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- https://math.libretexts.org/Courses/Las_Positas_College/Foundational_Mathematics/22%3A_Conics/22.05%3A_HyperbolasIn the figure, we placed the hyperbola so the foci \(((−c,0),(c,0))\) are on the \(x\)-axis and the center is the origin. Sketch the rectangle that goes through the points \(3\) units to the left/righ...In the figure, we placed the hyperbola so the foci \(((−c,0),(c,0))\) are on the \(x\)-axis and the center is the origin. Sketch the rectangle that goes through the points \(3\) units to the left/right of the center and \(4\) units above and below the center. Sketch the rectangle that goes through the points \(3\) units to the left/right of the center and \(2\) units above and below the center. The midpoint of the segment joining the foci is called the center of the hyperbola.
- https://math.libretexts.org/Courses/Coastline_College/Math_C045%3A_Beginning_and_Intermediate_Algebra_(Tran)/13%3A_Conics/13.05%3A_HyperbolasIn the figure, we placed the hyperbola so the foci \(((−c,0),(c,0))\) are on the \(x\)-axis and the center is the origin. Sketch the rectangle that goes through the points \(3\) units to the left/righ...In the figure, we placed the hyperbola so the foci \(((−c,0),(c,0))\) are on the \(x\)-axis and the center is the origin. Sketch the rectangle that goes through the points \(3\) units to the left/right of the center and \(4\) units above and below the center. Sketch the rectangle that goes through the points \(3\) units to the left/right of the center and \(2\) units above and below the center. The midpoint of the segment joining the foci is called the center of the hyperbola.
- https://math.libretexts.org/Workbench/Intermediate_Algebra_2e_(OpenStax)/11%3A_Conics/11.05%3A_Hyperbolasⓐ 9 x 2 + 4 y 2 + 56 y + 160 = 0 9 x 2 + 4 y 2 + 56 y + 160 = 0 ⓑ 9 x 2 − 16 y 2 + 18 x + 64 y − 199 = 0 9 x 2 − 16 y 2 + 18 x + 64 y − 199 = 0 ⓒ x 2 + y 2 − 6 x − 8 y = 0 x 2 + y 2 − 6 x − 8 y = 0 ⓓ ...ⓐ 9 x 2 + 4 y 2 + 56 y + 160 = 0 9 x 2 + 4 y 2 + 56 y + 160 = 0 ⓑ 9 x 2 − 16 y 2 + 18 x + 64 y − 199 = 0 9 x 2 − 16 y 2 + 18 x + 64 y − 199 = 0 ⓒ x 2 + y 2 − 6 x − 8 y = 0 x 2 + y 2 − 6 x − 8 y = 0 ⓓ y = −2 x 2 − 4 x − 5 y = −2 x 2 − 4 x − 5 ⓐ x = − y 2 − 2 y + 3 x = − y 2 − 2 y + 3 ⓑ 9 y 2 − x 2 + 18 y − 4 x − 4 = 0 9 y 2 − x 2 + 18 y − 4 x − 4 = 0 ⓒ 9 x 2 + 25 y 2 = 225 9 x 2 + 25 y 2 = 225 ⓓ x 2 + y 2 − 4 x + 10 y − 7 = 0 x 2 + y 2 − 4 x + 10 y − 7 = 0
- https://math.libretexts.org/Courses/Mission_College/Math_C%3A_Intermediate_Algebra_(Carr)/08%3A_Conics/8.04%3A_HyperbolasIn the figure, we placed the hyperbola so the foci \(((−c,0),(c,0))\) are on the \(x\)-axis and the center is the origin. Sketch the rectangle that goes through the points \(3\) units to the left/righ...In the figure, we placed the hyperbola so the foci \(((−c,0),(c,0))\) are on the \(x\)-axis and the center is the origin. Sketch the rectangle that goes through the points \(3\) units to the left/right of the center and \(4\) units above and below the center. Sketch the rectangle that goes through the points \(3\) units to the left/right of the center and \(2\) units above and below the center. The midpoint of the segment joining the foci is called the center of the hyperbola.
