Let M>0; since this is a limit from the left, we need −δ<x+7<0 to lead 1x+7<−M (since the limit is −∞) 208) A function has to be continuous at x=a if the \(\displaystyle ...Let M>0; since this is a limit from the left, we need −δ<x+7<0 to lead 1x+7<−M (since the limit is −∞) 208) A function has to be continuous at x=a if the lim exists. 210) If there is a vertical asymptote at x=a for the function f(x), then f is undefined at the point x=a. Since lim_{x→0}\,x^2=0=lim_{x→0}\,−x^2, it follows that lim_{x→0}\,x^2cos(2πx)=0.
