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  • https://math.libretexts.org/Courses/Montana_State_University/M273%3A_Multivariable_Calculus/13%3A_Vector-valued_Functions/13.2b%3A_The_Calculus_of_Vector-Valued_Functions_II
    We now find \(\vecs u\,'(t)\) using part 3 of Theorem 92: \[\begin{align*}\vecs u\,'(t) &= f^\prime (t)\vecs u(t) + f(t)\vecs u\,'(t) \\&= -\frac{2t(2t^2-1)}{2\big(\sqrt{t^2+(t^2-1)^2}\,\big)^3}\langl...We now find \(\vecs u\,'(t)\) using part 3 of Theorem 92: \[\begin{align*}\vecs u\,'(t) &= f^\prime (t)\vecs u(t) + f(t)\vecs u\,'(t) \\&= -\frac{2t(2t^2-1)}{2\big(\sqrt{t^2+(t^2-1)^2}\,\big)^3}\langle t,t^2-1\rangle + \frac{1}{\sqrt{t^2+(t^2-1)^2}}\langle 1,2t\rangle.\end{align*}\]
  • https://math.libretexts.org/Courses/Misericordia_University/MTH_226%3A_Calculus_III/Chapter_13%3A_Vector-valued_Functions/13.2B%3A_The_Calculus_of_Vector-Valued_Functions_II
    We now find \(\vecs u\,'(t)\) using part 3 of Theorem 92: \[\begin{align*}\vecs u\,'(t) &= f^\prime (t)\vecs u(t) + f(t)\vecs u\,'(t) \\&= -\frac{2t(2t^2-1)}{2\big(\sqrt{t^2+(t^2-1)^2}\,\big)^3}\langl...We now find \(\vecs u\,'(t)\) using part 3 of Theorem 92: \[\begin{align*}\vecs u\,'(t) &= f^\prime (t)\vecs u(t) + f(t)\vecs u\,'(t) \\&= -\frac{2t(2t^2-1)}{2\big(\sqrt{t^2+(t^2-1)^2}\,\big)^3}\langle t,t^2-1\rangle + \frac{1}{\sqrt{t^2+(t^2-1)^2}}\langle 1,2t\rangle.\end{align*}\]
  • https://math.libretexts.org/Courses/Georgia_State_University_-_Perimeter_College/MATH_2215%3A_Calculus_III/13%3A_Vector-valued_Functions/The_Calculus_of_Vector-Valued_Functions_II
    We now find \(\vecs u\,'(t)\) using part 3 of Theorem 92: \[\begin{align*}\vecs u\,'(t) &= f^\prime (t)\vecs u(t) + f(t)\vecs u\,'(t) \\&= -\frac{2t(2t^2-1)}{2\big(\sqrt{t^2+(t^2-1)^2}\,\big)^3}\langl...We now find \(\vecs u\,'(t)\) using part 3 of Theorem 92: \[\begin{align*}\vecs u\,'(t) &= f^\prime (t)\vecs u(t) + f(t)\vecs u\,'(t) \\&= -\frac{2t(2t^2-1)}{2\big(\sqrt{t^2+(t^2-1)^2}\,\big)^3}\langle t,t^2-1\rangle + \frac{1}{\sqrt{t^2+(t^2-1)^2}}\langle 1,2t\rangle.\end{align*}\]

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