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10.R: Analytic Geometry (Review)

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10.1: The Ellipse

In this section, we will investigate the shape of this room and its real-world applications, including how far apart two people in Statuary Hall can stand and still hear each other whisper.

For the exercises 1-4, write the equation of the ellipse in standard form. Then identify the center, vertices, and foci.

1) x225+y264=1

Answer

x252+y282=1; center: (0,0); Vertices: (5,0), (5,0), (0,8), (0,8); foci: (0,39), (0,39)

2) (x2)2100+(y+3)236=1

3) 9x2+y2+54x4y+76=0

Answer

(x+3)212+(y2)232=1; center: (3,2); Vertices: (2,2), (4,2), (3,5), (3,1); foci: (3,2+22), (3,222)

4) 9x2+36y236x+72y+36=0

For the exercises 5-8, graph the ellipse, noting center, vertices, and foci.

5) x236+y29=1

Answer

center: (0,0); Vertices: (6,0, (6,0), (0,3), (0,3); foci: (33,0), (33,0)

R10.1.5.png

6) (x4)225+(y+3)249=1

7) 4x2+y2+16x+4y44=0

Answer

center: (2,2); Vertices: (2,2), (6,2), (2,6), (2,10); foci: (2,2+43), (2,243)

R10.1.7.png

8) 2x2+3y220x+12y+38=0

For the exercises 9-11, use the given information to find the equation for the ellipse.

9) Center at (0,0), focus at (3,0), vertex at (5,0)

Answer

x225+y216=1

10) Center at (2,2), vertex at (7,2), focus at (4,2)

11) A whispering gallery is to be constructed such that the foci are located 35 feet from the center. If the length of the gallery is to be 100 feet, what should the height of the ceiling be?

Answer

Approximately 35.71 feet

10.2: The Hyperbola

In analytic geometry, a hyperbola is a conic section formed by intersecting a right circular cone with a plane at an angle such that both halves of the cone are intersected. This intersection produces two separate unbounded curves that are mirror images of each other.

For the exercises 1-4, write the equation of the hyperbola in standard form. Then give the center, vertices, and foci.

1) x281y29=1

2) (y+1)216(x4)236=1

Answer

(y+1)242(x4)262=1; center: (4,1); Vertices: (4,3), (4,5); foci: (4,1+213), (4,1213)

3) 9y24x2+54y16x+29=0

4) 3x2y212x6y9=0

Answer

(x2)222(y+3)2(23)2=1; center: (2,3); Vertices: (4,3), (0,3); foci: (6,3), (2,3)

For the exercises 5-8, graph the hyperbola, labeling vertices and foci.

5) x29y216=1

6) (y1)249(x+1)24=1

Answer

R10.2.6.png

7) x24y2+6x+32y91=0

8) 2y2x212y6=0

Answer

R10.2.8.png

For the exercises 9-10, find the equation of the hyperbola.

9) Center at (0,0), vertex at (0,4), focus at (0,6)

10) Foci at (3,7) and (7,7), vertex at (6,7

Answer

(x5)21(y7)23=1

10.3: The Parabola

Like the ellipse and hyperbola, the parabola can also be defined by a set of points in the coordinate plane. A parabola is the set of all points in a plane that are the same distance from a fixed line, called the directrix, and a fixed point (the focus) not on the directrix.

For the exercises 1-4, write the equation of the parabola in standard form. Then give the vertex, focus, and directrix.

1) y2=12x

2) (x+2)2=12(y1)

Answer

(x+2)2=12(y1); vertex: (2,1); focus: (2,98); directrix: y=78

3) y26y6x3=0

4) x2+10xy+23=0

Answer

(x+5)2=(y+2); vertex: (5,2); focus: (5,74); directrix: y=94

For the exercises 5-8, graph the parabola, labeling vertex, focus, and directrix.

5) x2+4y=0

6) (y1)2=12(x+3)

Answer

R10.3.6.png

7) x28x10y+46=0

8) 2y2+12y+6x+15=0

Answer

R10.3.8.png

For the exercises 9-11, write the equation of the parabola using the given information.

9) Focus at (4,0); directrix is x=4

10) Focus at (2,98); directrix is y=78

Answer

(x2)2=(12)(y1)

11) A cable TV receiving dish is the shape of a paraboloid of revolution. Find the location of the receiver, which is placed at the focus, if the dish is 5 feet across at its opening and 1.5 feet deep.

10.4: Rotation of Axes

In previous sections of this chapter, we have focused on the standard form equations for nondegenerate conic sections. In this section, we will shift our focus to the general form equation, which can be used for any conic. The general form is set equal to zero, and the terms and coefficients are given in a particular order, as shown below.

For the exercises 1-3, determine which of the conic sections is represented.

1) 16x2+24xy+9y2+24x60y60=0

Answer

B24AC=0, parabola

2) 4x2+14xy+5y2+18x6y+30=0

3) 4x2+xy+2y2+8x26y+9=0

Answer

B24AC=31<0, ellipse

For the exercises 4-5, determine the angle θ that will eliminate the xy term, and write the corresponding equation without the xy term.

