4.2E: Projections and Planes Exercises
- Page ID
- 132816
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solutions
2
Compute \(\mathbf{u}\bullet \mathbf{v}\) where:
- \(\mathbf{u} = \left[ \begin{array}{r} 2\\ -1\\ 3 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} -1\\ 1\\ 1 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} 1\\ 2\\ -1 \end{array} \right]\), \(\mathbf{v} = \mathbf{u}\)
- \(\mathbf{u} = \left[ \begin{array}{r} 1\\ 1\\ -3 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} 2\\ -1\\ 1 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} 3\\ -1\\ 5 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} 6\\ -7\\ -5 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} x\\ y\\ z \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} a\\ b\\ c \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} a\\ b\\ c \end{array} \right]\), \(\mathbf{v} = \mathbf{0}\)
- \(6\)
- \(0\)
- \(0\)
Find the angle between the following pairs of vectors.
- \(\mathbf{u} = \left[ \begin{array}{r} 1\\ 0\\ 3 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} 2\\ 0\\ 1 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} 3\\ -1\\ 0 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} -6\\ 2\\ 0 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} 7\\ -1\\ 3 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} 1\\ 4\\ -1 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} 2\\ 1\\ -1 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} 3\\ 6\\ 3 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} 1\\ -1\\ 0 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} 0\\ 1\\ 1 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} 0\\ 3\\ 4 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} 5\sqrt{2}\\ -7\\ -1 \end{array} \right]\)
- \(\pi\) or \(180^\circ\)
- \(\frac{\pi}{3}\) or \(60^\circ\)
- \(\frac{2\pi}{3}\) or \(120^\circ\)
Find all real numbers \(x\) such that:
- \(\left[ \begin{array}{r} 2\\ -1\\ 3 \end{array} \right]\) and \(\left[ \begin{array}{r} x\\ -2\\ 1 \end{array} \right]\) are orthogonal.
- \(\left[ \begin{array}{r} 2\\ -1\\ 1 \end{array} \right]\) and \(\left[ \begin{array}{r} 1\\ x\\ 2 \end{array} \right]\) are at an angle of \(\frac{\pi}{3}\).
- \(1\) or \(-17\)
Find all vectors \(\mathbf{v} = \left[ \begin{array}{r} x\\ y\\ z \end{array} \right]\) orthogonal to both:
- \(\mathbf{u}_{1} = \left[ \begin{array}{r} -1\\ -3\\ 2 \end{array} \right]\), \(\mathbf{u}_{2} = \left[ \begin{array}{r} 0\\ 1\\ 1 \end{array} \right]\)
- \(\mathbf{u}_{1} = \left[ \begin{array}{r} 3\\ -1\\ 2 \end{array} \right]\), \(\mathbf{u}_{2} = \left[ \begin{array}{r} 2\\ 0\\ 1 \end{array} \right]\)
- \(\mathbf{u}_{1} = \left[ \begin{array}{r} 2\\ 0\\ -1 \end{array} \right]\), \(\mathbf{u}_{2} = \left[ \begin{array}{r} -4\\ 0\\ 2 \end{array} \right]\)
- \(\mathbf{u}_{1} = \left[ \begin{array}{r} 2\\ -1\\ 3 \end{array} \right]\), \(\mathbf{u}_{2} = \left[ \begin{array}{r} 0\\ 0\\ 0 \end{array} \right]\)
- \(t \left[ \begin{array}{r} -1\\ 1\\ 2 \end{array} \right]\)
- \(s \left[ \begin{array}{r} 1\\ 2\\ 0 \end{array} \right] + t \left[ \begin{array}{r} 0\\ 3\\ 1 \end{array} \right]\)
Find two orthogonal vectors that are both orthogonal to \(\mathbf{v} = \left[ \begin{array}{r} 1\\ 2\\ 0 \end{array} \right]\).
Consider the triangle with vertices \(P(2, 0, -3)\), \(Q(5, -2, 1)\), and \(R(7, 5, 3)\).
- Show that it is a right-angled triangle.
- Find the lengths of the three sides and verify the Pythagorean theorem.
