6.2: Finding the factors of a Monomial
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Products of Polynomials
Previously, we studied the multiplication of polynomials. We were given factors and asked to find their product, as shown below.
Given the factors 4 and 8, find the product. 4⋅8=32. The product is 32.
Given the factors 6x2 and 2x−7, find the product.
6x2(2x−7)=12x3−42x2
The product is 12x3−42x2.
Given the factors x−2y and 3x+y, find the product.
x−2y)(3x+y)=3x2+xy−6xy−2y2=3x3−5xy−2y2
The product is 3x2−5xy−2y2.
Given the factors a+8 and a+8, find the product.
(a+8)2=a2+16a+64
The product is a2+16a+64.
Factoring
Now, let’s reverse the situation. We will be given the product, and we will try to find the factors. This process, which is the reverse of multiplication, is called factoring.
Factoring is the process of determining the factors of a given product.
Sample Set A
The number 24 is the product, and one factor is 6. What is the other factor?
We’re looking for a number () such that 6⋅()=24. We know from experience that ()=4. As problems become progressively more complex, our experience may not give us the solution directly. We need a method for finding factors. To develop this method we can use the relatively simple problem 6⋅()=24 as a guide.
To find the number (), we would divide 24 by 6.
246=4
The other factor is 4.
The product is 18x3y4z2 and one factor is 9xy2z. What is the other factor?
We know that since 9xy2z is a factor of 18x3y4z2, there must be some quantity ) such that 9xy2z⋅()=18x3y4z2.
Dividing 18x3y4z2 by 9xy2z, we get:
18x3y4z29xy2z=2x2y2z
Thus, the other factor is 2x2y2z.
Checking will convince us that 2x2y2z is indeed the proper factor.
2x2y2z)(9xy2z)=18x2+1y2+2z1+1=18x3y4z2
We should try to find the quotient mentally and avoid actually writing the division problem.
The product of −21a5bn and 3ab4 is a factor. Find the other factor.
Mentally dividing −21a5bn by 3ab4, we get
−21a5bn3ab4=−7a5−1bn−4=−7a4bn−4
Thus, the other factor is −7a4bn−4.
Practice Set A
The product is 84 and one factor is 6. What is the other factor?
- Answer
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14
The product is 14x3y2z5 and one factor is 7xyz. What is the other factor?
- Answer
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2x2yz4
Exercises
In the following problems, the first quantity represents the product and the second quantity represents a factor of that product. Find the other factor.
30,6
- Answer
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5
45,9
10a,5
- Answer
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2a
16a,8
21b,7b
- Answer
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3
15a,5a
20x3,4
- Answer
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5x3
30y4,6
8x4,4x
- Answer
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2x3
16y5,2y
6x2y,3x
- Answer
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2xy
9a4b5,9a4
15x2b4c7,5x2bc6
- Answer
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3b3c
25a3b2c,5ac
18x2b5,−2xb4
- Answer
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−9xb
22b8c6d3,−11b8c4
−60x5b3f9,−15x2b2f2
- Answer
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4x3bf7
39x4y5z11,3xy3z10
147a20b6c18d2,21a3bd
- Answer
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7a17b5c18d
−121a6b8c10,11b2c5
18x4y3,12xy3
- Answer
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14x3
7x2y3z2,7x2y3z
5a4b7c3d2,5a4b7c3d
- Answer
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d
14x4y3z7,14x4y3z7
12a3b2c8,12a3b2c8
- Answer
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1
6(a+1)2(a+5),3(a+1)2
8(x+y)3(x−2y),2(x−2y)
- Answer
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4(x+y)3
14(a−3)6(a+4)2,2(a−3)2(a+4)
26(x−5y)10(x−3y)12,−2(x−5y)7(x−3y)7
- Answer
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−13(x−5y)3(x−3y)5
34(1−a)4(1+a)8,−17(1−a)4(1+a)2
(x+y)(x−y),x−y
- Answer
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(x+y)
(a+3)(a−3),a−3
48xn+3y2n−1,8x3yn+5
- Answer
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6xnyn−6
0.0024x4ny3n+5z2,0.03x3ny5
Exercises for Review
Simplify (x4y0z2)3
- Answer
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x12z6
Simplify −−[−(−|6|)]
Find the product (2x−4)2
- Answer
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4x2−16x+16