1.11: Integration by Parts
- Page ID
- 90394
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Another integration technique makes use of the product rule for differentiation. Since \[(fg)'=f'g+fg',\nonumber\] we have \[f'g=(fg)'-fg'.\nonumber\]
Therefore, \[\int f'(x)g(x)dx=f(x)g(x)-\int f(x)g'(x)dx.\nonumber\]
Commonly, the above integral is done by writing \[\begin{array}{cc}u=g(x)&dv=f'(x)dx \\ du=g'(x)dx&v=f(x).\end{array}\nonumber\]
Then, the formula to be memorized is \[\int udv=uv-\int vdu.\nonumber\]