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A.7.1: Section 7.1 Answers

( \newcommand{\kernel}{\mathrm{null}\,}\)

1.

  1. R=2;I=(1,3)
  2. R=1/2;I=(3/2,5/2)
  3. R=0
  4. R=16;I=(14,18)
  5. R=;I=(,)
  6. R=4/3;I=(25/3,17/3)

3.

  1. R=1;I=(0,2)
  2. R=2;I=(22,2+2)
  3. R=;I=(,)
  4. R=0
  5. R=3;I=(3,3)
  6. R=1:I=(0,2)

5.

  1. R=3;I=(0,6)
  2. R=1;I=(1,1)
  3. R=1/3;I=(31/3,3+1/3)
  4. R=;I=(,)
  5. R=0
  6. R=2;I=(1,3)

11. bn=2(n+2)(n+1)an+2+(n+1)nan+1+(n+3)an

12. b0=2a22a0bn=(n+2)(n+1)an+2+[3n(n1)2]an+3(n1)an1,n1

13. bn=(n+2)(n+1)an+2+2(n+1)an+1+(2n25n+4)an

14. bn=(n+2)(n+1)an+2+2(n+1)an+1+(n22n+3)an

15. bn=(n+2)(n+1)an+2+(3n25n+4)an

16. b0=2a2+2a1+a0,bn=(n+2)(n+1)an+2+(n+1)(n+2)an+1+(2n+1)an+an1,n2

17. b0=8a2+4a16a0,bn=4(n+2)(n+1)an+2+4(n+1)2an+1+(n2+n6)an3an1,n1

21. b0=(r+1)(r+2)a0,bn=(n+r+1)(n+r+2)an(n+r2)2an1,n1.

22. b0=(r2)(r+2)a0,bn=(n+r2)(n+r+2)an+(n+r+2)(n+r3)an1,n14

23. b0=(r1)2a0,b1=r2a1+(r+2)(r+3)a0,bn=(n+r1)2an+(n+r+1)(n+r+2)an1+(n+r1)an2,n2

24. b0=r(r+1)a0,b1=(r+1)(r+2)a1+3(r+1)(r+2)a0,bn=(n+r)(n+r+1)an+3(n+r)(n+r+1)an1+(n+r)an2,n2

25. b0=(r+2)(r+1)a0,b1=(r+3)(r+2)a1,bn=(n+r+2)(n+r+1)an+2(n+r1)(n+r3)an2,n2

26. b0=2(r+1)(r+3)a0,b1=2(r+2)(r+4)a1,bn=2(n+r+1)(n+r+3)an+(n+r3)(n+r)an2,n2


This page titled A.7.1: Section 7.1 Answers is shared under a CC BY-NC-SA 3.0 license and was authored, remixed, and/or curated by William F. Trench.

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