.03%3A_Working_with_Events
where \(P(A \text { and } B)\) is the probability of events \(A\) and \(B\) both occurring, \(P(A)\) is the probability of event \(A\) occurring, and \(P(B)\) is the probability of event \(B\) occurri...where \(P(A \text { and } B)\) is the probability of events \(A\) and \(B\) both occurring, \(P(A)\) is the probability of event \(A\) occurring, and \(P(B)\) is the probability of event \(B\) occurring If you look back at the coin and die example from earlier, you can see how the number of outcomes of the first event multiplied by the number of outcomes in the second event multiplied to equal the total number of possible outcomes in the combined event.
5.0.2: Working with Events
https://math.libretexts.org/Courses/Cosumnes_River_College/Math_300%3A_Mathematical_Ideas_Textbook_(Muranaka)/05%3A_Probability/5.00%3A_Probability/5.0.02%3A_Working_with_Events
where \(P(A \text { and } B)\) is the probability of events \(A\) and \(B\) both occurring, \(P(A)\) is the probability of event \(A\) occurring, and \(P(B)\) is the probability of event \(B\) occurri...where \(P(A \text { and } B)\) is the probability of events \(A\) and \(B\) both occurring, \(P(A)\) is the probability of event \(A\) occurring, and \(P(B)\) is the probability of event \(B\) occurring If you look back at the coin and die example from earlier, you can see how the number of outcomes of the first event multiplied by the number of outcomes in the second event multiplied to equal the total number of possible outcomes in the combined event.
12.3: Working with Events
https://math.libretexts.org/Bookshelves/Applied_Mathematics/Math_in_Society_(Lippman)/12%3A_Probability/12.03%3A_Working_with_Events
where \(P(A \text { and } B)\) is the probability of events \(A\) and \(B\) both occurring, \(P(A)\) is the probability of event \(A\) occurring, and \(P(B)\) is the probability of event \(B\) occurri...where \(P(A \text { and } B)\) is the probability of events \(A\) and \(B\) both occurring, \(P(A)\) is the probability of event \(A\) occurring, and \(P(B)\) is the probability of event \(B\) occurring If you look back at the coin and die example from earlier, you can see how the number of outcomes of the first event multiplied by the number of outcomes in the second event multiplied to equal the total number of possible outcomes in the combined event.
13.3: Conditional Probability and Intersections of Events
https://math.libretexts.org/Courses/Las_Positas_College/Math_for_Liberal_Arts/13%3A_Probability/13.03%3A_Conditional_Probability_and_Intersections_of_Events
If you look back at the coin and die example from earlier, you can see how the number of outcomes of the first event multiplied by the number of outcomes in the second event equals the total number of...If you look back at the coin and die example from earlier, you can see how the number of outcomes of the first event multiplied by the number of outcomes in the second event equals the total number of possible outcomes in the combined event. The probability that the second card is black given that the first card is the Ace of Diamonds is \(\frac{26}{51}\) because 26 of the remaining 51 cards are black.
4.2: Theoretical Probability
https://math.libretexts.org/Courses/Cosumnes_River_College/STAT_300%3A_Introduction_to_Probability_and_Statistics_(Nam_Lam)/04%3A_Probability/4.02%3A_Theoretical_Probability
However, the outcomes are not equally likely since you can get one head by getting a head on the first flip and a tail on the second or a tail on the first flip and a head on the second.
9.5: Working with Events
https://math.libretexts.org/Courses/Angelo_State_University/Finite_Mathematics/09%3A_Sets_and_Probability/9.07%3A_Working_with_Events
where \(P(A \text { and } B)\) is the probability of events \(A\) and \(B\) both occurring, \(P(A)\) is the probability of event \(A\) occurring, and \(P(B)\) is the probability of event \(B\) occurri...where \(P(A \text { and } B)\) is the probability of events \(A\) and \(B\) both occurring, \(P(A)\) is the probability of event \(A\) occurring, and \(P(B)\) is the probability of event \(B\) occurring If you look back at the coin and die example from earlier, you can see how the number of outcomes of the first event multiplied by the number of outcomes in the second event multiplied to equal the total number of possible outcomes in the combined event.

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