6.4.E: Further Problems on Differentiable Functions
( \newcommand{\kernel}{\mathrm{null}\,}\)
For E=Er(Cr) prove Theorem 2 directly.
[Hint: Find
Dkhj(→p),j=1,…,r,
from Theorem 4 of §3, and Theorem 3 of §2. Verify that
Dkh(→p)=r∑j=1ejDkhj(→p) and Dig(→q)=r∑j=1ejDigj(→q),
where the ej are the basic unit vectors in Er. Proceed.]
Let g(x,y,z)=u,x=f1(r,θ),y=f2(r,θ),z=f3(r,θ), and
f=(f1,f2,f3):E2→E3.
Assuming differentiability, verify (using "variables") that
du=∂u∂xdx+∂u∂ydy+∂u∂zdz=∂u∂rdr+∂u∂θdθ
by computing derivatives from (8'). Then do all in the mapping notation for H=g∘f,dH(→p;→t).
For the specific functions f,g,h, and k of Problems 4 and 5 of §2, set up and solve problems analogous to Problem 2, using
(a) k∘f;(b) g∘k;(c) f∘h;(d) h∘g.
For the functions of Problem 5 in §1, find the formulas for df(→p;→t). At which →p does df(→p;⋅) exist in each given case? Describe it for a chosen →p.
From Theorem 2, with E=E1(C), find
∇h(→p)=n∑k=1Dkg(→q)∇fk(→p).
Use Theorem 1 for a new solution of Problem 7 in §3 with E=E1(C).
[Hint: Define F on E′ and G on E2(C2) by
F(→x)=(f(→x),g(→x)) and G(→y)=ay1+by2.
Then h=af+bg=G∘F. (Why?) Use Problems 9 and 10(ii) of §3. Do all in "variable" notation, too.]
Use Theorem 1 for a new proof of the "only if " in Problem 9 in §3.
[Hint: Set fi=g∘f, where g(→x)=xi (the ith "projection map") is a monomial. Verify!]
Do Problem 8(I) in §3 for the case E′=E2(C2), with
f(→x)=x1 and g(→x)=x2.
(Simplify!) Then do the general case as in Problem 6 above, with
G(→y)=y1y2.
Use Theorem 2 for a new proof of Theorem 4 in Chapter 5, §1. (Proceed as in Problems 6 and 8, with E′=E1, so that D1h=h′). Do it in the "variable" notation, too.
Under proper differentiability assumptions, use formula (8') to express the partials of u if
(i) u=g(x,y),x=f(r)h(θ),y=r+h(θ)+θf(r);
(ii) u=g(r,θ),r=f(x+f(y)),θ=f(xf(y));
(iii) u=g(xy,yz,zx+y).
Then redo all in the "mapping" terminology, too.
Let the map g:E1→E1 be differentiable on E1. Find |∇h(→p)| if
h=g∘f and
(i) f(→x)=∑nk=1xk,→x∈En;
(ii) f(→x)=|→x|2,→x∈En.
(Euler's theorem.) A map f:En→E1 (or Cn→C) is called homogeneous of degree m on G iff
(∀t∈E1(C))f(t→x)=tmf(→x)
when →x,t→x∈G. Prove the following statements.
(i) If so, and f is differentiable at →p∈G (an open globe), then
→p⋅∇f(→p)=mf(→p).
*(ii) Conversely, if the latter holds for all →p∈G and if →0∉G, then f is homogeneous of degree m on G.
(iii) What if →0∈G?
[Hints: (i) Let g(t)=f(t→p). Find g′(1). (iii) Take f(x,y)=x2y2 if x≤0,f=0 if x>0,G=G0(1).]
Try Problem 12 for f:E′→E, replacing →p⋅∇f(→p) by df(→p;→p).
With all as in Theorem 1, prove the following.
(i) If E′=E1 and →s=f′(p)≠→0, then h′(p)=D→sg(→q).
(ii) If →u and →v are nonzero in E′ and a→u+b→v≠→0 for some scalars a,b, then
Da→u+b→vf(→p)=aD→uf(→p)+bD→vf(→p).
(iii) If f is differentiable on a globe G→p, and →u≠→0 in E′, then
D→uf(→p)=lim→x→→uD→x(→p).
[Hints: Use Theorem 2(ii) from §3 and Note 1.]
Use Theorem 2 to find the partially derived functions of f, if
(i) f(x,y,z)=(sin(xy/z))x;
(ii) f(x,y)=logx|tan(y/x)|.
(Set f=0 wherever undefined.)