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Mathematics LibreTexts

3.6: Irrational Numbers

  • Page ID
    129526
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    A painting shows Pythagoreans' hymn to the rising sun.
    Figure 3.28 The Pythagoreans were a philosophical sect of ancient Greece, often associated with mathematics. (credit: Fedor Andreevich Bronnikov (1827-1902) “Hymn of the Pythagoreans to the Rising Sun,” 1877, oil on canvas/Wikimedia, public domain)

    Learning Objectives

    After completing this section, you should be able to:

    1. Define and identify numbers that are irrational.
    2. Simplify irrational numbers and express in lowest terms.
    3. Add and subtract irrational numbers.
    4. Multiply and divide irrational numbers.
    5. Rationalize fractions with irrational denominators.

    The Pythagoreans were a philosophical sect in ancient Greece. Their philosophy included reincarnation and purifying the mind through the study and contemplation of mathematics and science. One of their principles was the cosmos is ruled by order, specifically mathematics and music. They even held mystic beliefs about specific numbers and figures. For example, the number 1 was associated with the mind and essence. Four represented justice, as it is the first product of two even numbers. Most famously, though, is the association with the Pythagorean Theorem, which states that in a right triangle, the sum of the squares of the shorter sides of the triangle (the legs) equals the square of the longer side (the hypotenuse). Even the ancient Egyptians used this relationship, as triangles with side measures 3, 4, and 5 were often used in surveying following the flooding of the Nile.

    There is a story of a Pythagorean, Hippasus, discovering that not all numbers could be expressed as fractions. In other words, not all numbers were rational numbers. The story ends with Hippasus, who shared this, or in some versions discovered it, put to death by drowning for sharing this fact, that not all quantities could be expressed as the ratio of two natural numbers.

    As colorful as that story may be, it is most likely false, as there are no contemporary sources to corroborate it. But it does seem to mark the discovery that not all quantities or measures were fractions of numbers. And so, irrational numbers were discovered.

    Video

    The Philosophy of the Pythagoreans

    Defining and Identifying Numbers That Are Irrational

    We defined rational numbers in the last section as numbers that could be expressed as a fraction of two integers. Irrational numbers are numbers that cannot be expressed as a fraction of two integers. Recall that rational numbers could be identified as those whose decimal representations either terminated (ended) or had a repeating pattern at some point. So irrational numbers must be those whose decimal representations do not terminate or become a repeating pattern.

    One collection of irrational numbers is square roots of numbers that aren’t perfect squares. xx is the square root of the number aa, denoted aa, if x2=ax2=a. The number aa is the perfect square of the integer nn if a=n2a=n2. The rational number abab is a perfect square if both aa and bb are perfect squares.

    One method of determining if an integer is a perfect square is to examine its prime factorization. If, in that factorization, all the prime factors are raised to even powers, the integer is a perfect square. Another method is to attempt to factor the integer into an integer squared. It is possible that you recognize the number as a perfect square (such as 4 or 9). Or, if you have a calculator at hand, use the calculator to determine if the square root of the integer is an integer.

    Example 3.84

    Identifying Perfect Squares

    Determine which of the following are perfect squares.

    1. 45
    2. 81
    3. 928928
    4. 144400144400
    Answer

    1. The prime factorization of 45 is 45=32×545=32×5. Since the 5 is not raised to an even power, 45 is not a perfect square.
    2. The prime factorization of 81 is 3434. All the prime factors are raised to even powers, so 81 is a perfect square.
    3. We must determine if both the numerator and denominator of 928928 are perfect squares for the rational number to be a perfect square. The numerator is 9, and as mentioned above, 9 is a perfect square (it is 3 squared). Now we check the prime factorization of the denominator, 28, which is 28=22×728=22×7. Since 7 is not raised to an even power, 28 is not a perfect square. Since the denominator is not a perfect square, 928928 is not a perfect square.
    4. We must determine if both the numerator and denominator of 144400144400 are perfect squares for the rational number to be a perfect square. The numerator is 144. The prime factorization of 144 is 144=24×32144=24×32. Since all the prime factors of 144 are raised to even powers, 144 is a perfect square. Now we check the prime factorization of the denominator, 400, which is 400=24×52400=24×52. Since all the prime factors of 400 are raised to even powers, 400 is a perfect square. Since the numerator and denominator of 144400144400 are perfect squares, 144400144400 is a perfect square.

