11.2E: Exercises for Section 11.2
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- Dec 12, 2022
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In exercises 1 - 4, each set of parametric equations represents a line. Without eliminating the parameter, find the slope of each line.
1) x=3+t,y=1−t
2) x=8+2t,y=1
- Answer
- m=0
3) x=4−3t,y=−2+6t
4) x=−5t+7,y=3t−1
- Answer
- m=−35
In exercises 5 - 9, determine the slope of the tangent line, then find the equation of the tangent line at the given value of the parameter.
5) x=3sint,y=3cost,for t=π4
6) x=cost,y=8sint,for t=π2
- Answer
- Slope=0;y=8.
7) x=2t,y=t3,for t=−1
8) x=t+1t,y=t−1t,for t=1
- Answer
- Slope is undefined; x=2.
9) x=√t,y=2t,for t=4
In exercises 10 - 13, find all points on the curve that have the given slope.
10) x=4cost,y=4sint, slope = 0.5
- Solution
- dydx=dy/dtdx/dt=4cost−4sint=−cott.
Setting this derivative equal to 0.5, we obtain the equation, tant=−2.
tant=−2⟹yx=−2⟹y=−2x.
Note also that this pair of parametric equations represents the circle x2+y2=16.
By substitution, we find that this curve has a slope of 0.5 at the points:
(4√55,−8√55) and (−4√55,8√55).
11) x=2cost,y=8sint, slope= −1
12) x=t+1t,y=t−1t, slope= 1
- Answer
- No points possible; undefined expression.
13) x=2+√t,y=2−4t, slope= 0
In exercises 14 - 16, write the equation of the tangent line in Cartesian coordinates for the given parameter t.
14) x=e√t,y=1−lnt2,for t=1
- Answer
- y=−(4e)x+5
15) x=tlnt,y=sin2t,for t=π4
16) x=et,y=(t−1)2, at (1,1)
- Answer
- y=−2x+3
17) For x=sin(2t),y=2sint where 0≤t<2π. Find all values of t at which a horizontal tangent line exists.
18) For x=sin(2t),y=2sint where 0≤t<2π. Find all values of t at which a vertical tangent line exists.
- Answer
- A vertical tangent line exists at t=π4,5π4,3π4,7π4
19) Find all points on the curve x=4cos(t),y=4sin(t) that have the slope of 12.
20) Find dydx for x=sin(t),y=cos(t).
- Answer
- dydx=−tan(t)
21) Find the equation of the tangent line to x=sin(t),y=cos(t) at t=π4.
22) For the curve x=4t,y=3t−2, find the slope and concavity of the curve at t=3.
- Answer
- dydx=34 and d2ydx2=0, so the curve is neither concave up nor concave down at t=3. Therefore the graph is linear and has a constant slope but no concavity.
23) For the parametric curve whose equation is x=4cosθ,y=4sinθ, find the slope and concavity of the curve at θ=π4.
24) Find the slope and concavity for the curve whose equation is x=2+secθ,y=1+2tanθ at θ=π6.
- Answer
- dydx=4,d2ydx2=−4√3; the curve is concave down at θ=π6.
25) Find all points on the curve x=t+4,y=t3−3t at which there are vertical and horizontal tangents.
26) Find all points on the curve x=secθ,y=tanθ at which horizontal and vertical tangents exist.
- Answer
- No horizontal tangents. Vertical tangents at (1,0) and (−1,0).
In exercises 27 - 29, find d2y/dx2.
27) x=t4−1,y=t−t2
28) x=sin(πt),y=cos(πt)
- Answer
- d2y/dx2=−sec3(πt)
29) x=e−t,y=te2t
In exercises 30 - 31, find points on the curve at which tangent line is horizontal or vertical.
30) x=t(t2−3),y=3(t2−3)
- Answer
- Horizontal (0,−9);
Vertical (±2,−6).
31) x=3t1+t3,y=3t21+t3
In exercises 32 - 34, find dy/dx at the value of the parameter.
