\(w^{\circ} = 115^{\circ}\) since the opposite angles of a parallelogram are equal. \(x^{\circ} = 180^{\circ} -(w^{\circ} + 30^{\circ}) = 180^{\circ} - (115^{\circ} + 30^{\circ}) = 180^{\circ} - 145^{...\(w^{\circ} = 115^{\circ}\) since the opposite angles of a parallelogram are equal. \(x^{\circ} = 180^{\circ} -(w^{\circ} + 30^{\circ}) = 180^{\circ} - (115^{\circ} + 30^{\circ}) = 180^{\circ} - 145^{\circ} = 35^{\circ}\), because the sum of the angles of \(\triangle ABC\) is \(180^{\circ}\), \(y^{\circ} = 30^{\circ}\) and \(x^{\circ} = x^{\circ} = 35^{\circ}\) because they are alternate interior angles of parallel lines.
\(w^{\circ} = 115^{\circ}\) since the opposite angles of a parallelogram are equal. \(x^{\circ} = 180^{\circ} -(w^{\circ} + 30^{\circ}) = 180^{\circ} - (115^{\circ} + 30^{\circ}) = 180^{\circ} - 145^{...\(w^{\circ} = 115^{\circ}\) since the opposite angles of a parallelogram are equal. \(x^{\circ} = 180^{\circ} -(w^{\circ} + 30^{\circ}) = 180^{\circ} - (115^{\circ} + 30^{\circ}) = 180^{\circ} - 145^{\circ} = 35^{\circ}\), because the sum of the angles of \(\triangle ABC\) is \(180^{\circ}\), \(y^{\circ} = 30^{\circ}\) and \(x^{\circ} = x^{\circ} = 35^{\circ}\) because they are alternate interior angles of parallel lines.