    Your Turn 3.84

    Determine which of the following are perfect squares.
    1.
    36
    2.
    27
    3.
    /**/\frac{9}49/**/
    4.
    /**/\frac12221/**/

    Tech Check

    Using Desmos to Determine if a Number Is a Perfect Square

    Desmos may be used to determine if a number is a perfect square by using its square root function. When Desmos is opened, there is a tab in the lower left-hand corner of the Desmos screen. This tab opens the Desmos keypad, shown in Figure 3.29.

    Desmos keyboard is displayed. Three sets of keys are displayed. The first set has 4 rows of 4 keys, each. Row 1: x, y, a squared, and a to the power b. Row 2: open parenthesis, close parenthesis, lesser than, and greater than. Row 3: modulus of a, comma, lesser than or equal to, and greater than or equal to. Row 4: A B C, sound, square root, which is circled, and pi. The second set has 4 rows of 4 keys, each. Row 1: 7, 8, 9, and division symbol. Row 2: 4, 5, 6, and multiplication symbol. Row 3: 1, 2, 3, and minus symbol. Row 4: 0, dot, equals sign, and plus sign. The third set has the following keys: functions, left arrow, right arrow, close, and back.
    Figure 3.29 Desmos keyboard with square root key circles

    There you find the key for the square root, which is circled in Figure 3.29. To find the square root of a number, click the square root key, which begins a calculation, and then enter the value for which you want a square root. If the result is an integer, then the number is a perfect square.

    Video

    Using Desmos to Find the Square Root of a Number

    Another collection of irrational numbers is based on the special number, pi, denoted by the Greek letter πFigure 3.30).

    A circle with its radius, diameter, and circumference labeled.
    Figure 3.30 Circle with radius, diameter, and circumference labeled

    Any multiple or power of ππ is an irrational number.

    Any number expressed as a rational number times an irrational number is an irrational number also. When an irrational number takes that form, we call the rational number the rational part, and the irrational number the irrational part. It should be noted that a rational number plus, minus, multiplied by, or divided by any irrational number is an irrational number.

    Example 3.85

    Identifying Irrational Numbers

    Identify which of the following numbers are irrational.

    1. 3535
    2. 0.15¯0.15¯
    3. 121121
    4. 4π4π
    Answer

    1. 35 can be factored as 5×75×7, showing that 35 is not the square of an integer or a rational number. This mean its square root is an irrational number.
    2. Since 0.15¯0.15¯ is a decimal with a repeating pattern, it is rational, so it is not an irrational number.
    3. 121=112121=112. Since 121 is the square of an integer, its square root is a rational number.
    4. Since 4π4π is a multiple of pi, it is irrational. In this case, the rational part of the number is 4, while the irrational part is ππ.

    Your Turn 3.85

    Identify which of the following numbers are irrational.
    1.
    /**/\sqrt {225}/**/
    2.
    /**/3\sqrt 5/**/
    3.
    /**/\sqrt {80}/**/
    4.
    /**/20 - 3\pi/**/

    Who Knew?

    Euler-Mascheroni Constant

    Determining if a number is rational or irrational is not trivial. There are numbers that defied such classification for quite a long time. One such is the Euler-Mascheroni constant. The Euler-Mascheroni constant is used in mathematics, and is primarily associated with the natural logarithm, which is a mathematical function. The constant has been around since around 1790. However, it was unknown if this constant was rational or irrational until 2013, at which point it was proven to be irrational.

    Simplifying Square Roots and Expressing Them in Lowest Terms

    To simplify a square root means that we rewrite the square root as a rational number times the square root of a number that has no perfect square factors. The act of changing a square root into such a form is simplifying the square root.

    The number inside the square root symbol is referred to as the radicand. So in the expression aa the number aa is referred to as the radicand.