- \(29 + 57 = 86\)
Show that the triangle with vertices \(A(4, -7, 9)\), \(B(6, 4, 4)\), and \(C(7, 10, -6)\) is not a right-angled triangle.
Find the three internal angles of the triangle with vertices:
- \(A(3, 1, -2)\), \(B(3, 0, -1)\), and \(C(5, 2, -1)\)
- \(A(3, 1, -2)\), \(B(5, 2, -1)\), and \(C(4, 3, -3)\)
- \(A = B = C = \frac{\pi}{3}\) or \(60^\circ\)
Show that the line through \(P_{0}(3, 1, 4)\) and \(P_{1}(2, 1, 3)\) is perpendicular to the line through \(P_{2}(1, -1, 2)\) and \(P_{3}(0, 5, 3)\).
In each case, compute the projection of \(\mathbf{u}\) on \(\mathbf{v}\).
- \(\mathbf{u} = \left[ \begin{array}{r} 5\\ 7\\ 1 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} 2\\ -1\\ 3 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} 3\\ -2\\ 1 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} 4\\ 1\\ 1 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} 1\\ -1\\ 2 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} 3\\ -1\\ 1 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} 3\\ -2\\ -1 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} -6\\ 4\\ 2 \end{array} \right]\)
- \(\frac{11}{18}\mathbf{v}\)
- \(-\frac{1}{2}\mathbf{v}\)
In each case, write \(\mathbf{u} = \mathbf{u}_{1} + \mathbf{u}_{2}\), where \(\mathbf{u}_{1}\) is parallel to \(\mathbf{v}\) and \(\mathbf{u}_{2}\) is orthogonal to \(\mathbf{v}\).
- \(\mathbf{u} = \left[ \begin{array}{r} 2\\ -1\\ 1 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} 1\\ -1\\ 3 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} 3\\ 1\\ 0 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} -2\\ 1\\ 4 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} 2\\ -1\\ 0 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} 3\\ 1\\ -1 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} 3\\ -2\\ 1 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} -6\\ 4\\ -1 \end{array} \right]\)
- \(\frac{5}{21}\left[ \begin{array}{r} 2\\ -1\\ -4 \end{array} \right] + \frac{1}{21}\left[ \begin{array}{r} 53\\ 26\\ 20 \end{array} \right]\)
- \(\frac{27}{53}\left[ \begin{array}{r} 6\\ -4\\ 1 \end{array} \right] + \frac{1}{53}\left[ \begin{array}{r} -3\\ 2\\ 26 \end{array} \right]\)
Calculate the distance from the point \(P\) to the line in each case and find the point \(Q\) on the line closest to \(P\).
-
\(P(3,2-1) \quad\)
line: \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 2\\ 1\\ 3 \end{array} \right] +t \left[ \begin{array}{r} 3\\ -1\\ -2 \end{array} \right]\) -
\(P(1,-1,3) \quad\)
line: \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 1\\ 0\\ -1 \end{array} \right] +t \left[ \begin{array}{r} 3\\ 1\\ 4 \end{array} \right]\)
- \(\frac{1}{26}\sqrt{5642}\), \(Q(\frac{71}{26}, \frac{15}{26}, \frac{34}{26})\)
Compute \(\mathbf{u} \times \mathbf{v}\) where:
- \(\mathbf{u} = \left[ \begin{array}{r} 1\\ 2\\ 3 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} 1\\ 1\\ 2 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} 3\\ -1\\ 0 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} -6\\ 2\\ 0 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} 3\\ -2\\ 1 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} 1\\ 1\\ -1 \end{array} \right]\)
- \(\mathbf{u} = \left[ \begin{array}{r} 2\\ 0\\ -1 \end{array} \right]\), \(\mathbf{v} = \left[ \begin{array}{r} 1\\ 4\\ 7 \end{array} \right]\)
- \(\left[ \begin{array}{r} 0\\ 0\\ 0 \end{array} \right]\)
- \(\left[ \begin{array}{r} 4\\ -15\\ 8 \end{array} \right]\)
Find an equation of each of the following planes.
- Passing through \(A(2, 1, 3)\), \(B(3, -1, 5)\), and \(C(1, 2, -3)\).
