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Mathematics LibreTexts

15: Linear Independence

( \newcommand{\kernel}{\mathrm{null}\,}\)

Consider a plane P that includes the origin in 3 and a collection {u,v,w} of non-zero vectors in P:

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If no two of u,v and w are parallel, then P=span{u,v,w}. But any two vectors determines a plane, so we should be able to span the plane using only two of the vectors u,v,w. Then we could choose two of the vectors in {u,v,w} whose span is P, and express the other as a linear combination of those two. Suppose u and v span P. Then there exist constants d1,d2 (not both zero) such that w=d1u+d2v. Since w can be expressed in terms of u and v we say that it is not independent. More generally, the relationship

c1u+c2v+c3w=0ci, some ci0

expresses the fact that u,v,w are not all independent.

Definition (Independent)

We say that the vectors v1,v2,,vn are linearly dependent if there exist constants (usually our vector spaces are defined over R, but in general we can have vector spaces defined over different base fields such as C or Z2. The coefficients ci should come from whatever our base field is (usually R).} c1,c2,,cn not all zero such that

c1v1+c2v2++cnvn=0.

Otherwise, the vectors v1,v2,,vn are linearly independent.

Remark
The zero vector 0V can never be on a list of independent vectors because α0V=0V for any scalar α.

Example 106

Consider the following vectors in 3:
v1=(413),v2=(374),v3=(51217),v4=(110).


Are these vectors linearly independent?

No, since 3v1+2v2v3+v4=0, the vectors are linearly dependent.

Contributor


15: Linear Independence is shared under a not declared license and was authored, remixed, and/or curated by LibreTexts.

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