    Before discussing how to simplify a square root, we need to introduce a rule about square roots. The square root of a product of numbers equals the product of the square roots of those number. Written symbolically, a×b=a×ba×b=a×b.

    FORMULA

    For any two numbers aa and b b, a×b=a×ba×b=a×b.

    Using this formula, we can factor an integer inside a square root into a perfect square times another integer. Then the square root can be applied to the perfect square, leaving an integer times the square root of another integer. If the number remaining under the square root has no perfect square factors, then we’ve simplified the irrational number into lowest terms. To simplify the irrational number into lowest terms when nn is an integer:

    Step 1: Determine the largest perfect square factor of nn, which we denote a2a2.

    Step 2: Factor nn into a2×ba2×b.

    Step 3: Apply a2×b=a2×ba2×b=a2×b.

    Step 4: Write nn in its simplified form, abab.

    When a square root has been simplified in this manner, aa is referred to as the rational part of the number, and bb is referred to as the irrational part.

    Example 3.86

    Simplifying a Square Root

    Simplify the irrational number 180180 and express in lowest terms. Identify the rational and irrational parts.

    Answer

    Begin by finding the largest perfect square that is a factor of 180. We can do this by writing out the factor pairs of 180:

    1 × 180 2 × 90 3 × 60 4 × 45 5 × 36 6 × 30 9 × 20 10 × 18 12 × 15 1 × 180 2 × 90 3 × 60 4 × 45 5 × 36 6 × 30 9 × 20 10 × 18 12 × 15

    Looking at the list of factors, the perfect squares are 4, 9, and 36. The largest is 36, so we factor the into 36×5=62×536×5=62×5. In the formula, a=6a=6 and b=5b=5. Apply a2×b=a2×ba2×b=a2×b.

    6 2 × 5 = 6 2 × 5 6 2 × 5 = 6 2 × 5

    The simplified form of 180180 is 6565. In this example, the 6 is the rational part, and the 55 is the irrational part.

    Your Turn 3.86

    1.
    Simplify the irrational number /**/\sqrt {550}/**/ and express in lowest terms. Identify the rational and irrational parts.

    Video

    Simplifying Square Roots

    Example 3.87

    Simplifying a Square Root

    Simplify the irrational number 330330 and express in lowest terms. Identify the rational and irrational parts.

    Answer

    Begin by finding the largest perfect square that is a factor of 330. We can do this by writing out the factor pairs of 330:

    1 × 330 2 × 165 3 × 110 5 × 66 6 × 55 10 × 33 11 × 30 15 × 22 1 × 330 2 × 165 3 × 110 5 × 66 6 × 55 10 × 33 11 × 30 15 × 22

    Looking at the list of factors, there are no perfect squares other than 1, which means 330330 is already expressed in lowest terms. In this case, 1 is the rational part, and 330330 is the irrational part. Though we could write this as 13301330, but the product of 1 and any other number is just the number.

    Your Turn 3.87

    1.
    Simplify the irrational number /**/\sqrt {733}/**/ and express in lowest terms. Identify the rational and irrational parts.

    Example 3.88

    Simplifying a Square Root

    Simplify the irrational number 2,5482,548 and express in lowest terms. Identify the rational and irrational parts.

    Answer

    Begin by finding the largest perfect square that is a factor of 2,548. We can do this by writing out the factor pairs of 2,548:

    1 × 2548 2 × 1274 4 × 637 7 × 364 13 × 196 14 × 182 26 × 98 28 × 91 49 × 52 1 × 2548 2 × 1274 4 × 637 7 × 364 13 × 196 14 × 182 26 × 98 28 × 91 49 × 52

    Looking at the list of factors, the perfect squares are 4, 49, and 196. The largest is 196, so we factor the 2,548 into 196×13=142×13196×13=142×13. In the formula, a=14a=14 and b=5b=5. Apply a2×b=a2×ba2×b=a2×b.

    14 2 × 13 = 14 2 × 13 14 2 × 13 = 14 2 × 13

    The simplified form of 2,5482,548 is 14131413. In this example, 14 is the rational part, and 1313 is the irrational part.

