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1.2: The primary Bulbs counting

  • Page ID
    101024
    • Robert L. Devaney
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    One can obtain m/n rotation number for the largest bulb between the 1/2 and 1/3 bulbs (note that they are both larger then our new bulb) by adding the numerators and adding the denominators (Farey addition rule)

    2/5 = 1/2 + 1/3

    1.2.1.png
    Figure \(\PageIndex{1}\): -0.5500  0.5000  1.5000   207ms

    Explore the picture to test bulbs rotating numbers m/n.

    So we get next primary bulbs sequences:

        1/2 + 1/3 = 2/5 + 1/2 = 3/7 + 1/2 = 4/9 +... and
        1/2 + 1/3 = 2/5 + 1/3 = 3/8 + 1/3 = 4/11 +....

    And at last 1/n sequence!

        1/2 + 0/1 = 1/3 + 0/1 = 1/4 + 0/1 = ... = 1/n

    1.2.2.jpg
    Figure \(\PageIndex{2}\): 0.0000  0.0000  3.0000   759ms  "quadratic" parametrization

     

     

     

     

     

     

     

     


    This page titled 1.2: The primary Bulbs counting is shared under a Public Domain license and was authored, remixed, and/or curated by Robert L. Devaney via source content that was edited to the style and standards of the LibreTexts platform; a detailed edit history is available upon request.