4.3: Chapter 4 Review Exercises
- Page ID
- 176343
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\(\newcommand{\avec}{\mathbf a}\) \(\newcommand{\bvec}{\mathbf b}\) \(\newcommand{\cvec}{\mathbf c}\) \(\newcommand{\dvec}{\mathbf d}\) \(\newcommand{\dtil}{\widetilde{\mathbf d}}\) \(\newcommand{\evec}{\mathbf e}\) \(\newcommand{\fvec}{\mathbf f}\) \(\newcommand{\nvec}{\mathbf n}\) \(\newcommand{\pvec}{\mathbf p}\) \(\newcommand{\qvec}{\mathbf q}\) \(\newcommand{\svec}{\mathbf s}\) \(\newcommand{\tvec}{\mathbf t}\) \(\newcommand{\uvec}{\mathbf u}\) \(\newcommand{\vvec}{\mathbf v}\) \(\newcommand{\wvec}{\mathbf w}\) \(\newcommand{\xvec}{\mathbf x}\) \(\newcommand{\yvec}{\mathbf y}\) \(\newcommand{\zvec}{\mathbf z}\) \(\newcommand{\rvec}{\mathbf r}\) \(\newcommand{\mvec}{\mathbf m}\) \(\newcommand{\zerovec}{\mathbf 0}\) \(\newcommand{\onevec}{\mathbf 1}\) \(\newcommand{\real}{\mathbb R}\) \(\newcommand{\twovec}[2]{\left[\begin{array}{r}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\ctwovec}[2]{\left[\begin{array}{c}#1 \\ #2 \end{array}\right]}\) \(\newcommand{\threevec}[3]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\cthreevec}[3]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \end{array}\right]}\) \(\newcommand{\fourvec}[4]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\cfourvec}[4]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \end{array}\right]}\) \(\newcommand{\fivevec}[5]{\left[\begin{array}{r}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\cfivevec}[5]{\left[\begin{array}{c}#1 \\ #2 \\ #3 \\ #4 \\ #5 \\ \end{array}\right]}\) \(\newcommand{\mattwo}[4]{\left[\begin{array}{rr}#1 \amp #2 \\ #3 \amp #4 \\ \end{array}\right]}\) \(\newcommand{\laspan}[1]{\text{Span}\{#1\}}\) \(\newcommand{\bcal}{\cal B}\) \(\newcommand{\ccal}{\cal C}\) \(\newcommand{\scal}{\cal S}\) \(\newcommand{\wcal}{\cal W}\) \(\newcommand{\ecal}{\cal E}\) \(\newcommand{\coords}[2]{\left\{#1\right\}_{#2}}\) \(\newcommand{\gray}[1]{\color{gray}{#1}}\) \(\newcommand{\lgray}[1]{\color{lightgray}{#1}}\) \(\newcommand{\rank}{\operatorname{rank}}\) \(\newcommand{\row}{\text{Row}}\) \(\newcommand{\col}{\text{Col}}\) \(\renewcommand{\row}{\text{Row}}\) \(\newcommand{\nul}{\text{Nul}}\) \(\newcommand{\var}{\text{Var}}\) \(\newcommand{\corr}{\text{corr}}\) \(\newcommand{\len}[1]{\left|#1\right|}\) \(\newcommand{\bbar}{\overline{\bvec}}\) \(\newcommand{\bhat}{\widehat{\bvec}}\) \(\newcommand{\bperp}{\bvec^\perp}\) \(\newcommand{\xhat}{\widehat{\xvec}}\) \(\newcommand{\vhat}{\widehat{\vvec}}\) \(\newcommand{\uhat}{\widehat{\uvec}}\) \(\newcommand{\what}{\widehat{\wvec}}\) \(\newcommand{\Sighat}{\widehat{\Sigma}}\) \(\newcommand{\lt}{<}\) \(\newcommand{\gt}{>}\) \(\newcommand{\amp}{&}\) \(\definecolor{fillinmathshade}{gray}{0.9}\)Exercises 1 - 4
True or False? Justify your answer with a proof or a counterexample.
- The rectangular coordinates of the point \(\left(4,\frac{5π}{6}\right)\) are \(\left(2\sqrt{3},−2\right).\)
- The equations \(x=\cosh(3t), \; y=2\sinh(3t)\) represent a hyperbola.
- Answer
- True
- The arc length of the spiral given by \(r=\dfrac{θ}{2}\) for \(0≤θ≤3π\) is \(\frac{9}{4}π^3\) units.
- Given \(x=f(t)\) and \(y=g(t)\), if \(\dfrac{dx}{dy}=\dfrac{dy}{dx}\), then \(f(t)=g(t)+C,\) where \(C\) is a constant.
- Answer
- False. Imagine \(y=t+1, \; x=−t+1.\)
Exercises 5 -8
Sketch the parametric curve and eliminate the parameter to find the Cartesian equation of the curve.
- \(x=1+t, \; y=t^2−1, \quad −1≤t≤1\)
- \(x=e^t, \; y=1−e^{3t}, \quad 0≤t≤1\)
- Answer
-
\(y=1−x^3\)
Figure \(\PageIndex{1}\): Graph of a curve starting at (1, 0) and decreasing into the fourth quadrant.
- \(x=\sin θ, \; y=1−\csc θ, \quad 0≤θ≤2π\)
- \(x=4\cos ϕ, \; y=1−\sin ϕ, \quad 0≤ϕ≤2π\)
- Answer
-
\(\dfrac{x^2}{16}+(y−1)^2=1\)
Figure \(\PageIndex{2}\): Graph of an ellipse with center (0, 1), major axis horizontal and of length 8, and minor axis of length 2.
- Find the equation of the tangent line to the given curve. Graph both the function and its tangent line.
\(x=\ln(t),\; y=t^2−1, \; t=1\)
- Find \(\dfrac{dy}{dx}, \; \dfrac{dx}{dy},\) and \(\dfrac{d^2x}{dy^2}\) of \(y=(2+e^{−t}), \; x=1−\sin t\)
- Find the area of the region.
\(x=t^2, \; y=\ln(t), \quad 0≤t≤e\)
- Answer
- \(\dfrac{e^2}{2}\text{ units}^2\)
- Find the arc length of the curve over the given interval.
\(x=3t+4, \; y=9t−2, \quad 0≤t≤3\)
- Answer
- \(9\sqrt{10}\) units


