11.4E: Exercises
- Page ID
- 120676
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Exercises
In Exercises 1 - 16, plot the point given in polar coordinates and then give three different expressions for the point such that
- \(r<0 \text { and } 0 \leq \theta \leq 2 \pi,\)
- \(r>0 \text { and } \theta \leq 0\)
- \(r>0 \text { and } \theta \geq 2 \pi\)
- \(\left(2, \frac{\pi}{3}\right)\)
- \(\left(5, \frac{7 \pi}{4}\right)\)
- \(\left(\frac{1}{3}, \frac{3 \pi}{2}\right)\)
- \(\left(\frac{5}{2}, \frac{5 \pi}{6}\right)\)
- \(\left(12,-\frac{7 \pi}{6}\right)\)
- \(\left(3,-\frac{5 \pi}{4}\right)\)
- \((2 \sqrt{2},-\pi)\)
- \(\left(\frac{7}{2},-\frac{13 \pi}{6}\right)\)
- \((-20,3 \pi)\)
- \(\left(-4, \frac{5 \pi}{4}\right)\)
- \(\left(-1, \frac{2 \pi}{3}\right)\)
- \(\left(-3, \frac{\pi}{2}\right)\)
- \(\left(-3,-\frac{11 \pi}{6}\right)\)
- \(\left(-2.5,-\frac{\pi}{4}\right)\)
- \(\left(-\sqrt{5},-\frac{4 \pi}{3}\right)\)
- \((-\pi,-\pi)\)
In Exercises 17 - 36, convert the point from polar coordinates into rectangular coordinates.
- \(\left(5, \frac{7 \pi}{4}\right)\)
- \(\left(2, \frac{\pi}{3}\right)\)
- \(\left(11,-\frac{7 \pi}{6}\right)\)
- \((-20,3 \pi)\)
- \(\left(\frac{3}{5}, \frac{\pi}{2}\right)\)
- \(\left(-4, \frac{5 \pi}{6}\right)\)
- \(\left(9, \frac{7 \pi}{2}\right)\)
- \(\left(-5,-\frac{9 \pi}{4}\right)\)
- \(\left(42, \frac{13 \pi}{6}\right)\)
- \((-117,117 \pi)\)
- \((6, \arctan (2))\)
- \((10, \arctan (3))\)
- \(\left(-3, \arctan \left(\frac{4}{3}\right)\right)\)
- \(\left(5, \arctan \left(-\frac{4}{3}\right)\right)\)
- \(\left(2, \pi-\arctan \left(\frac{1}{2}\right)\right)\)
- \(\left(-\frac{1}{2}, \pi-\arctan (5)\right)\)
- \(\left(-1, \pi+\arctan \left(\frac{3}{4}\right)\right)\)
- \(\left(\frac{2}{3}, \pi+\arctan (2 \sqrt{2})\right)\)
- \((\pi, \arctan (\pi))\)
- \(\left(13, \arctan \left(\frac{12}{5}\right)\right)\)
In Exercises 37 - 56, convert the point from rectangular coordinates into polar coordinates with \(r \geq 0\) and \(0 \leq \theta<2 \pi\).
