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16.4: Depth-first and breadth-first searches

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    83486
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    Let \(G\) be a graph. Given vertices \(v,v'\) of \(G\text{,}\) we might wish to find a path from \(v\) to \(v'\text{,}\) if one exists. We can do this by constructing a tree \(T \preceq G\text{.}\)

    Algorithm \(\PageIndex{1}\): Depth-first search.

    To create a tree \(T\) that is a subgraph of a graph \(G\) wherein a path (in \(G\)) from \(v\) to \(v'\) is evident, begin with \(T\) containing the single vertex \(v\) and no edges. Set \(x=v\text{.}\)

    1. Look for a vertex \(y\) of \(G\) which is adjacent to \(x\) but not already in \(T\text{.}\) If such a \(y\) is found, go to Step 2. Otherwise, go to Step 3.
    2. Adjoin \(y\) and a single edge between \(x\) and \(y\) to \(T\text{.}\) If \(y = v'\text{,}\) stop — a path from \(v\) to \(v'\) exists and is now contained in \(T\text{.}\) Otherwise, set \(x=y\) and return to Step 1.
    3. If you have arrived here immediately after beginning the algorithm (i.e. with \(x\) still set to be \(v\)), stop — there is no path from \(v\) to \(v'\text{.}\) Otherwise, return to the vertex \(z\) adjoined before \(x\text{.}\) Set \(x = z\) and return to Step 1.

    The depth-first search will not necessarily yield the shortest path from \(v\) to \(v'\text{.}\) The following algorithm will.

    Algorithm \(\PageIndex{2}\): Breadth-first search.

    To create a tree \(T\) that is a subgraph of a graph \(G\) wherein the shortest path in \(G\) from \(v\) to \(v'\) is evident, begin with \(T\) containing the single vertex \(v\) and no edges.

    1. For each vertex \(x\) in \(T\) added in the last application of this step (or, in the case of the first application of this step, for \(x = v\)), adjoin all vertices of \(G\) that are adjacent to \(x\) and not already in \(T\text{,}\) along with a single edge between each such vertex and \(x\text{.}\) If at least one vertex has been adjoined to \(T\) in this step, proceed to Step 2. Otherwise, stop — there is no path from \(v\) to \(v'\) in \(G\text{.}\)
    2. If \(v'\) was one of the vertices adjoined in Step 1, stop — a path from \(v\) to \(v'\) exists and is now contained in \(T\text{.}\) Otherwise, return to Step 1.

    This page titled 16.4: Depth-first and breadth-first searches is shared under a GNU Free Documentation License 1.3 license and was authored, remixed, and/or curated by Jeremy Sylvestre via source content that was edited to the style and standards of the LibreTexts platform.