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4.4: Attracting Fixed point and Period 2 orbit

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    101795
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    The main cardioid equation

    There are always two fixed points   z = f(z)   for a quadratic map

        f(z) - z = z2 + c - z = 0,   (1)

        z1,2 = 1/2 ∓ (1/4 - c)½.      (2)

    4.4.1.png
    Figure \(\PageIndex{1}\)

    A fixed point with multiplier λ = f '(z) = 2z is attracting if

        |λ| < 1,     |z| < 1/2,

    i.e. z lies inside the u = ½ exp(iφ) circle. The multiplier on the circle is

        λ = exp(iφ).     (3)

    It follows from (1) that c = z - z2 and corresponding c lies inside the cardioid

        c = u - u2 = ½ exp(iφ) - ¼ exp(2iφ),

        Re(c) = ½ cos(φ) - ¼ cos(2φ),

        Im(c) = ½ sin(φ) - ¼ sin(2φ).

    The M-set in the "quadratic" parametrization

    4.4.2.png
    Figure \(\PageIndex{2}\)

    We get one more useful "quadratic" parametrization if we use

        c = 1/4 - a2.     (4)

    As since a2 = (-a)2 the M is symmetric with respect to a = 0. After substitution of (4) into (2) we get:

        z = 1/2 ± a.

    z is attracting if |1/2 ± a| < 1/2, i.e. a lies inside one of the circles

        ½ e ± 1/2 .

    So the (4) transformation converts the main cardioid in two circles.

    Internal angles theory

    4.4.3.png
    Figure \(\PageIndex{3}\)

    From (3) it follows that if a fixed point lies at the u = ½ exp(i2πm/n) value then under iterations its neighbourhood is rotated by the φ = 2πm/n "internal angle". On the main cardioid the corresponding point lies near the m/n bulb at

        cφ = ½ e - ¼ e2iφ .

    In the "quadratic" parametrization

        aφ = ½ e - 1/2 .

    Therefore aφ lays on the r = 1/2 circle at the angle φ with respect to the real axis.

    Period 2 orbit

    The equation for the period 2 orbit zo = f o2(zo ) = f(f(zo )) is

        (zo2 + c)2 + c - zo = (zo2 + c - zo )(zo2 + zo + c + 1) = 0.

    The roots of the first factor are the two fixed points z1,2 . They are repelling outside the main cardioid. The second factor has two roots

        z3,4 = -1/2 ± (-3/4 - c)½.

    These two roots form period-2 orbit. Since z3 z4 = c + 1 the multiplier of the orbit is

        λ = f '(z3 ) f '(z4 ) = 4z3 z4 = 4(c + 1).

    Therefore the orbit is attracting while |c + 1| < 1/4 or c lies within the ¼ exp(iφ) - 1 circle. This is exactly equation of the biggest 1/2 bulb to the left of the main cardioid.

    I.e. the main cardioid and the 1/2 bulb are connected and touch each other in one point z = -3/4.

    4.4.4.png
    Figure \(\PageIndex{4}\)

    You see the points z1-4 positions for c = -0.71+0.1i (inside the main cardioid). Two roots z3 , z4 are symmetrical with respect to the point z = -1/2.

    Repeller z2 lies in Julia set. Is it "very often" the extreme right point for connected Js ("very often" because it is not true e.g. for "cauliflower").

     

     

     


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