- Passing through \(A(1, -1, 6)\), \(B(0, 0, 1)\), and \(C(4, 7, -11)\).
- Passing through \(P(2, -3, 5)\) and parallel to the plane with equation \(3x - 2y - z = 0\).
- Passing through \(P(3, 0, -1)\) and parallel to the plane with equation \(2x - y + z = 3\).
- Containing \(P(3, 0, -1)\) and the line \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 0\\ 0\\ 2 \end{array} \right] +t \left[ \begin{array}{r} 1\\ 0\\ 1 \end{array} \right].\)
- \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 3\\ -1\\ 2 \end{array} \right] +t \left[ \begin{array}{r} 1\\ 0\\ -1 \end{array} \right].\)
- \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 1\\ -1\\ 2 \end{array} \right] +t \left[ \begin{array}{r} 1\\ 1\\ 1 \end{array} \right]\) and \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 0\\ 0\\ 2 \end{array} \right] +t \left[ \begin{array}{r} 1\\ -1\\ 0 \end{array} \right]\).
- Containing the lines \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 3\\ 1\\ 0 \end{array} \right] +t \left[ \begin{array}{r} 1\\ -1\\ 3 \end{array} \right]\) and \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 0\\ -2\\ 5 \end{array} \right] +t \left[ \begin{array}{r} 2\\ 1\\ -1 \end{array} \right]\).
- Each point of which is equidistant from \(P(2, -1, 3)\) and \(Q(1, 1, -1)\).
- Each point of which is equidistant from \(P(0, 1, -1)\) and \(Q(2, -1, -3)\).
- \(-23x + 32y + 11z = 11\)
- \(2x - y + z = 5\)
- \(2x + 3y + 2z = 7\)
- \(2x - 7y - 3z = -1\)
- \(x - y - z = 3\)
In each case, find a vector equation of the line.
- Passing through \(P(3, -1, 4)\) and perpendicular to the plane \(3x - 2y - z = 0\).
- Passing through \(P(2, -1, 3)\) and perpendicular to the plane \(2x + y = 1\).
- Passing through \(P(0, 0, 0)\) and perpendicular to the lines \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 1\\ 1\\ 0 \end{array} \right] +t \left[ \begin{array}{r} 2\\ 0\\ -1 \end{array} \right]\) and \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 2\\ 1\\ -3 \end{array} \right] +t \left[ \begin{array}{r} 1\\ -1\\ 5 \end{array} \right]\).
- \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 2\\ 0\\ 1 \end{array} \right] +t \left[ \begin{array}{r} 1\\ 1\\ -2 \end{array} \right]\) and
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 5\\ 5\\ -2 \end{array} \right] +t \left[ \begin{array}{r} 1\\ 2\\ -3 \end{array} \right]\). - Passing through \(P(2, 1, -1)\), intersecting the line \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 1\\ 2\\ -1 \end{array} \right] +t \left[ \begin{array}{r} 3\\ 0\\ 1 \end{array} \right]\), and perpendicular to that line.
- Passing through \(P(1, 1, 2)\), intersecting the line \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 2\\ 1\\ 0 \end{array} \right] +t \left[ \begin{array}{r} 1\\ 1\\ 1 \end{array} \right]\), and perpendicular to that line.
- \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 2\\ -1\\ 3 \end{array} \right] +t \left[ \begin{array}{r} 2\\ 1\\ 0 \end{array} \right]\)
- \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 1\\ 1\\ -1 \end{array} \right] +t \left[ \begin{array}{r} 1\\ 1\\ 1 \end{array} \right]\)
- \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 1\\ 1\\ 2 \end{array} \right] +t \left[ \begin{array}{r} 4\\ 1\\ -5 \end{array} \right]\)
In each case, find the shortest distance from the point \(P\) to the plane and find the point \(Q\) on the plane closest to \(P\).
- \(P(2, 3, 0)\); plane with equation \(5x + y + z = 1\).
- \(P(3, 1, -1)\); plane with equation \(2x + y - z = 6\).