32) x=cost,y=sint,for t=3π4
- Answer
- dy/dx=1
33) x=√t,y=2t+4,t=9
34) x=4cos(2πs),y=3sin(2πs),for s=−14
- Answer
- dy/dx=0
In exercises 35 - 36, find d2y/dx2 at the given point without eliminating the parameter.
35) x=12t2,y=13t3,for t=2
36) x=√t,y=2t+4,for t=1
- Answer
- d2y/dx2=4
37) Find intervals for t on which the curve x=3t2,y=t3−t is concave up as well as concave down.
38) Determine the concavity of the curve x=2t+lnt,y=2t−lnt.
- Answer
- Concave up on t>0.
39) Sketch and find the area under one arch of the cycloid x=r(θ−sinθ),y=r(1−cosθ).
40) Find the area bounded by the curve x=cost,y=et,for 0≤t≤π2 and the lines y=1 and x=0.
- Answer
- 1 unit2
41) Find the area enclosed by the ellipse x=acosθ,y=bsinθ,for 0≤θ<2π.
42) Find the area of the region bounded by x=2sin2θ,y=2sin2θtanθ, for 0≤θ≤π2.
- Answer
- 3π2 units2
In exercises 43 - 46, find the area of the regions bounded by the parametric curves and the indicated values of the parameter.
43) x=2cotθ,y=2sin2θ,for 0≤θ≤π
44) [T] x=2acost−acos(2t),y=2asint−asin(2t),for 0≤t<2π
- Answer
- 6πa2 units2
45) [T] x=asin(2t),y=bsin(t),for 0≤t<2π (the “hourglass”)
46) [T] x=2acost−asin(2t),y=bsint,for 0≤t<2π (the “teardrop”)
- Answer
- 2πab units2
In exercises 47 - 52, find the arc length of the curve on the indicated interval of the parameter.
47) x=4t+3,y=3t−2,for 0≤t≤2
48) x=13t3,y=12t2,for 0≤t≤1
- Answer
- s=13(2√2−1) units
49) x=cos(2t),y=sin(2t),for 0≤t≤π2
50) x=1+t2,y=(1+t)3,for 0≤t≤1
- Answer
- s=7.075 units
51) x=etcost,y=etsint,for 0≤t≤π2 (express answer as a decimal rounded to three places)
52) x=acos3θ,y=asin3θ on the interval [0,2π) (the hypocycloid)
- Answer
- s=6a units
53) Find the length of one arch of the cycloid x=4(t−sint),y=4(1−cost).
54) Find the distance traveled by a particle with position (x,y) as t varies in the given time interval: x=sin2t,y=cos2t,for 0≤t≤3π.
- Answer
- 6√2 units
55) Find the length of one arch of the cycloid x=θ−sinθ,y=1−cosθ.
56) Show that the total length of the ellipse x=4sinθ,y=3cosθ is L=16∫π/20√1−e2sin2θdθ, where e=ca and c=√a2−b2.
57) Find the length of the curve x=et−t,y=4et/2,for −8≤t≤3.
In exercises 58 - 59, find the area of the surface obtained by rotating the given curve about the x-axis.
58) x=t3,y=t2,for 0≤t≤1
- Answer
- 2π(247√13+64)1215 units2
59) x=acos3θ,y=asin3θ,for 0≤θ≤π2
60) [T] Use a CAS to find the area of the surface generated by rotating x=t+t3,y=t−1t2,for 1≤t≤2 about the x-axis. (Answer to three decimal places.)
- Answer
- 59.101 units2
61) Find the surface area obtained by rotating x=3t2,y=2t3,for 0≤t≤5 about the y-axis.
62) Find the area of the surface generated by revolving x=t2,y=2t,for 0≤t≤4 about the x-axis.
- Answer
- 8π3(17√17−1) units2
63) Find the surface area generated by revolving x=t2,y=2t2,for 0≤t≤1 about the y-axis.