- \((0,5)\)
- \((3, \sqrt{3})\)
- \((7,-7)\)
- \((-3,-\sqrt{3})\)
- \((-3,0)\)
- \((-\sqrt{2}, \sqrt{2})\)
- \((-4,-4 \sqrt{3})\)
- \(\left(\frac{\sqrt{3}}{4},-\frac{1}{4}\right)\)
- \(\left(-\frac{3}{10},-\frac{3 \sqrt{3}}{10}\right)\)
- \((-\sqrt{5},-\sqrt{5})\)
- \((6,8)\)
- \((\sqrt{5}, 2 \sqrt{5})\)
- \((-8,1)\)
- \((-2 \sqrt{10}, 6 \sqrt{10})\)
- \((-5,-12)\)
- \(\left(-\frac{\sqrt{5}}{15},-\frac{2 \sqrt{5}}{15}\right)\)
- \((24,-7)\)
- \((12,-9)\)
- \(\left(\frac{\sqrt{2}}{4}, \frac{\sqrt{6}}{4}\right)\)
- \(\left(-\frac{\sqrt{65}}{5}, \frac{2 \sqrt{65}}{5}\right)\)
In Exercises 57 - 76, convert the equation from rectangular coordinates into polar coordinates. Solve for \(r\) in all but #60 through #63. In Exercises 60 - 63, you need to solve for \(\theta\)
- \(x = 6\)
- \(x = −3\)
- \(y = 7\)
- \(y = 0\)
- \(y = −x\)
- \(y=x \sqrt{3}\)
- \(y = 2x\)
- \(x^{2}+y^{2}=25\)
- \(x^{2}+y^{2}=117\)
- \(y = 4x − 19\)
- \(x = 3y + 1\)
- \(y=-3 x^{2}\)
- \(4 x=y^{2}\)
- \(x^{2}+y^{2}-2 y=0\)
- \(x^{2}-4 x+y^{2}=0\)
- \(x^{2}+y^{2}=x\)
- \(y^{2}=7 y-x^{2}\)
- \((x+2)^{2}+y^{2}=4\)
- \(x^{2}+(y-3)^{2}=9\)
- \(4 x^{2}+4\left(y-\frac{1}{2}\right)^{2}=1\)
In Exercises 77 - 96, convert the equation from polar coordinates into rectangular coordinates.
- \(r = 7\)
- \(r = −3\)
- \(r=\sqrt{2}\)
- \(\theta=\frac{\pi}{4}\)
- \(\theta=\frac{2 \pi}{3}\)
- \(\theta=\pi\)
- \(\theta=\frac{3 \pi}{2}\)
- \(r=4 \cos (\theta)\)
- \(5 r=\cos (\theta)\)
- \(r=3 \sin (\theta)\)
- \(r=-2 \sin (\theta)\)
- \(r=7 \sec (\theta)\)
- \(12 r=\csc (\theta)\)
- \(r=-2 \sec (\theta)\)
- \(r=-\sqrt{5} \csc (\theta)\)
- \(r=2 \sec (\theta) \tan (\theta)\)
- \(r=-\csc (\theta) \cot (\theta)\)
- \(r^{2}=\sin (2 \theta)\)
- \(r=1-2 \cos (\theta)\)
- \(r=1+\sin (\theta)\)
- Convert the origin (0, 0) into polar coordinates in four different ways.
- With the help of your classmates, use the Law of Cosines to develop a formula for the distance between two points in polar coordinates.
Answers
-
\(\begin{aligned}
&\left(2, \frac{\pi}{3}\right),\left(-2, \frac{4 \pi}{3}\right) \\
&\left(2,-\frac{5 \pi}{3}\right),\left(2, \frac{7 \pi}{3}\right)
\end{aligned}\) -
\(\begin{aligned}
&\left(5, \frac{7 \pi}{4}\right),\left(-5, \frac{3 \pi}{4}\right) \\
&\left(5,-\frac{\pi}{4}\right),\left(5, \frac{15 \pi}{4}\right)
\end{aligned}\) -
\(\begin{aligned}
&\left(\frac{1}{3}, \frac{3 \pi}{2}\right),\left(-\frac{1}{3}, \frac{\pi}{2}\right) \\
&\left(\frac{1}{3},-\frac{\pi}{2}\right),\left(\frac{1}{3}, \frac{7 \pi}{2}\right)
\end{aligned}\) -
\(\begin{aligned}
