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6: Moments and Centroids

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Mass and Slugs

Newton's Second Law states that

F=ma

where F is the force, m is the mass, and a is the acceleration. In the US system, Force is measured in pounds and mass is measures in slugs.

Example 6.1: Weight to Mass

I weigh 165 lbs. What is my mass?

Solution

Since weight corresponds with gravitational force, and the acceleration of gravity is 32 ft/sec2 we have

165=32m

or

m=5.15 slugs.

In the metric system, kg is a mass unit and Newtons is a weight unit.

Moments and Center of Mass for Discrete Mass Points

Suppose that we have a teeter totter and a 10 kg child is on the left 5 meters from the center of the teeter totter and a 15 kg child is on the right 4 meters from the center of the teeter totter. We define the moment as:

10(5)+15(4)=10.

In general, we define the moment for masses mi at the points xi to be

Moment=mixi.

If the moment is 0 then we say that the system is in equilibrium. Otherwise, let x be the value such that

mi(xix)=0.

Then x is called the center of mass of the system.

Theorem: center of mass

Tthe center of mass of the system is given by

x=momenttotal mass

Proof:

mi(xiˉx)=miximiˉx=mixiˉxmi

so that

x=mixi.

Example 6.2

Find the center of mass of the teeter totter.

Solution

We have

moment =10

and

total mass=25

hence the

center of mass=1025=0.4.

We can say that if the center of the teeter totter was 0.4 meters from the current center, then the children would be in balance.

For points in the plane, we can find moments and centers of mass coordinate wise. We define:

Definition: Moments

mx=moment about the x axis =Smixi,

my=moment about the y axis =Smiyi,

Center of Mass =(myM,mxm).

Example 6.3

For the points (3,0) with mass 4, (2,2) with mass 3, and (1,2) with mass 1 we have

mx=(4)(3)+(3)(2)+(1)(1)=5,

my=(4)(0)+(3)(2)+(1)(2)=8,

Center of Mass=(58,88)=(0.625,1).

Center of Mass for a Two Dimensional Plate

First, we recall that for a region of density r bounded by f(x) and g(x)

Mass=(Density)(Area)=ρba(f(x)g(x))dx

Mx=ρbaf(x)g(x)2(f(x)g(x))dx

My=ρbax(f(x)g(x))dx

and

Center of Mass=(MyM,MxM)

Example 6.4

Find the center of mass for the plate of constant density 2 that is bounded by the curves

y=1x, y=0 and x=0.

We have

Mx=2101x2(1x)dx,

My=210x(1x)dx,

M=210(1x)dx.

Pappus Theorem

Suppose that we revolve a region around the y-axis. Then the volume of revolution is:

V=2prA

where A is the area of the region and r is the distance from the centroid (constant density) to the axis of rotation.

Example 6.5

Suppose that we revolve the 4 x4 frame with width 1 centered about (6,2) about the y-axis. Then we have that the Area is

A=4+4+2+2=12.

R=7

so that

V=2p7(12)=168p.

Example 6.6

Find the volume of the torus formed by revolving the disk

(x11)2+y2=4

about the y-axis.

Contributors and Attributions


This page titled 6: Moments and Centroids is shared under a not declared license and was authored, remixed, and/or curated by Larry Green.

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