3.7 E: Chain Rule Exercises
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3.7: The Chain Rule
Exercise:
For the following exercises, given y=f(u) and u=g(x), find dydx by using Leibniz’s notation for the chain rule: dydx=dydududx.
214) y=3u−6,u=2x2
215) y=6u3,u=7x−4
Solution: 18u2⋅7=18(7x−4)2⋅7
216) y=sinu,u=5x−1
217) y=cosu,u=−x8
Solution: −sinu⋅−18=−sin(−x8)⋅−18
218) y=tanu,u=9x+2
219) y=√4u+3,u=x2−6x
Solution: 8x−242√4u+3=4x−12√4x2−24x+3
For each of the following exercises,
a. decompose each function in the form y=f(u) and u=g(x), and
b. find dydx as a function of x.
220) y=(3x−2)6
221) y=(3x2+1)3
Solution: a. u=3x2+1; b. 18x(3x2+1)2
222) y=sin5(x)
For each of the following exercises, find dydx as a function of x.
223) y=(x7+7x)7
Solution: a.f(u)=u7,u=x7+7x;b.7(x7+7x)6⋅(17−7x2)
224) y=tan(secx)
225) y=csc(πx+1)
Solution: a.f(u)=cscu,u=πx+1;b.−πcsc(πx+1)⋅cot(πx+1)
226) y=cot2x
227) y=−6sin−3x
a. f(u)=−6u−3,u=sinx,b.18sin−4x⋅cosx
For the following exercises, find dydx for each function.
228) y=(3x2+3x−1)4
229) y=(5−2x)−2
Solution: 4(5−2x)3
230) y=cos3(πx)
231) y=(2x3−x2+6x+1)3
Solution: 6(2x3−x2+6x+1)2(3x2−x+3)
232) y=1sin2(x)
233) y=(tanx+sinx)−3
Soution: −3(tanx+sinx)−4⋅(sec2x+cosx)
234) y=x2cos4x
235) y=sin(cos7x)
Solution: −7cos(cos7x)⋅sin7x
236) y=√6+secπx2
237) y=cot3(4x+1)
Solution: −12cot2(4x+1)⋅csc2(4x+1)
238) Let y=[f(x)]3 and suppose that f′(1)=4 and dydx=10 for x=1. Find f(1).
239) Let y=(f(x)+5x2)4 and suppose that f(−1)=−4 and dydx=3 when x=−1. Find f′(−1)
Solution: 1034
240) Let y=(f(u)+3x)2 and u=x3−2x. If f(4)=6 and dydx=18 when x=2, find f′(4).
241) [T] Find the equation of the tangent line to y=−sin(x2) at the origin. Use a calculator to graph the function and the tangent line together.
Solution: y=−12x
242) [T] Find the equation of the tangent line to y=(3x+1x)2 at the point (1,16). Use a calculator to graph the function and the tangent line together.
243) Find the x -coordinates at which the tangent line to y=(x−6x)8 is horizontal.
Solution: x=±√6
244) [T] Find an equation of the line that is normal to g(θ)=sin2(πθ) at the point (14,12). Use a calculator to graph the function and the normal line together.
For the following exercises, use the information in the following table to find h′(a) at the given value for a.
x | f(x) | f′(x) | g(x) | g′(x) |
0 | 2 | 5 | 0 | 2 |
1 | 1 | −2 | 3 | 0 |
2 | 4 | 4 | 1 | −1 |
3 | 3 | −3 | 2 | 3 |
245) h(x)=f(g(x));a=0
Solution: 10
246) h(x)=g(f(x));a=0
247) h(x)=(x4+g(x))−2;a=1
Solution: −18
248) h(x)=(f(x)g(x))2;a=3
249) h(x)=f(x+f(x));a=1
Solution: −4
250) h(x)=(1+g(x))3;a=2
251) h(x)=g(2+f(x2));a=1
Solution: −12
252) h(x)=f(g(sinx));a=0
253) [T] The position function of a freight train is given by
s(t)=100(t+1)−2, with s in meters and t in seconds. At time t=6s, find the train’s
a. velocity and
b. acceleration.
c. Using a. and b. is the train speeding up or slowing down?
Solution: a.−200343 m/s, b. 6002401 m/s^2, c. The train is slowing down since velocity and acceleration have opposite signs.
254) [T] A mass hanging from a vertical spring is in simple harmonic motion as given by the following position function, where t is measured in seconds and s is in inches:
s(t)=−3cos(πt+π4).
a. Determine the position of the spring at t=1.5 s.
b. Find the velocity of the spring at t=1.5 s.
255) [T] The total cost to produce x boxes of Thin Mint Girl Scout cookies is C dollars, where C=0.0001x3−0.02x2+3x+300. In t weeks production is estimated to be x=1600+100t boxes.
a. Find the marginal cost C′(x).
b. Use Leibniz’s notation for the chain rule, dCdt=dCdx⋅dxdt, to find the rate with respect to time t that the cost is changing.
c. Use b. to determine how fast costs are increasing when t=2 weeks. Include units with the answer.
Solution: a.C′(x)=0.0003x2−0.04x+3
b.dCdt=100⋅(0.0003x2−0.04x+3) c. Approximately $90,300 per week
256) [T] The formula for the area of a circle is A=πr2, where r is the radius of the circle. Suppose a circle is expanding, meaning that both the area A and the radius r (in inches) are expanding.
a. Suppose r=2−100(t+7)2 where t is time in seconds. Use the chain rule dAdt=dAdr⋅drdt to find the rate at which the area is expanding.
b. Use a. to find the rate at which the area is expanding at t=4 s.
257) [T] The formula for the volume of a sphere is S=43πr3, where r (in feet) is the radius of the sphere. Suppose a spherical snowball is melting in the sun.
a. Suppose r=1(t+1)2−112 where t is time in minutes. Use the chain rule dSdt=dSdr⋅drdt to find the rate at which the snowball is melting.
b. Use a. to find the rate at which the volume is changing at t=1 min.
Solution: a.dSdt=−8πr2(t+1)3 b. The volume is decreasing at a rate of −π36 ft3/min
258) [T] The daily temperature in degrees Fahrenheit of Phoenix in the summer can be modeled by the function T(x)=94−10cos[π12(x−2)], where x is hours after midnight. Find the rate at which the temperature is changing at 4 p.m.
259) [T] The depth (in feet) of water at a dock changes with the rise and fall of tides. The depth is modeled by the function D(t)=5sin(π6t−7π6)+8, where t is the number of hours after midnight. Find the rate at which the depth is changing at 6 a.m.
Solution: 2.3 ft/hr
More Exercises
For the following exercises, find f′(x) for each function.
331) f(x)=x2ex
Solution: 2xex+x2ex
332) f(x)=e−xx
333) f(x)=ex3lnx
Solution: ex3lnx(3x2lnx+x2)
334) f(x)=√e2x+2x
335) f(x)=ex−e−xex+e−x
Solution: 4(ex+e−x)2
336) f(x)=10xln10
337) f(x)=24x+4x2
Solution: 24x+2⋅ln2+8x