1.2: The primary Bulbs counting
- Page ID
- 101024
\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\)
One can obtain m/n rotation number for the largest bulb between the 1/2 and 1/3 bulbs (note that they are both larger then our new bulb) by adding the numerators and adding the denominators (Farey addition rule)
2/5 = 1/2 + 1/3
Explore the picture to test bulbs rotating numbers m/n.
So we get next primary bulbs sequences:
1/2 + 1/3 = 2/5 + 1/2 = 3/7 + 1/2 = 4/9 +... and
1/2 + 1/3 = 2/5 + 1/3 = 3/8 + 1/3 = 4/11 +....
And at last 1/n sequence!
1/2 + 0/1 = 1/3 + 0/1 = 1/4 + 0/1 = ... = 1/n