Matrices
( \newcommand{\kernel}{\mathrm{null}\,}\)
1. Definition of a Matrix
Definition: Matrix
An m by n matrix is an array of numbers with m rows and n columns.
Example 1
\begin{pmatrix} 4&5\\0&15\\-9&3 \end{pmatrix}\nonumber
is a 3 by 2 matrix.
Example 2
Consider the system of equations
\begin{align} &2x &-y &&+3z&=5 \\ &x & &&+4z&=3 \\ &5x &-7y &&+3z&=7 \end{align}\nonumber
Then the matrix
\begin{pmatrix}\begin{array}{ccc|c}2&-1&3&5 \\1&0&4&3\\ 5&-7&3&7\end{array}\end{pmatrix}\nonumber
is called the augmented matrix associated to the system of equations. Two matrices are called equal if all of their entries are the same. Two matrices are called row equivalent is one can be transformed using a sequence of the three operations that we discussed earlier.
- Interchanging two rows.
- Multiplying a row by a nonzero constant.
- Replacing a row with the row + a constant multiple of another row.
2. Solving Linear Systems Using Matrices
We can solve a linear system by writing down its augmented matrix and performing the row operations that we did last time.
Example 3
Solve
\begin{align} &2x &-y &&+z&=3 \\ &x&+y&&+z&=2 \\ & &y&&-z&=-1 \end{align}\nonumber
Solution
We write the associated augmented matrix:
\begin{pmatrix}\begin{array}{ccc|c}2&-1&1&3 \\1&1&1&2 \\ 0&1&-1&-1\end{array}\end{pmatrix}\nonumber
Now begin solving by performing row operations:
R_1 \leftrightarrow R_2 \nonumber
\begin{pmatrix}\begin{array}{ccc|c}1&1&1&2 \\2&-1&1&3\\ 0&1&-1&-1\end{array}\end{pmatrix}\nonumber
R_1 \leftrightarrow R-2\nonumber
\begin{pmatrix}\begin{array}{ccc|c}1&1&1&2 \\0&3&-1&-1\\ 0&1&-1&-1\end{array}\end{pmatrix}\nonumber
R_2 \leftrightarrow R_3\nonumber
\begin{pmatrix}\begin{array}{ccc|c}1&1&1&2 \\0&1&-1&-1\\ 0&3&-1&-1\end{array}\end{pmatrix} \nonumber
R_1 - R_2 \rightarrow R_1, \;\; R_3 + 3R_2 \rightarrow R_3\nonumber
\begin{pmatrix}\begin{array}{ccc|c}1&1&1&2 \\0&1&-1&-1\\ 0&3&-1&-1\end{array}\end{pmatrix}\nonumber
R_1 - R_2 \rightarrow R_1, \;\; R_3 + 3R_2 \rightarrow R_3 \nonumber
\begin{pmatrix}\begin{array}{ccc|c}1&0&2&3 \\0&1&-1&-1\\ 0&0&-4&-4\end{array}\end{pmatrix}\nonumber
R_3 \rightarrow -\dfrac{1}{4} R_3\nonumber
\begin{pmatrix}\begin{array}{ccc|c}1&0&2&3 \\0&1&-1&-1\\ 0&0&1&1\end{array}\end{pmatrix}\nonumber
R_1 - 2R_3 \rightarrow R_1, \;\; R_2 + R_3 \rightarrow R_2\nonumber
\begin{pmatrix}\begin{array}{ccc|c}1&0&0&1 \\0&1&1&0\\ 0&0&1&1\end{array}\end{pmatrix}\nonumber
R_1 - 2R_3 - \rightarrow +R_1, \;\;R_2 + R_3 \rightarrow R_2\nonumber
\begin{pmatrix}\begin{array}{ccc|c}1&0&0&1 \\0&1&0&0\\ 0&0&1&1\end{array}\end{pmatrix}\nonumber
We can now put the matrix back in equation form:x = 1, y = 0 \text{ and } z = 1\nonumber
Note
If we had seen a bottom row that was of the form 0 \; 0 \; 0 \; a where a is a nonzero constant, then there would be no solution. If a had been 0 there would be infinitely many solutions.
3. Addition and Scalar Multiplication of Matrices
We can only add matrices that are of the same dimensions, that is if
A=\begin{pmatrix} 1&2\\3&4 \end{pmatrix}, \;\;\; B=\begin{pmatrix} 2&3\\4&1\\5&9 \end{pmatrix}, \;\;\; C=\begin{pmatrix} 1&3\\7&2 \end{pmatrix}\nonumber
then only A + C makes sense. We write
A+C=\begin{pmatrix} 1+1&2+3\\3+7&4+2\end{pmatrix}=\begin{pmatrix} 2&5\\10&6\end{pmatrix} \nonumber
For any matrix, we can multiply a matrix by a real number as in the following example (Same B as above):
5B=\begin{pmatrix} 10&15\\20&5\\25&45 \end{pmatrix}\nonumber
We define the zero matrix to be the matrix with only zeros for entries. For example, the 2 by 2 zero matrix is
\begin{pmatrix} 0&0\\0&0 \end{pmatrix}\nonumber
4. Multiplication of Matrices
To multiply matrices, unfortunately the definition is not the obvious one. We can only multiply matrices where the number of columns of the first matrix is the same as the number of rows of the second matrix. The best way to learn how to multiply matrices is by example:
\text{Let}\; A=\begin{pmatrix} 3&5&2\\0&1&-2 \end{pmatrix}, \;\; \text{and}\; B=\begin{pmatrix} 7&-3\\-2&1\\0&5 \end{pmatrix}\nonumber
\text{then}\;AB=\begin{pmatrix} 3(7)+4(-2)+2(0)&3(-3)+4(1)+2(5)\\0(7)+1(-2)+-2(5) &0(-3)+1(1)+-2(5) \end{pmatrix}=\begin{pmatrix} 13&5\\-12&-9 \end{pmatrix}\nonumber
Exercise
\text{Let}\;A=\begin{pmatrix} 1&2\\3&4 \end{pmatrix}, \;\;\; B=\begin{pmatrix} 4&2&1\\-2&0&0\\1&6&-1 \end{pmatrix}, \;\;\; C=\begin{pmatrix} 1&0\\2&1\\4&5 \end{pmatrix}, \;\;\; D=\begin{pmatrix} 3&4&0\\5&0&0\end{pmatrix},\;\;\; B=\begin{pmatrix} 3&4&2\\1&5&0\\1&-1&2\end{pmatrix}\nonumber
Evaluate each one that makes sense:
1) A + B 2) 4C 3) AB 4) CD 5) DC 6) B + E 7) A^3
5. Applications of Matrices
Application 1
A) Tables and chairs are made in the Mexico plant, the Brazil plant, and the US plant. The matrix below represents the quantity made per day.
A: |
|
Labor and material cost for 1997 are represented in the following matrix.
B = |
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In 1997, the costs have increases to
C = |
|
Find the following and describe what they mean:
1) AB 2) C - B 3) AC 4) A(C - B) 5) 365AC
Application 2
Suppose that you have two jobs, each contribute to two different mutual funds for retirement. The first fund pays 5% interest and the second pays 8% interest. Initially $5,000 is put into the funds and after one year there will be $5,300. If the first fund got half of the money from the first job and one third of the money from the second job, how much did each job contribute?
Hint: Multiplication of matrices is the same as composition of functions
Larry Green (Lake Tahoe Community College)
Integrated by Justin Marshall.