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  • 22.10: Dividir polinomios
    https://math.libretexts.org/Courses/Santiago_Canyon_College/HiSet_Mathematica_(Lopez)/22%3A_Expresiones_racionales/22.10%3A_Dividir_polinomios
    \(\dfrac{3x^2}{x} + \dfrac{x}{x} - \dfrac{11}{x} = 3x + 1 - \dfrac{11}{x}\) Restar\(x^3 + 3x^2\) de\(x^3 + 4x^2 + x - 1\). x^3 + 4x^2 + x - 1 && x^3 + 4x^2 + x - 1\\ - (x^2 + 3x) && - (x^2 + 3x) && -x...\(\dfrac{3x^2}{x} + \dfrac{x}{x} - \dfrac{11}{x} = 3x + 1 - \dfrac{11}{x}\) Restar\(x^3 + 3x^2\) de\(x^3 + 4x^2 + x - 1\). x^3 + 4x^2 + x - 1 && x^3 + 4x^2 + x - 1\\ - (x^2 + 3x) && - (x^2 + 3x) && -x^2 - 3x\ Tenemos que dividirnos\(x^3 + 4x^2 + x - 1\) por\(x + 3\). \(\dfrac{x^3 + 4x^2 + x - 1}{x + 3} = x^2 + x - 2 + \dfrac{5}{x+3}\) \(x - 3 + \dfrac{14x - 14}{x^2 + 4x - 5} = x - 3 + \dfrac{14}{x+5}\) Resolver la ecuación\(\dfrac{1}{x + 3} + \dfrac{1}{x - 3} = \dfrac{1}{x^2 - 9}\)

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