2.6E: Integrating Factors (Exercises)
( \newcommand{\kernel}{\mathrm{null}\,}\)
Q2.6.1
1.
- Verify that μ(x,y)=y is an integrating factor for ydx+(2x+1y)dy=0 on any open rectangle that does not intersect the x axis or, equivalently, that y2dx+(2xy+1)dy=0 is exact on any such rectangle.
- Verify that y≡0 is a solution of (B), but not of (A).
- Show that y(xy+1)=c is an implicit solution of (B), and explain why every differentiable function y=y(x) other than y≡0 that satisfies (C) is also a solution of (A).
2.
- Verify that μ(x,y)=1/(x−y)2 is an integrating factor for −y2dx+x2dy=0 on any open rectangle that does not intersect the line y=x or, equivalently, that −y2(x−y)2dx+x2(x−y)2dy=0 is exact on any such rectangle.
- Use Theorem 2.2.1 to show that xy(x−y)=c is an implicit solution of (B), and explain why it is also an implicit solution of (A)
- Verify that y=x is a solution of (A), even though it can’t be obtained from (C).
Q2.6.2
In Exercises 2.6.3-2.6.16 find an integrating factor; that is a function of only one variable, and solve the given equation.
3. ydx−xdy=0
4. 3x2ydx+2x3dy=0
5. 2y3dx+3y2dy=0
6. (5xy+2y+5)dx+2xdy=0
7. (xy+x+2y+1)dx+(x+1)dy=0
8. (27xy2+8y3)dx+(18x2y+12xy2)dy=0
9. (6xy2+2y)dx+(12x2y+6x+3)dy=0
10. y2dx+(xy2+3xy+1y)dy=0
11. (12x3y+24x2y2)dx+(9x4+32x3y+4y)dy=0
12. (x2y+4xy+2y)dx+(x2+x)dy=0
13. −ydx+(x4−x)dy=0
14. cosxcosydx+(sinxcosy−sinxsiny+y)dy=0
15. (2xy+y2)dx+(2xy+x2−2x2y2−2xy3)dy=0
16. ysinydx+x(siny−ycosy)dy=0
Q2.6.3
In Exercises 2.6.17-2.6.23 find an integrating factor of the form μ(x,y)=P(x)Q(y) and solve the given equation.
17. y(1+5ln|x|)dx+4xln|x|dy=0
18. (αy+γxy)dx+(βx+δxy)dy=0
19. (3x2y3−y2+y)dx+(−xy+2x)dy=0
20. 2ydx+3(x2+x2y3)dy=0
21. (acosxy−ysinxy)dx+(bcosxy−xsinxy)dy=0
22. x4y4dx+x5y3dy=0
23. y(xcosx+2sinx)dx+x(y+1)sinxdy=0
Q2.6.4
In Exercises 2.6.24-2.6.27 find an integrating factor and solve the equation. Plot a direction field and some integral curves for the equation in the indicated rectangular region.
24. (x4y3+y)dx+(x5y2−x)dy=0;{−1≤x≤1,−1≤y≤1}
25. (3xy+2y2+y)dx+(x2+2xy+x+2y)dy=0;{−2≤x≤2,−2≤y≤2}
26. (12xy+6y3)dx+(9x2+10xy2)dy=0;{−2≤x≤2,−2≤y≤2}
27. (3x2y2+2y)dx+2xdy=0;{−4≤x≤4,−4≤y≤4}
Q2.6.5
28. Suppose a, b, c, and d are constants such that ad−bc≠0, and let m and n be arbitrary real numbers. Show that
(axmy+byn+1)dx+(cxm+1+dxyn)dy=0
has an integrating factor μ(x,y)=xαyβ.
29. Suppose M, N, Mx, and Ny are continuous for all (x,y), and μ=μ(x,y) is an integrating factor for M(x,y)dx+N(x,y)dy=0.
Assume that μx and μy are continuous for all (x,y), and suppose y=y(x) is a differentiable function such that μ(x,y(x))=0 and μx(x,y(x))≠0 for all x in some interval I. Show that y is a solution of (A) on I.
30. According to Theorem 2.1.2, the general solution of the linear nonhomogeneous equation y′+p(x)y=f(x)
is y=y1x(c+∫f(x)/y1(x)dx),
where y1 is any nontrivial solution of the complementary equation y′+p(x)y=0. In this exercise we obtain this conclusion in a different way. You may find it instructive to apply the method suggested here to solve some of the exercises in Section 2.1.
- Rewrite (A) as [p(x)y−f(x)]dx+dy=0, and show that μ=±e∫p(x)dx is an integrating factor for (C).
- Multiply (A) through by μ=±e∫p(x)dx and verify that the resulting equation can be rewritten as (μ(x)y)′=μ(x)f(x). Then integrate both sides of this equation and solve for y to show that the general solution of (A) is y=1μ(x)(c+∫f(x)μ(x)dx). Why is this form of the general solution equivalent to (B)?