    Your Turn 3.88

    1.
    Simplify the irrational number /**/\sqrt {\text{1,815}}/**/.

    Video

    Simplifying Square Roots

    Adding and Subtracting Irrational Numbers

    Just like any other number we’ve worked with, irrational numbers can be added or subtracted. When working with a calculator, enter the operation and a decimal representation will be given. However, there are times when two irrational numbers may be added or subtracted without the calculator. This can happen only when the irrational parts of the irrational numbers are the same.

    To add or subtract two irrational numbers that have the same irrational part, add or subtract the rational parts of the numbers, and then multiply that by the common irrational part.

    FORMULA

    Let our first irrational number be a×xa×x, where aa is the rational and xx the irrational parts.

    Let the other irrational number be b×xb×x, where bb is the rational and xx the irrational parts.

    Then a×x±b×x=(a±b)×xa×x±b×x=(a±b)×x.

    Example 3.89

    Subtracting Irrational Numbers with Similar Irrational Parts

    If possible, subtract the following irrational numbers without using a calculator. If this is not possible, state why.

    37873787

    Answer

    Since these two irrational numbers have the same irrational part, 77, we can subtract without using a calculator. The rational part of the first number is 3. The rational part of the second number is 8. Using the formula yields 3787=(38)×7=573787=(38)×7=57.

    Your Turn 3.89

    1.

    If possible, subtract the following irrational numbers without using a calculator. If this is not possible, state why.

    /**/41\sqrt {15} - 23\sqrt {15}/**/

    Example 3.90

    Adding Irrational Numbers with Similar Irrational Parts

    If possible, add the following irrational numbers without using a calculator. If this is not possible, state why.

    35π+17π35π+17π

    Answer

    Since these two irrational numbers have the same irrational part, ππ, the addition can be performed without using a calculator. The rational part of the first number is 35. The rational part of the second number is 17. Using the formula yields 35π+17π=(35+17)×π=52π35π+17π=(35+17)×π=52π.

    Your Turn 3.90

    1.
    If possible, add the following irrational numbers without using a calculator. If this is not possible, state why.
    /**/4.1\pi + 3.2\pi/**/

    Example 3.91

    Subtracting Irrational Numbers with Different Irrational Parts

    If possible, subtract the following irrational numbers without using a calculator. If this is not possible, state why.

    1935.671935.67

    Answer

    The two numbers being subtracted do not have the same irrational part, so the operation cannot be performed.

    Your Turn 3.91

    1.
    If possible, subtract the following irrational numbers without using a calculator. If this is not possible, state why. /**/2.1\sqrt {45} - 3.7\sqrt 5/**/

    Multiplying and Dividing Irrational Numbers

    Just like any other number that we’ve worked with, irrational numbers can be multiplied or divided. When working with a calculator, enter the operation and a decimal representation will be given. Sometimes, though, you may want to retain the form of the irrational number as a rational part times an irrational part. The process is similar to adding and subtracting irrational numbers when they are in this form. We do not need the irrational parts to match. Even though they need not match, they do need to be similar, such as both irrational parts are square roots, or both irrational parts are multiples of pi. Also, if the irrational parts are square roots, we may need to reduce the resulting square root to lowest terms.

    When multiplying two square roots, use the following formula. It is the same formula presented during the discussion of simplifying square roots.

    FORMULA

    For any two positive numbers aa and bb, a×b=a×ba×b=a×b.

    When dividing two square roots, use the following formula.

    FORMULA

    For any two positive numbers aa and bb, with bb not equal to 0, a÷b=ab=aba÷b=ab=ab.

    To multiply or divide irrational numbers with similar irrational parts, do the following:

    Step 1: Multiply or divide the rational parts.

    Step 2: If necessary, reduce the result of Step 1 to lowest terms. This becomes the rational part of the answer.

    Step 3: Multiply or divide the irrational parts.

    Step 4: If necessary, reduce the result from Step 3 to lowest terms. This becomes the irrational part of the answer.