&\left(\frac{5}{2}, \frac{5 \pi}{6}\right),\left(-\frac{5}{2}, \frac{11 \pi}{6}\right) \\
&\left(\frac{5}{2},-\frac{7 \pi}{6}\right),\left(\frac{5}{2}, \frac{17 \pi}{6}\right)
\end{aligned}\) -
\(\begin{aligned}
&\left(12,-\frac{7 \pi}{6}\right),\left(-12, \frac{11 \pi}{6}\right) \\
&\left(12,-\frac{19 \pi}{6}\right),\left(12, \frac{17 \pi}{6}\right)
\end{aligned}\) -
\(\begin{aligned}
&\left(3,-\frac{5 \pi}{4}\right),\left(-3, \frac{7 \pi}{4}\right) \\
&\left(3,-\frac{13 \pi}{4}\right),\left(3, \frac{11 \pi}{4}\right)
\end{aligned}\) -
\(\begin{aligned}
&(2 \sqrt{2},-\pi),(-2 \sqrt{2}, 0) \\
&(2 \sqrt{2},-3 \pi),(2 \sqrt{2}, 3 \pi)
\end{aligned}\) -
\(\begin{aligned}
&\left(\frac{7}{2},-\frac{13 \pi}{6}\right),\left(-\frac{7}{2}, \frac{5 \pi}{6}\right) \\
&\left(\frac{7}{2},-\frac{\pi}{6}\right),\left(\frac{7}{2}, \frac{23 \pi}{6}\right)
\end{aligned}\) -
\(\begin{aligned}
&(-20,3 \pi),(-20, \pi) \\
&(20,-2 \pi),(20,4 \pi)
\end{aligned}\) -
\(\begin{aligned}
&\left(-4, \frac{5 \pi}{4}\right),\left(-4, \frac{13 \pi}{4}\right) \\
&\left(4,-\frac{7 \pi}{4}\right),\left(4, \frac{9 \pi}{4}\right)
\end{aligned}\) -
\(\begin{aligned}
&\left(-1, \frac{2 \pi}{3}\right),\left(-1, \frac{8 \pi}{3}\right) \\
&\left(1,-\frac{\pi}{3}\right),\left(1, \frac{11 \pi}{3}\right)
\end{aligned}\) -
\(\begin{aligned}
&\left(-3, \frac{\pi}{2}\right),\left(-3, \frac{5 \pi}{2}\right) \\
&\left(3,-\frac{\pi}{2}\right),\left(3, \frac{7 \pi}{2}\right)
\end{aligned}\) -
\(\begin{aligned}
&\left(-3,-\frac{11 \pi}{6}\right),\left(-3, \frac{\pi}{6}\right) \\
&\left(3,-\frac{5 \pi}{6}\right),\left(3, \frac{19 \pi}{6}\right)
\end{aligned}\) -
\(\begin{aligned}
&\left(-2.5,-\frac{\pi}{4}\right),\left(-2.5, \frac{7 \pi}{4}\right) \\
&\left(2.5,-\frac{5 \pi}{4}\right),\left(2.5, \frac{11 \pi}{4}\right)
\end{aligned}\) -
\(\begin{aligned}
&\left(-\sqrt{5},-\frac{4 \pi}{3}\right),\left(-\sqrt{5}, \frac{2 \pi}{3}\right) \\
&\left(\sqrt{5},-\frac{\pi}{3}\right),\left(\sqrt{5}, \frac{11 \pi}{3}\right)
\end{aligned}\) -
\(\begin{aligned}
&(-\pi,-\pi),(-\pi, \pi) \\
&(\pi,-2 \pi),(\pi, 2 \pi)
\end{aligned}\) - \(\left(\frac{5 \sqrt{2}}{2},-\frac{5 \sqrt{2}}{2}\right)\)
- \((1, \sqrt{3})\)
- \(\left(-\frac{11 \sqrt{3}}{2}, \frac{11}{2}\right)\)
- \((20, 0)\)
- \(\left(0, \frac{3}{5}\right)\)
- \((2 \sqrt{3},-2)\)
- \((0, −9)\)
- \(\left(-\frac{5 \sqrt{2}}{2}, \frac{5 \sqrt{2}}{2}\right)\)
- \((21 \sqrt{3}, 21)\)
- \((117,0)\)
- \(\left(\frac{6 \sqrt{5}}{5}, \frac{12 \sqrt{5}}{5}\right)\)
- \((\sqrt{10}, 3 \sqrt{10})\)
- \(\left(-\frac{9}{5},-\frac{12}{5}\right)\)
