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  • 2.6: Chain Rule
    https://math.libretexts.org/Courses/Butler_Community_College/MA148%3A_Calculus_with_Applications_-_Butler_CC/02%3A_The_Derivative/2.06%3A_Chain_Rule
    ddt(et(t−1))=(et)(t−1)+(et)(1) so \[ \frac{d}{dt}\left(\frac{3t^3}{e^t(t-1)}\right)=\frac{\left( 9t^2 \right)\left( e^t(t-1) \right)...ddt(et(t−1))=(et)(t−1)+(et)(1) so ddt(3t3et(t−1))=(9t2)(et(t−1))−(3t3)((et)(t−1)+(et)(1))(et(t−1))2 so \[\frac{dz}{dt}=\frac{d}{dt}\left(\frac{3t^3}{e^t(t-1)}\right)^4=4\left(\frac{3t^3}{e^t(t-1)}\right)^3\cdot \left( \frac{\left( 9t^2 \right)\left( e^t(t-1) \right)-\left( 3t^3 …
  • 1.6: Chain Rule
    https://math.libretexts.org/Courses/Prince_Georges_Community_College/MAT_2160%3A_Applied_Calculus_I/01%3A_The_Derivative/1.06%3A_Chain_Rule
    There is one more type of complicated function that we will want to know how to differentiate: composition. The Chain Rule will let us find the derivative of a composition.
  • 3.4: Chain Rule
    https://math.libretexts.org/Courses/Chabot_College/MTH_15%3A_Applied_Calculus_I/03%3A_The_Derivative/3.04%3A_Chain_Rule
    There is one more type of complicated function that we will want to know how to differentiate: composition. The Chain Rule will let us find the derivative of a composition.
  • 2.5: Chain Rule
    https://math.libretexts.org/Courses/Penn_State_University_Greater_Allegheny/MATH_110%3A_Techniques_of_Calculus_I_(Gaydos)/02%3A_The_Derivative/2.05%3A_Chain_Rule
    There is one more type of complicated function that we will want to know how to differentiate: composition. The Chain Rule will let us find the derivative of a composition.

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