    Step 5: The result is the product of the rational and irrational parts.

    Example 3.92

    Dividing Irrational Numbers with Similar Irrational Parts

    Perform the following operations without a calculator. Simplify if possible.

    1. 315÷(83)315÷(83)
    2. 14.7135÷(35)14.7135÷(35).
    Answer

    1. In this division problem, 315÷(83)315÷(83), notice that the irrational parts of these numbers are similar. They are both square roots, so follow the steps given above.

      Step 1: Divide the rational parts. 3÷8=383÷8=38

      Step 2: If necessary, reduce the result of Step 1 to lowest terms. The 3 and 8 have no common factors, so 3838 is already in lowest terms.

      Step 3: Divide the irrational parts. 15÷3=153=15315÷3=153=153

      Step 4: If necessary, reduce the result from Step 3 to lowest terms. The radicand can be reduced, which yields 55.

      Step 5: The result is the product of the rational and irrational parts, which is 385385.

    2. In this division problem, 14.7135÷(35)14.7135÷(35), notice that the irrational parts of these numbers are similar. They are both square roots, so follow the steps given above.

      Step 1: Divide the rational parts. 14.7÷3=4.914.7÷3=4.9

      Step 2: If necessary, reduce the result of Step 1 to lowest terms. This rational number is expressed as a decimal so will not be reduced.

      Step 3: Divide the irrational parts. 135÷5=1355=1355135÷5=1355=1355

      Step 4: If necessary, reduce the result from Step 3 to lowest terms. The radicand can be reduced, which yields 1355=27=9×3=331355=27=9×3=33.

      Step 5: The result is the product of the rational and irrational parts, which is 4.9×33=14.734.9×33=14.73.

    Your Turn 3.92

    Perform the following operations without a calculator. Simplify if possible.
    1.
    /**/84\sqrt {132} \div \left(14\sqrt {11} \right)/**/
    2.
    /**/57\sqrt {792} \div \left(25\sqrt {2}\right)/**/

    Example 3.93

    Multiplying Irrational Numbers with Similar Irrational Parts

    Perform the following operations without a calculator. Simplify if possible.

    1. (193)×(5.612) (193)×(5.612)
    2. 13π×8π 13π×8π
    Answer

    1. In this multiplication problem, (193)×(5.612)(193)×(5.612), notice that the irrational parts of these numbers are similar. They are both square roots. Follow the process above.

      Step 1: Multiply the rational parts. 19×5.6=106.419×5.6=106.4

      Step 2: If necessary, reduce the result of Step 1 to lowest terms. This rational number is expressed as a decimal and will not be reduced.

      Step 3: Multiply the irrational parts. 3×12=3×12=363×12=3×12=36

      Step 4: If necessary, reduce the result from Step 3 to lowest terms. The radicand is 36, which is the square of 6. The irrational part reduces to 36=636=6.

      Step 5: The result is the product of the rational and irrational parts, which is 106.4×6=638.4106.4×6=638.4.

      Notice that sometimes multiplying or dividing irrational numbers can result in a rational number.

    2. In this multiplication problem, 13π×8π13π×8π, notice that the irrational parts of these numbers are the same, ππ. Follow the process above.

      Step 1: Multiply the rational parts. 13×8=10413×8=104

      Step 2: If necessary, reduce the result of Step 1 to lowest terms. That result is an integer.

      Step 3: Multiply the irrational parts. π×π=π2π×π=π2

      Step 4: If necessary, reduce the result from Step 3 to lowest terms. This cannot be reduced.

      Step 5: The result is the product of the rational and irrational parts, which is 104π2104π2.

    Your Turn 3.93

    Perform the following operations without a calculator. Simplify if possible.
    1.
    /**/\left( {1.2\sqrt {21} } \right) \times \left( {4.5\sqrt {14} } \right)/**/
    2.
    /**/38\pi \div \left(2\pi \right)/**/

    Rationalizing Fractions with Irrational Denominators

    Fractions often represent that some amount is being equally divided into some number of parts. But to conceptualize a fraction in that manner, the denominator needs to be an integer. An irrational number in the denominator interferes with that interpretation of a fraction. Fractions that have denominators that are just the square root of an integer can be altered into fractions with integer denominators using a process called rationalizing the denominator. The process relies on the following property of square roots: a×a=aa×a=a and the following property of fractions: ab=acbcab=acbc for any non-zero number cc.

