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6.1: Trigonometric Identities
https://math.libretexts.org/Courses/Coastline_College/Math_C280%3A_Calculus_III_(Tran)/06%3A_Appendices/6.01%3A_Trigonometric_Identities
$\cos^2 x + \sin^2 x = 1$ $\sec^2 x - \tan^2 x = 1$ $\sin 2x = 2 \sin x \cos x$ $\cos 2x = \cos^2 x - \sin^2 x = 1 - 2 \sin^2 x = 2 \cos^2 x - 1$ $\cos^2 x = \dfrac{1+ \cos 2x}{2}$ \(\sin^2 ... $\cos^2 x + \sin^2 x = 1$ $\sec^2 x - \tan^2 x = 1$ $\sin 2x = 2 \sin x \cos x$ $\cos 2x = \cos^2 x - \sin^2 x = 1 - 2 \sin^2 x = 2 \cos^2 x - 1$ $\cos^2 x = \dfrac{1+ \cos 2x}{2}$ $\sin^2 x = \dfrac{1- \cos 2x}{2}$ $\sin (-x) = -\sin x$ $\cos(-x) = \cos x$ $\tan (-x) = -\tan x$ $\sin\left(x \pm \frac{\pi}{2}\right) = \pm \cos x$ $\cos\left(x \pm \frac{\pi}{2}\right) = \mp \sin x$ $\sin(\pi - x) = \sin x$ $\cos(\pi - x) = -\cos x$ $\tan(\pi - x) = -\tan x$
6.1: Trigonometric Identities
https://math.libretexts.org/Courses/Coastline_College/Math_C280%3A_Calculus_III_(Everett)/06%3A_Appendices/6.01%3A_Trigonometric_Identities
$\cos^2 x + \sin^2 x = 1$ $\sec^2 x - \tan^2 x = 1$ $\sin 2x = 2 \sin x \cos x$ $\cos 2x = \cos^2 x - \sin^2 x = 1 - 2 \sin^2 x = 2 \cos^2 x - 1$ $\cos^2 x = \dfrac{1+ \cos 2x}{2}$ \(\sin^2 ... $\cos^2 x + \sin^2 x = 1$ $\sec^2 x - \tan^2 x = 1$ $\sin 2x = 2 \sin x \cos x$ $\cos 2x = \cos^2 x - \sin^2 x = 1 - 2 \sin^2 x = 2 \cos^2 x - 1$ $\cos^2 x = \dfrac{1+ \cos 2x}{2}$ $\sin^2 x = \dfrac{1- \cos 2x}{2}$ $\sin (-x) = -\sin x$ $\cos(-x) = \cos x$ $\tan (-x) = -\tan x$ $\sin\left(x \pm \frac{\pi}{2}\right) = \pm \cos x$ $\cos\left(x \pm \frac{\pi}{2}\right) = \mp \sin x$ $\sin(\pi - x) = \sin x$ $\cos(\pi - x) = -\cos x$ $\tan(\pi - x) = -\tan x$

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