3.7.E: Problems on Metric Spaces (Exercises)
( \newcommand{\kernel}{\mathrm{null}\,}\)
The "arrowed" problems should be noted for later work.
Show that E2 becomes a metric space if distances ρ(¯x,¯y) are defined by
(a) ρ(¯x,¯y)=|x1−y1|+|x2−y2| or
(b) ρ(¯x,¯y)=max{|x1−y1|,|x2−y2|},
where ¯x=(x1,x2) and ¯y=(y1,y2). In each case, describe G¯0(1) and S¯0(1). Do the same for the subspace of points with nonnegative coordinates.
Prove the assertions made in the text about globes in a discrete space. Find an empty sphere in such a space. Can a sphere contain the entire space?
Show that ρ in Examples (3) and (5) obeys the metric axioms.
Let M be the set of all positive integers together with the "point" ∞. Metrize M by setting
ρ(m,n)=|1m−1n|, with the convention that 1∞=0.
Verify the metric axioms. Describe G∞(12),S∞(12), and G1(1).
⇒5. Metrize the extended real number system E∗ by
ρ′(x,y)=|f(x)−f(y)|,
where the function
f:E∗⟶ onto [−1,1]
is defined by
f(x)=x1+|x| if x is finite, f(−∞)=−1, and f(+∞)=1.
Compute ρ′(0,+∞),ρ′(0,−∞),ρ′(−∞,+∞),ρ′(0,1),ρ′(1,2), and ρ′(n,+∞). Describe G0(1),G+∞(1), and G−∞(12). Verify the metric axioms (also when infinities are involved).
⇒6. In Problem 5, show that the function f is one to one, onto [−1,1], and increasing; i.e.
x<x′ implies f(x)<f(x′) for x,x′∈E∗.
Also show that the f -image of an interval (a,b)⊆E∗ is the interval (f(a),f(b)). Hence deduce that globes in E∗ (with ρ′ as in Problem 5) are intervals in E∗ (possibly infinite).
[Hint: For a finite x, put
y=f(x)=x1+|x|.
Solving for x (separately in the cases x≥0 and x<0), show that
(∀y∈(−1,1))x=f−1(y)=y1−|y|;
thus x is uniquely determined by y, i.e., f is one to one and onto-each y∈(−1,1) corresponds to some x∈E1. (How about ±1?)
To show that f is increasing, consider separately the three cases x<0<x′, x<x′<0 and 0<x<x′ (also for infinite x and x′).]
Continuing Problems 5 and 6, consider (E1,ρ′) as a subspace of (E∗,ρ′) with ρ′ as in Problem 5. Show that globes in (E1,ρ′) are exactly all open intervals in E∗. For example, (0,1) is a globe. What are its center and radius under ρ′ and under the standard metric ρ?
Metrize the closed interval [0,+∞] in E∗ by setting
ρ(x,y)=|11+x−11+y|,
with the conventions 1+(+∞)=+∞ and 1/(+∞)=0. Verify the metric axioms. Describe Gp(1) for arbitrary p≥0.
Prove that if ρ is a metric for S, then another metric ρ′ for S is given by
(i) ρ′(x,y)=min{1,ρ(x,y)};
(ii) ρ′(x,y)=ρ(x,y)1+ρ(x,y).
In case (i), show that globes Gp(ε) of radius ε≤1 are the same under ρ and ρ′. In case (ii), prove that any Gp(ε) in (S,ρ) is also a globe Gp(ε′) in (S,ρ′) of radius
ε′=ε1+ε,
and any globe of radius ε′<1 in (S,ρ′) is also a globe in (S,ρ). (Find the converse formula for ε as well!)
[Hint for the triangle inequality in (ii): Let a=ρ(x,z),b=ρ(x,y), and c=ρ(y,z) so that a≤b+c. The required inequality is
a1+a≤b1+b+c1+c.
Simplify it and show that it follows from a≤b+c.]
Prove that if (X,ρ′) and (Y,ρ′′) are metric spaces, then a metric ρ for the set X×Y is obtained by setting, for x1,x2∈X and y1,y2∈Y,
(i) ρ((x1,y1),(x2,y2))=max{ρ′(x1,x2),ρ′′(y1,y2)}; or
(ii) ρ((x1,y1),(x2,y2))=√ρ′(x1,x2)2+ρ′′(y1,y2)2.
[Hint: For brevity, put ρ′12=ρ′(x1,x2),ρ′′12=ρ′′(y1,y2), etc. The triangle inequality in (ii),
√(ρ′13)2+(ρ′′13)2≤√(ρ′12)2+(ρ′′12)2+√(ρ′23)2+(ρ′′23)2,
is verified by squaring both sides, isolating the remaining square root on the right side, simplifying, and squaring again. Simplify by using the triangle inequalities valid in X and Y, i.e.,
ρ′13≤ρ′12+ρ′23 and ρ′′13≤ρ′′12+ρ′′23.
Reverse all steps, so that the required inequality becomes the last step. ]
Prove that
|ρ(y,z)−ρ(x,z)|≤ρ(x,y)
in any metric space (S,ρ).
[Caution: The formula ρ(x,y)=|x−y|, valid in En, cannot be used in (S,ρ). Why? ]
Prove that
ρ(p1,p2)+ρ(p2,p3)+⋯+ρ(pn−1,pn)≥ρ(p1,pn).
[Hint: Use induction. ]