    Using these two properties, when a fraction has a square root in the denominator, we can eliminate that square root. Multiply the numerator and denominator by that square root from the denominator, ab=abb×bab=abb×b. Then apply a×a=aa×a=a to the denominator, yielding abb×b=abbabb×b=abb. Notice that there is no longer a square root in the denominator, which allows for interpreting the fraction as dividing a whole into equal parts.

    Video

    Rationalizing the Denominator

    Example 3.94

    Rationalizing the Denominator

    Rationalize the denominator of the following:

    1. 5757
    2. 3621036210
    Answer

    1. The square root in the denominator is 77. In order to rationalize the denominator of 5757, we need to multiply the numerator and denominator by 77 and simplify.
      57=577×7=57757=577×7=577
      The square root is in simplified form, so the final answer is 577577.
    2. The square root in the denominator is 1010.
      Step 1: In order to rationalize the denominator of 3621036210, we need to multiply the numerator and denominator by 1010 and simplify.
      36210=36×10210×10=3602×10=3602036210=36×10210×10=3602×10=36020

      Step 2: The 60 under the square root can be factored into the following factor pairs:

      1×602×303×204×155×126×101×602×303×204×155×126×10

      Step 3: The largest square factor of 60 is 4, so we simplify the 6060 in the numerator into 215215. We also cancel any common factors.

      36020=3×21520=61520=3151036020=3×21520=61520=31510

      This is completely simplified.

    Your Turn 3.94

    Rationalize the denominator of the following:
    1.
    /**/\frac24
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    /**/
    2.
    /**/\frac
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    /**/

    There are occasions when the denominator is irrational but is the sum of two numbers where one or both involve square roots. For instance, 54+354+3. The process used earlier required that the denominator was the square root of a number and would not work here. However, this type of denominator can be rationalized. In order to rationalize such a denominator, we will multiply the numerator and denominator of the fraction by the conjugate of the denominator. The conjugate of a+ba+b is abab. We say that a+ba+b and abab are conjugate numbers.

    So, the conjugate of 3+103+10 is just 310310. But why is this of interest? The reason is because it leads to the difference of squares formula, which is used to factor the difference of two squares. Or, for our purposes, in reverse it allows us to eliminate a square root.

    FORMULA

    For any two numbers, aa and bb, a2b2=(ab)(a+b)a2b2=(ab)(a+b).

    Looking at that formula, you should see that the two factors on the right-hand side of the equals sign are conjugates of one another. So, for our purposes, we’re interested in (ab)(a+b)=a2b2(ab)(a+b)=a2b2. This tells us that when we multiply a+ba+b by its conjugate, we get aa squared minus bb squared, or a2b2a2b2. But how is this useful? Let’s return to the fraction above, 54+354+3. The denominator is 4+34+3. Its conjugate is 4343. According to the formula, and letting a=4a=4 and b=3b=3, we see that (4+3)(43)=42(3)2(4+3)(43)=42(3)2. But (3)2(3)2 is just 3. That means the product is 163163 or 13. This no longer has a square root. We use this to rationalize the denominator.

    We will also need the distributive property of numbers.

    FORMULA

    For any three numbers aa, bb, and cc, a×(b±c)=a×b±a×ca×(b±c)=a×b±a×c. This is called the distributive property.

    Example 3.95

    Rationalizing the Denominator Using Conjugates

    Rationalize the denominator of 46+10 46+10.

    Answer

    Step 1: We recognize that the denominator is the sum of two numbers where one or both involve square roots. This means the conjugate can be used to remove the square root from the denominator.

    Step 2: To do so, we multiply the numerator and the denominator each by the conjugate of the denominator. Since the denominator is 6+106+10, the conjugate we will use is 610610.

    Step 3: The conjugate is multiplied by the numerator and the denominator.

