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3.7 E: Chain Rule Exercises

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3.7: The Chain Rule

Exercise:

For the following exercises, given y=f(u) and u=g(x), find dydx by using Leibniz’s notation for the chain rule: dydx=dydududx.

214) y=3u6,u=2x2

215) y=6u3,u=7x4

Solution: 18u27=18(7x4)27

216) y=sinu,u=5x1

217) y=cosu,u=x8

Solution: sinu18=sin(x8)18

218) y=tanu,u=9x+2

219) y=4u+3,u=x26x

Solution: 8x2424u+3=4x124x224x+3

For each of the following exercises,

a. decompose each function in the form y=f(u) and u=g(x), and

b. find dydx as a function of x.

220) y=(3x2)6

221) y=(3x2+1)3

Solution: a. u=3x2+1; b. 18x(3x2+1)2

222) y=sin5(x)

For each of the following exercises, find dydx as a function of x.

223) y=(x7+7x)7

Solution: a.f(u)=u7,u=x7+7x;b.7(x7+7x)6(177x2)

224) y=tan(secx)

225) y=csc(πx+1)

Solution: a.f(u)=cscu,u=πx+1;b.πcsc(πx+1)cot(πx+1)

226) y=cot2x

227) y=6sin3x

a. f(u)=6u3,u=sinx,b.18sin4xcosx

For the following exercises, find dydx for each function.

228) y=(3x2+3x1)4

229) y=(52x)2

Solution: 4(52x)3

230) y=cos3(πx)

231) y=(2x3x2+6x+1)3

Solution: 6(2x3x2+6x+1)2(3x2x+3)

232) y=1sin2(x)

233) y=(tanx+sinx)3

Soution: 3(tanx+sinx)4(sec2x+cosx)

234) y=x2cos4x

235) y=sin(cos7x)

Solution: 7cos(cos7x)sin7x

236) y=6+secπx2

237) y=cot3(4x+1)

Solution: 12cot2(4x+1)csc2(4x+1)

238) Let y=[f(x)]3 and suppose that f(1)=4 and dydx=10 for x=1. Find f(1).

239) Let y=(f(x)+5x2)4 and suppose that f(1)=4 and dydx=3 when x=1. Find f(1)

Solution: 1034

240) Let y=(f(u)+3x)2 and u=x32x. If f(4)=6 and dydx=18 when x=2, find f(4).

241) [T] Find the equation of the tangent line to y=sin(x2) at the origin. Use a calculator to graph the function and the tangent line together.

Solution: y=12x

242) [T] Find the equation of the tangent line to y=(3x+1x)2 at the point (1,16). Use a calculator to graph the function and the tangent line together.

243) Find the x -coordinates at which the tangent line to y=(x6x)8 is horizontal.

Solution: x=±6

244) [T] Find an equation of the line that is normal to g(θ)=sin2(πθ) at the point (14,12). Use a calculator to graph the function and the normal line together.

For the following exercises, use the information in the following table to find h(a) at the given value for a.

x f(x) f(x) g(x) g(x)
0 2 5 0 2
1 1 −2 3 0
2 4 4 1 −1
3 3 −3 2 3

245) h(x)=f(g(x));a=0

Solution: 10

246) h(x)=g(f(x));a=0

247) h(x)=(x4+g(x))2;a=1

Solution: 18

248) h(x)=(f(x)g(x))2;a=3

249) h(x)=f(x+f(x));a=1

Solution: 4

250) h(x)=(1+g(x))3;a=2

251) h(x)=g(2+f(x2));a=1

Solution: 12

252) h(x)=f(g(sinx));a=0

253) [T] The position function of a freight train is given by

s(t)=100(t+1)2, with s in meters and t in seconds. At time t=6s, find the train’s

a. velocity and

b. acceleration.

c. Using a. and b. is the train speeding up or slowing down?

Solution: a.200343 m/s, b. 6002401 m/s^2, c. The train is slowing down since velocity and acceleration have opposite signs.

254) [T] A mass hanging from a vertical spring is in simple harmonic motion as given by the following position function, where t is measured in seconds and s is in inches:

s(t)=3cos(πt+π4).

a. Determine the position of the spring at t=1.5 s.

b. Find the velocity of the spring at t=1.5 s.

255) [T] The total cost to produce x boxes of Thin Mint Girl Scout cookies is C dollars, where C=0.0001x30.02x2+3x+300. In t weeks production is estimated to be x=1600+100t boxes.

a. Find the marginal cost C(x).

b. Use Leibniz’s notation for the chain rule, dCdt=dCdxdxdt, to find the rate with respect to time t that the cost is changing.

c. Use b. to determine how fast costs are increasing when t=2 weeks. Include units with the answer.

Solution: a.C(x)=0.0003x20.04x+3

b.dCdt=100(0.0003x20.04x+3) c. Approximately $90,300 per week

256) [T] The formula for the area of a circle is A=πr2, where r is the radius of the circle. Suppose a circle is expanding, meaning that both the area A and the radius r (in inches) are expanding.

a. Suppose r=2100(t+7)2 where t is time in seconds. Use the chain rule dAdt=dAdrdrdt to find the rate at which the area is expanding.

b. Use a. to find the rate at which the area is expanding at t=4 s.

257) [T] The formula for the volume of a sphere is S=43πr3, where r (in feet) is the radius of the sphere. Suppose a spherical snowball is melting in the sun.

a. Suppose r=1(t+1)2112 where t is time in minutes. Use the chain rule dSdt=dSdrdrdt to find the rate at which the snowball is melting.

b. Use a. to find the rate at which the volume is changing at t=1 min.

Solution: a.dSdt=8πr2(t+1)3 b. The volume is decreasing at a rate of π36 ft3/min

258) [T] The daily temperature in degrees Fahrenheit of Phoenix in the summer can be modeled by the function T(x)=9410cos[π12(x2)], where x is hours after midnight. Find the rate at which the temperature is changing at 4 p.m.

259) [T] The depth (in feet) of water at a dock changes with the rise and fall of tides. The depth is modeled by the function D(t)=5sin(π6t7π6)+8, where t is the number of hours after midnight. Find the rate at which the depth is changing at 6 a.m.

Solution:  2.3 ft/hr

More Exercises

For the following exercises, find f(x) for each function.

331) f(x)=x2ex

Solution: 2xex+x2ex

332) f(x)=exx

333) f(x)=ex3lnx

Solution: ex3lnx(3x2lnx+x2)

334) f(x)=e2x+2x

335) f(x)=exexex+ex

Solution: 4(ex+ex)2

336) f(x)=10xln10

337) f(x)=24x+4x2

Solution: 24x+2ln2+8x


3.7 E: Chain Rule Exercises is shared under a CC BY-NC-SA license and was authored, remixed, and/or curated by LibreTexts.

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