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Mathematics LibreTexts

4.2: Logs and Integrals

  • Page ID
    531
  • [ "article:topic", "authorname:green" ]

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    Recall that

    \[ \int \dfrac{1}{x} dx = \ln |x| + C.\]

    Note that we have the absolute value sign since for negative values of that graph of \(\frac{1}{x}\) is still continuous.

    Example 1

    Evaluate the integral

    \[ \int \dfrac{dx}{1-3x}.\]

    Solution

    Let \(u = 1-3x\) and \(du = -3\, dx\).

    The integral becomes

    \[\begin{align}  -\dfrac{1}{3} \int \dfrac{du}{u} &=  \dfrac{1}{3}\ln |u| +C \\ &= -\dfrac{1}{3} \ln |1-3x| +C. \end{align}\]

    Exercises

    Evaluate the integrals of the following:

    1)  \(\dfrac{1}{(x-1)}\)

    2)  \(\dfrac{1}{(1-x)}\)

    3)  \(\cot x\)

    4)  \(\dfrac{(2x - 1)}{(x + 2)}\)          

    5)  \(\dfrac{3x}{(x^2 + 1)^2}\)                     

    6)  \(\dfrac{1}{x \ln x}\)

    7)  \(\dfrac{1}{\sqrt{x - 1}}\)

    8)  \(\dfrac{(x^2 + 2x + 4)}{(3x)}\)

    9)  \(\dfrac{(x + 1)}{(x^2 + 2x)^3}\)

    10)  \((4 - x)^5 \)

    11) \(\dfrac{1}{\sqrt{3x}}\)

    12) \(\tan x\)

    13) \((\tan x)(\ln(\cos x))\)

    14)  \(\sec x\)  (hint:  multiply top and bottom by \(\sec x + \tan x)\)

    15)  \(\csc x\)  (hint: Use the formula \(\csc x = \sec (\pi/2 - x)\).    

    Larry Green (Lake Tahoe Community College)

    • Integrated by Justin Marshall.