    4 6 + 10 × 6 10 6 10 4 6 + 10 × 6 10 6 10

    Step 4: Remembering how a number times its conjugate works, this becomes

    46+10×610610=4×(610)62(10)246+10×610610=4×(610)62(10)2.

    Step 5: In the numerator, we apply the distributive property. Using it yields
    4×(610)62(10)2=244103610=24410264×(610)62(10)2=244103610=2441026.

    Step 6: Notice that the denominator no longer contains a square root. It has been rationalized. If desired, this can then be written as a rational number minus an irrational number, by recalling that abc=acbcabc=acbc.

    Applying that to the answer, we have 46+10=2441026=24264102646+10=2441026=242641026.

    Step 7: With a bit of cancellation, this reduces to 46+10=242641026=12132101346+10=242641026=121321013.

    Your Turn 3.95

    1.
    Rationalize the denominator of /**/\frac15
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    /**/
    .

    Video

    Rationalizing the Denominator

    Check Your Understanding

    29.
    Simplify the following square root: /**/\sqrt {500}/**/.
    30.
    Perform the following operation: /**/3\sqrt 7 - 10\sqrt 7/**/.
    31.
    Perform the following operation: /**/8\sqrt {10} \times 3\sqrt 2/**/.
    32.
    Rationalize the denominator of the following: /**/\frac{4}
    ParseError: invalid DekiScript (click for details)
    Callstack:
        at (Bookshelves/Applied_Mathematics/Contemporary_Mathematics_(OpenStax)/03:_Real_Number_Systems_and_Number_Theory/3.06:__Irrational_Numbers), /content/body/div[9]/div/div/div[3]/div[2]/div[4]/div/div/span/span, line 1, column 1
    
    /**/
    .

    Section 3.5 Exercises

    1.
    Identify which of the following numbers are irrational:
    /**/\sqrt {441}/**/, 4.33, /**/\sqrt {70}/**/, /**/5 + 9\pi/**/
    2.
    Identify which of the following numbers are irrational:
    /**/\frac13
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    Callstack:
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    /**/
    , /**/4 + 13\pi/**/, /**/\sqrt {144}/**/, /**/\frac{5}{9}/**/
    For the following exercises, simplify the square root by expressing it in lowest terms.
    3.
    /**/\sqrt {12}/**/
    4.
    /**/\sqrt {75}/**/
    5.
    /**/\sqrt {605}/**/
    6.
    /**/\sqrt {45}/**/
    7.
    /**/\sqrt {112}/**/
    8.
    /**/\sqrt {396}/**/
    9.
    /**/\sqrt {\text{2,940}}/**/
    10.
    /**/\sqrt {\text{2,400}}/**/
    11.
    /**/\sqrt {\text{3,240}}/**/
    12.
    /**/\sqrt {\text{5,472}}/**/
    For the following exercises, perform the arithmetic operations without a calculator, if possible. If it is not possible, state why.
    13.
    /**/4\sqrt 3 + 2\sqrt 3/**/
    14.
    /**/8\sqrt 5 + 3\sqrt 5/**/
    15.
    /**/9\sqrt 7 - 15\sqrt 7/**/
    16.
    /**/\sqrt {13} - 15\sqrt {13}/**/
    17.
    /**/8\pi - 13\sqrt 2/**/
    18.
    /**/7\sqrt 5 + 6\sqrt {14}/**/
    19.
    /**/7.2\pi + 8.6\pi/**/
    20.
    /**/14.5\pi - 5.8\pi/**/
    21.
    /**/19.8\sqrt {12} - 6.1\sqrt 3/**/
    22.
    /**/7.3\sqrt {45} - 6.8\sqrt {20}/**/
    23.
    /**/\left( {4\sqrt {15} } \right) \times \left( {3\sqrt {10} } \right)/**/
    24.
    /**/\left( {7\sqrt {33} } \right) \times \left( {8\sqrt {66} } \right)/**/
    25.
    /**/\left( {4.5\sqrt {154} } \right) \div \left( {3\sqrt {77} } \right)/**/
    26.
    /**/\left( {70\sqrt {30} } \right) \div \left( {14\sqrt 6 } \right)/**/
    For the following exercises, rationalize the denominators of the fractions, and then simplify.
    27.
    /**/\frac{3}
    ParseError: invalid DekiScript (click for details)
    Callstack:
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    /**/
    28.
    /**/\frac{8}
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    Callstack:
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    /**/
    29.
    /**/\frac{5}
    ParseError: invalid DekiScript (click for details)
    Callstack:
        at (Bookshelves/Applied_Mathematics/Contemporary_Mathematics_(OpenStax)/03:_Real_Number_Systems_and_Number_Theory/3.06:__Irrational_Numbers), /content/body/div[9]/div/div/div[3]/div[2]/div[33]/div/span/span, line 1, column 1
    