- \((3,-4)\)
- \(\left(-\frac{4 \sqrt{5}}{5}, \frac{2 \sqrt{5}}{5}\right)\)
- \(\left(\frac{\sqrt{26}}{52},-\frac{5 \sqrt{26}}{52}\right)\)
- \(\left(\frac{4}{5}, \frac{3}{5}\right)\)
- \(\left(-\frac{2}{9},-\frac{4 \sqrt{2}}{9}\right)\)
- \(\left(\frac{\pi}{\sqrt{1+\pi^{2}}}, \frac{\pi^{2}}{\sqrt{1+\pi^{2}}}\right)\)
- \((5,12)\)
- \(\left(5, \frac{\pi}{2}\right)\)
- \(\left(2 \sqrt{3}, \frac{\pi}{6}\right)\)
- \(\left(7 \sqrt{2}, \frac{7 \pi}{4}\right)\)
- \(\left(2 \sqrt{3}, \frac{7 \pi}{6}\right)\)
- \((3, \pi)\)
- \(\left(2, \frac{3 \pi}{4}\right)\)
- \(\left(8, \frac{4 \pi}{3}\right)\)
- \(\left(\frac{1}{2}, \frac{11 \pi}{6}\right)\)
- \(\left(\frac{3}{5}, \frac{4 \pi}{3}\right)\)
- \(\left(\sqrt{10}, \frac{5 \pi}{4}\right)\)
- \(\left(10, \arctan \left(\frac{4}{3}\right)\right)\)
- \((5, \arctan (2))\)
- \(\left(\sqrt{65}, \pi-\arctan \left(\frac{1}{8}\right)\right)\)
- \((20, \pi-\arctan (3))\)
- \(\left(13, \pi+\arctan \left(\frac{12}{5}\right)\right)\)
- \(\left(\frac{1}{3}, \pi+\arctan (2)\right)\)
- \(\left(25,2 \pi-\arctan \left(\frac{7}{24}\right)\right)\)
- \(\left(15,2 \pi-\arctan \left(\frac{3}{4}\right)\right)\)
- \(\left(\frac{\sqrt{2}}{2}, \frac{\pi}{3}\right)\)
- \((\sqrt{13}, \pi-\arctan (2))\)
- \(r=6 \sec (\theta)\)
- \(r=-3 \sec (\theta)\)
- \(r=7 \csc (\theta)\)
- \(\theta=0\)
- \(\theta=\frac{3 \pi}{4}\)
- \(\theta=\frac{\pi}{3}\)
- \(\theta=\arctan (2)\)
- \(r=5\)
- \(r=\sqrt{117}\)
- \(r=\frac{19}{4 \cos (\theta)-\sin (\theta)}\)
- \(x=\frac{1}{\cos (\theta)-3 \sin (\theta)}\)
- \(r=\frac{-\sec (\theta) \tan (\theta)}{3}\)
- \(r=4 \csc (\theta) \cot (\theta)\)
- \(r=2 \sin (\theta)\)
- \(r=4 \cos (\theta)\)
- \(r=\cos (\theta)\)
- \(r=7 \sin (\theta)\)
- \(r=-4 \cos (\theta)\)
- \(r=6 \sin (\theta)\)
- \(r=\sin (\theta)\)
- \(x^{2}+y^{2}=49\)
- \(x^{2}+y^{2}=9\)
- \(x^{2}+y^{2}=2\)
- \(y = x\)
- \(y=-\sqrt{3} x\)
- \(y = 0\)
- \(x = 0\)
- \(x^{2}+y^{2}=4 x \text { or }(x-2)^{2}+y^{2}=4\)
- \(5 x^{2}+5 y^{2}=x \text { or }\left(x-\frac{1}{10}\right)^{2}+y^{2}=\frac{1}{100}\)
- \(x^{2}+y^{2}=3 y \text { or } x^{2}+\left(y-\frac{3}{2}\right)^{2}=\frac{9}{4}\)
- \(x^{2}+y^{2}=-2 y \text { or } x^{2}+(y+1)^{2}=1\)
- \(x = 7\)
- \(y=\frac{1}{12}\)
- \(x = −2\)
- \(y=-\sqrt{5}\)
- \(x^{2}=2 y\)
- \(y^{2}=-x\)
- \(\left(x^{2}+y^{2}\right)^{2}=2 x y\)
- \(\left(x^{2}+2 x+y^{2}\right)^{2}=x^{2}+y^{2}\)
- \(\left(x^{2}+y^{2}+y\right)^{2}=x^{2}+y^{2}\)
- Any point of the form \((0, \theta)\) will work, e.g. \((0, \pi),(0,-117),\left(0, \frac{23 \pi}{4}\right) \text { and }(0,0)\).