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  • 5.1: Solving Equations Part I
    https://math.libretexts.org/Courses/Western_Technical_College/PrePALS_Math_with_Business_Apps/05%3A_Solving_Equations/5.01%3A_Solving_Equations_Part_I
    \[ \begin{aligned} -12 + 3 = =8 + 4 + \frac{p}{-3} ~ & \textcolor{red}{ \text{ Original equation.}} \\ -12 + 3 = -8 + 4 + \frac{15}{-3} ~ & \textcolor{red}{ \text{ Substitute 15 for } p.} \\ -9 = -8 +...\[ \begin{aligned} -12 + 3 = =8 + 4 + \frac{p}{-3} ~ & \textcolor{red}{ \text{ Original equation.}} \\ -12 + 3 = -8 + 4 + \frac{15}{-3} ~ & \textcolor{red}{ \text{ Substitute 15 for } p.} \\ -9 = -8 + 4 + (-5) ~ & \begin{aligned} \textcolor{red}{ \text{ On the left, add: } -12 + 3 = -9. \text{ On the }} \\ \textcolor{red}{ \text{ right, divide: } 15/(-3) = -5.} \end{aligned} \\ -9 = -4 + (-5) ~ & \textcolor{red}{ \text{ On the right, } -8 + 4 = -4.} \\ -9 = -9 ~ & \textcolor{red}{ \text{ On the…
  • 2.1.6: Solving Equations
    https://math.libretexts.org/Courses/Nova_Scotia_Community_College/MATH_1043/02%3A_Algebra/2.01%3A_The_Integers/2.1.06%3A_Solving_Equations
    \[ \begin{aligned} -12 + 3 = =8 + 4 + \frac{p}{-3} ~ & \textcolor{red}{ \text{ Original equation.}} \\ -12 + 3 = -8 + 4 + \frac{15}{-3} ~ & \textcolor{red}{ \text{ Substitute 15 for } p.} \\ -9 = -8 +...\[ \begin{aligned} -12 + 3 = =8 + 4 + \frac{p}{-3} ~ & \textcolor{red}{ \text{ Original equation.}} \\ -12 + 3 = -8 + 4 + \frac{15}{-3} ~ & \textcolor{red}{ \text{ Substitute 15 for } p.} \\ -9 = -8 + 4 + (-5) ~ & \begin{aligned} \textcolor{red}{ \text{ On the left, add: } -12 + 3 = -9. \text{ On the }} \\ \textcolor{red}{ \text{ right, divide: } 15/(-3) = -5.} \end{aligned} \\ -9 = -4 + (-5) ~ & \textcolor{red}{ \text{ On the right, } -8 + 4 = -4.} \\ -9 = -9 ~ & \textcolor{red}{ \text{ On the…
  • 7.6: Solving Equations
    https://math.libretexts.org/Courses/Barton_Community_College/Book%3A_Technical_Mathematics_(Turner)/07%3A_The_Integers/7.06%3A_Solving_Equations
    \[ \begin{aligned} -12 + 3 = =8 + 4 + \frac{p}{-3} ~ & \textcolor{red}{ \text{ Original equation.}} \\ -12 + 3 = -8 + 4 + \frac{15}{-3} ~ & \textcolor{red}{ \text{ Substitute 15 for } p.} \\ -9 = -8 +...\[ \begin{aligned} -12 + 3 = =8 + 4 + \frac{p}{-3} ~ & \textcolor{red}{ \text{ Original equation.}} \\ -12 + 3 = -8 + 4 + \frac{15}{-3} ~ & \textcolor{red}{ \text{ Substitute 15 for } p.} \\ -9 = -8 + 4 + (-5) ~ & \begin{aligned} \textcolor{red}{ \text{ On the left, add: } -12 + 3 = -9. \text{ On the }} \\ \textcolor{red}{ \text{ right, divide: } 15/(-3) = -5.} \end{aligned} \\ -9 = -4 + (-5) ~ & \textcolor{red}{ \text{ On the right, } -8 + 4 = -4.} \\ -9 = -9 ~ & \textcolor{red}{ \text{ On the…
  • 5.1: Solving Equations Part I
    https://math.libretexts.org/Courses/Western_Technical_College/PrePALS_PreAlgebra/05%3A_Solving_Equations/5.01%3A_Solving_Equations_Part_I
    \[ \begin{aligned} -12 + 3 = =8 + 4 + \frac{p}{-3} ~ & \textcolor{red}{ \text{ Original equation.}} \\ -12 + 3 = -8 + 4 + \frac{15}{-3} ~ & \textcolor{red}{ \text{ Substitute 15 for } p.} \\ -9 = -8 +...\[ \begin{aligned} -12 + 3 = =8 + 4 + \frac{p}{-3} ~ & \textcolor{red}{ \text{ Original equation.}} \\ -12 + 3 = -8 + 4 + \frac{15}{-3} ~ & \textcolor{red}{ \text{ Substitute 15 for } p.} \\ -9 = -8 + 4 + (-5) ~ & \begin{aligned} \textcolor{red}{ \text{ On the left, add: } -12 + 3 = -9. \text{ On the }} \\ \textcolor{red}{ \text{ right, divide: } 15/(-3) = -5.} \end{aligned} \\ -9 = -4 + (-5) ~ & \textcolor{red}{ \text{ On the right, } -8 + 4 = -4.} \\ -9 = -9 ~ & \textcolor{red}{ \text{ On the…

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