    /**/
    30.
    /**/\frac{9}
    ParseError: invalid DekiScript (click for details)
    Callstack:
        at (Bookshelves/Applied_Mathematics/Contemporary_Mathematics_(OpenStax)/03:_Real_Number_Systems_and_Number_Theory/3.06:__Irrational_Numbers), /content/body/div[9]/div/div/div[3]/div[2]/div[34]/div/span/span, line 1, column 1
    
    /**/
    31.
    /**/\frac12
    ParseError: invalid DekiScript (click for details)
    Callstack:
        at (Bookshelves/Applied_Mathematics/Contemporary_Mathematics_(OpenStax)/03:_Real_Number_Systems_and_Number_Theory/3.06:__Irrational_Numbers), /content/body/div[9]/div/div/div[3]/div[2]/div[35]/div/span/span[2], line 1, column 1
    
    /**/
    32.
    /**/\frac20
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    Callstack:
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    /**/
    33.
    Determine the conjugate of /**/5 + \sqrt 6/**/.
    34.
    Determine the conjugate of /**/10 - \sqrt {13}/**/.
    35.
    Determine the conjugate of /**/4 + 3\sqrt 5/**/.
    36.
    Determine the conjugate of /**/5\sqrt {15} + 8\sqrt {13}/**/.
    37.
    Find the product of /**/3 + 2\sqrt 7/**/ and its conjugate.
    38.
    Find the product of /**/2\sqrt {3 - } 5/**/ and its conjugate.
    For the following exercises, rationalize the denominator of the fraction, and then simplify the fraction.
    39.
    /**/\frac{4}
    ParseError: EOF expected (click for details)
    Callstack:
        at (Bookshelves/Applied_Mathematics/Contemporary_Mathematics_(OpenStax)/03:_Real_Number_Systems_and_Number_Theory/3.06:__Irrational_Numbers), /content/body/div[9]/div/div/div[3]/div[2]/div[43]/div[2]/div/span/span, line 1, column 3
    
    /**/
    40.
    /**/\frac{6}
    ParseError: EOF expected (click for details)
    Callstack:
        at (Bookshelves/Applied_Mathematics/Contemporary_Mathematics_(OpenStax)/03:_Real_Number_Systems_and_Number_Theory/3.06:__Irrational_Numbers), /content/body/div[9]/div/div/div[3]/div[2]/div[44]/div/span/span, line 1, column 2
    
    /**/
    41.
    /**/\frac-4
    ParseError: EOF expected (click for details)
    Callstack:
        at (Bookshelves/Applied_Mathematics/Contemporary_Mathematics_(OpenStax)/03:_Real_Number_Systems_and_Number_Theory/3.06:__Irrational_Numbers), /content/body/div[9]/div/div/div[3]/div[2]/div[45]/div/span/span[2], line 1, column 3
    
    /**/
    42.
    /**/\frac10
    ParseError: invalid DekiScript (click for details)
    Callstack:
        at (Bookshelves/Applied_Mathematics/Contemporary_Mathematics_(OpenStax)/03:_Real_Number_Systems_and_Number_Theory/3.06:__Irrational_Numbers), /content/body/div[9]/div/div/div[3]/div[2]/div[46]/div/span/span[2], line 1, column 1
    
    /**/

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