w^{\circ} = 115^{\circ} since the opposite angles of a parallelogram are equal. \(x^{\circ} = 180^{\circ} -(w^{\circ} + 30^{\circ}) = 180^{\circ} - (115^{\circ} + 30^{\circ}) = 180^{\circ} - 145^{...w^{\circ} = 115^{\circ} since the opposite angles of a parallelogram are equal. x^{\circ} = 180^{\circ} -(w^{\circ} + 30^{\circ}) = 180^{\circ} - (115^{\circ} + 30^{\circ}) = 180^{\circ} - 145^{\circ} = 35^{\circ}, because the sum of the angles of \triangle ABC is 180^{\circ}, y^{\circ} = 30^{\circ} and x^{\circ} = x^{\circ} = 35^{\circ} because they are alternate interior angles of parallel lines.
w^{\circ} = 115^{\circ} since the opposite angles of a parallelogram are equal. \(x^{\circ} = 180^{\circ} -(w^{\circ} + 30^{\circ}) = 180^{\circ} - (115^{\circ} + 30^{\circ}) = 180^{\circ} - 145^{...w^{\circ} = 115^{\circ} since the opposite angles of a parallelogram are equal. x^{\circ} = 180^{\circ} -(w^{\circ} + 30^{\circ}) = 180^{\circ} - (115^{\circ} + 30^{\circ}) = 180^{\circ} - 145^{\circ} = 35^{\circ}, because the sum of the angles of \triangle ABC is 180^{\circ}, y^{\circ} = 30^{\circ} and x^{\circ} = x^{\circ} = 35^{\circ} because they are alternate interior angles of parallel lines.