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11.27: A.4.1- Section 4.1 Answers

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1. Q=20e(tln2)/3200

2. 2ln10ln2days

3. τ=10ln2ln4/3minutes

4. τln(p0/p1)ln2

5. tptq=lnplnq

6. k=1t2t1lnQ1Q2

7. 20 g

8. 50ln23yrs

9. 252ln2

10.

  1. =20ln3yr
  2. Q0=100000e5

11.

  1. Q(t)=50004750et/10
  2. 5000lbs

12. 125 yrs

13. V=V0etln10/24 hours

14. 1500ln43ln2yrs;24/3Q0

15. W(t)=2019et/20;limtW(t)=20 ounces

16. S(t)=10(1+et/10;limtS(t)=10 g

17. 10 gallons

18. V(t)=15000+10000et/20

19. W(t)=4×106(t+1)2 dollars t years from now

20. p=1002524et/2

21.

  1. P(t)=1000e.06t+50e.06t1e.06/521
  2. 5.64×104

22.

  1. P=rP12M
  2. P=12Mr(1ert)+P0ert
  3. MrP012(1erN)
  4. For (i) approximate M=$402.25, exact M=$402.80 for (ii) approximate M=$1206.05, exact M=$1206.93.

23.

  1. T(α)=1rln(1(1erN)/α)) years S(α)=P0(1erN)[rN+αln(1(1erN)/α)]
  2. T(1.05)=13.69yrs,S(1.05)=$3579.94T(1.10)=12.61yrs,S(1.10)=$6476.63T(1.15)=11.70yrs,S(1.15)=$8874.

24. P0={S0(1e(ar)T)raif arS0Tif a=r


This page titled 11.27: A.4.1- Section 4.1 Answers is shared under a CC BY-NC-SA 3.0 license and was authored, remixed, and/or curated by William F. Trench.

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