4) x2+4xy2y26=0

5) x2xy+y26=0

Answer

θ=45,x2+3y212=0

For the exercises 6-8, graph the equation relative to the xy system in which the equation has no xy term.

6) 9x224xy+16y280x60y+100=0

7) x2xy+y22=0

Answer

θ=45

R10.4.7.png

8) 6x2+24xyy212x+26y+11=0

10.5: Conic Sections in Polar Coordinates

In this section, we will learn how to define any conic in the polar coordinate system in terms of a fixed point, the focus at the pole, and a line, the directrix, which is perpendicular to the polar axis.

For the exercises 1-4, given the polar equation of the conic with focus at the origin, identify the eccentricity and directrix.

1) r=1015cosθ

Answer

Hyperbola with e=5 and directrix 2 units to the left of the pole.

2) r=63+2cosθ

3) r=14+3sinθ

Answer

Ellipse with e=34 and directrix 13 unit above the pole.

4) r=355sinθ

For the exercises 5-8, graph the conic given in polar form. If it is a parabola, label the vertex, focus, and directrix. If it is an ellipse or a hyperbola, label the vertices and foci.

5) r=31sinθ

Answer

R10.5.5.png

6) r=84+3sinθ

7) r=104+5cosθ

Answer

R10.5.7.png

8) r=936cosθ

For the exercises 9-10, given information about the graph of a conic with focus at the origin, find the equation in polar form.

9) Directrix is x=3 and eccentricity e=1

Answer

r=31+cosθ

10) Directrix is y=2 and eccentricity e=4

Practice Test

For the exercises 1-2, write the equation in standard form and state the center, vertices, and foci.

1) x29+y24=1

Answer

x232+y222=1; center: (0,0); vertices: (3,0), (3,0), (0,2), (0,2); foci: (5,0), (5,0)

2) 9y2+16x236y+32x92=0

For the exercises 3-6, sketch the graph, identifying the center, vertices, and foci.

3) (x3)264+(y2)236=1

Answer

center: (3,2); vertices: (11,2), (5,2), (3,8), (3,4); foci: (3+27,2), (327,2)

RP3.png

4) 2x2+y2+8x6y7=0

5) Write the standard form equation of an ellipse with a center at (1,2), vertex at (7,2), and focus at (4,2).

Answer

(x1)236+(y2)227=1

6) A whispering gallery is to be constructed with a length of 150 feet. If the foci are to be located 20 feet away from the wall, how high should the ceiling be?

For the exercises 7-8, write the equation of the hyperbola in standard form, and give the center, vertices, foci, and asymptotes.

7) x249y281=1

Answer

x272y292=1; center: (0,0); vertices: (7,0), (7,0); foci: (130,0), (130,0); asymptotes: y=±97x

8) 16y29x2+128y+112=0

For the exercises 9-11, graph the hyperbola, noting its center, vertices, and foci. State the equations of the asymptotes.

9) (x3)225(y+3)21=1

Answer

center: (3,3); vertices: (8,3), (2,3); foci: (3+26,3), (326,3); asymptotes: y=±15(x3)3

RP9.png

10) y2x2+4y4x18=0

11) Write the standard form equation of a hyperbola with foci at (1,0), and (1,6), and a vertex at (1,2).

Answer

(y3)21(x1)28=1

For the exercises 12-13, write the equation of the parabola in standard form, and give the vertex, focus, and equation of the directrix.

12) y2+10x=0

13) 3x212xy+11=0

Answer

(x2)2=13(y+1); vertex: (2,1); focus: (2,1112); directrix: y=1312

For the exercises 14-17, graph the parabola, labeling the vertex, focus, and directrix.

14) (x1)2=4(y+3)

15) y2+8x8y+40=0

Answer

RP15.png

16) Write the equation of a parabola with a focus at (2,3) and directrix y=1.

17) A searchlight is shaped like a paraboloid of revolution. If the light source is located 1.5 feet from the base along the axis of symmetry, and the depth of the searchlight is 3 feet, what should the width of the opening be?

Answer

Approximately 8.49 feet

For the exercises 18-19, determine which conic section is represented by the given equation, and then determine the angle θ that will eliminate the xy term.

18) 3x22xy+3y2=4

19) x2+4xy+4y2+6x8y=0

Answer

parabola; θ63.4

For the exercises 20-21, rewrite in the xy system without the xy term, and graph the rotated graph.

20) 11x2+103xy+y2=4

21) 16x2+24xy+9y2125x=0

Answer

x24x+3y=0

RP21.png

For the exercises 22-23, identify the conic with focus at the origin, and then give the directrix and eccentricity.

22) r=32sinθ

23) r=54+6cosθ

Answer

Hyperbola with e=32 and directrix 56 units to the right of the pole.

For the exercises 24-26, graph the given conic section. If it is a parabola, label vertex, focus, and directrix. If it is an ellipse or a hyperbola, label vertices and foci.

24) r=1248sinθ

25) r=24+4sinθ

Answer

RP25.png

26) Find a polar equation of the conic with focus at the origin, eccentricity of e=2, and directrix: x=3.

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This page titled 10.R: Analytic Geometry (Review) is shared under a CC BY 4.0 license and was authored, remixed, and/or curated by OpenStax.

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