15.0: Chapter 1
- Page ID
- 129930
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A set with one member could contain any one of the following:
\(\{ {\text{Articuno}}\} {\text{, }}\{ {\text{Zapdos}}\} {\text{, }}\{ {\text{Moltres}}\} {\text{, or }}\{ {\text{Mewtwo}}\} \).
Any of the following combinations of three members would work:
\(\{ {\text{Articuno, Zapdos, Mewtwo}}\} \),\(\{ {\text{Articuno, Moltres, Mewtwo}}\} \), or \(\{ {\text{Zapdos, Moltres, Mewtwo}}\} \).
Serena also ordered a fish sandwich and chicken nuggets, because for the two sets to be equal they must contain the exact same items: {fish sandwich, chicken nuggets} = {fish sandwich, chicken nuggets}.
There are multiple possible solutions. Each set must contain two players, but both players cannot be the same, otherwise the two sets would be equal, not equivalent. For example, {Maria, Shantelle} and {Angie, Maria}.
Callstack:
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\(A \cap B = \{ 3,5,7\}\).
\(A \cup B = \{ 1,2,3,5,7,9\} \).
\(A \cap B' = \{ 1,9\} \).
\(n(A \cap B') = 2\).
\(n(B) = n(A{B^ + }) + n(A{B^ - }) + n({B^ + }) + n({B^ - }) = 14\)
\(n({B^\prime }) = n(U) - n(B) = 86\)
\(n(B \cup R{h^ + }) = 87\)
The left side of the equation is:
Check Your Understanding
Roster method: \(\{ \text{A, B, C, } \ldots \text{, Z}\},\) and set builder notation: \(\{ x|x{\text{ is a capital letter of the English alphabet}}\}\)
To be a subset of a set, every member of the subset must also be a member of the set. To be a proper subset, there must be at least one member of the set that is not also in the subset.
intersection
union
\(A \cup B\)
\(A \cap B\)
overlap
central
parentheses, complement