Since the probability of being infective at time t+Δt is equal to the probability of being infective at time t multiplied by the probability of not recovering during time Δt, w...Since the probability of being infective at time t+Δt is equal to the probability of being infective at time t multiplied by the probability of not recovering during time Δt, we have l(t+Δt)=l(t)(1−γΔt) or as Δt→0dldt=−γl With initial condition l(0)=1l(t)=e−γt Now, the expected number of secondary infections produced by a single primary infective over the …