- \(\frac{\sqrt{6}}{3}\), \(Q(\frac{7}{3}, \frac{2}{3}, \frac{-2}{3})\)
- Does the line through \(P(1, 2, -3)\) with direction vector \(\mathbf{d} = \left[ \begin{array}{r} 1\\ 2\\ -3 \end{array} \right]\) lie in the plane \(2x - y - z = 3\)? Explain.
- Does the plane through \(P(4, 0, 5)\), \(Q(2, 2, 1)\), and \(R(1, -1, 2)\) pass through the origin? Explain.
- Yes. The equation is \(5x -3y - 4z = 0\).
Show that every plane containing \(P(1, 2, -1)\) and \(Q(2, 0, 1)\) must also contain \(R(-1, 6, -5)\).
Find the equations of the line of intersection of the following planes.
- \(2x -3y + 2z = 5\) and \(x + 2y - z = 4\).
- \(3x + y -2z = 1\) and \(x + y + z = 5\).
- \((-2, 7, 0) + t(3, -5, 2)\)
In each case, find all points of intersection of the given plane and the line \(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 1\\ -2\\ 3 \end{array} \right] +t \left[ \begin{array}{r} 2\\ 5\\ -1 \end{array} \right]\).
\(x -3y + 2z = 4\) \(2x - y - z = 5\) \(3x - y + z = 8\) \(-x -4y -3z = 6\)
- None
- \(P(\frac{13}{19}, \frac{-78}{19}, \frac{65}{19})\)
Find the equation of all planes:
-
Perpendicular to the line
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 2\\ -1\\ 3 \end{array} \right] +t \left[ \begin{array}{r} 2\\ 1\\ 3 \end{array} \right]\). -
Perpendicular to the line
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 1\\ 0\\ -1 \end{array} \right] +t \left[ \begin{array}{r} 3\\ 0\\ 2 \end{array} \right]\). - Containing the origin.
- Containing \(P(3, 2, -4)\).
- Containing \(P(1, 1, -1)\) and \(Q(0, 1, 1)\).
- Containing \(P(2, -1, 1)\) and \(Q(1, 0, 0)\).
-
Containing the line
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 2\\ 1\\ 0 \end{array} \right] +t \left[ \begin{array}{r} 1\\ -1\\ 0 \end{array} \right]\). -
Containing the line
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 3\\ 0\\ 2 \end{array} \right] +t \left[ \begin{array}{r} 1\\ -2\\ -1 \end{array} \right]\).
- \(3x + 2z = d\), \(d\) arbitrary
- \(a(x - 3) + b(y - 2) + c(z + 4) = 0\); \(a\), \(b\), and \(c\) not all zero
- \(ax + by + (b - a)z = a\); \(a\) and \(b\) not both zero
- \(ax + by + (a - 2b)z = 5a - 4b\); \(a\) and \(b\) not both zero
If a plane contains two distinct points \(P_{1}\) and \(P_{2}\), show that it contains every point on the line through \(P_{1}\) and \(P_{2}\).
Find the shortest distance between the following pairs of parallel lines.
-
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 2\\ -1\\ 3 \end{array} \right] +t \left[ \begin{array}{r} 1\\ -1\\ 4 \end{array} \right];\)
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 1\\ 0\\ 1 \end{array} \right] +t \left[ \begin{array}{r} 1\\ -1\\ 4 \end{array} \right]\) -
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 3\\ 0\\ 2 \end{array} \right] +t \left[ \begin{array}{r} 3\\ 1\\ 0 \end{array} \right];\)
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} -1\\ 2\\ 2 \end{array} \right] +t \left[ \begin{array}{r} 3\\ 1\\ 0 \end{array} \right]\)
- \(\sqrt{10}\)
Find the shortest distance between the following pairs of nonparallel lines and find the points on the lines that are closest together.
-
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 3\\ 0\\ 1 \end{array} \right] +s \left[ \begin{array}{r} 2\\ 1\\ -3 \end{array} \right];\)
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 1\\ 1\\ -1 \end{array} \right] +t \left[ \begin{array}{r} 1\\ 0\\ 1 \end{array} \right]\) -
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 1\\ -1\\ 0 \end{array} \right] +s \left[ \begin{array}{r} 1\\ 1\\ 1 \end{array} \right];\)
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 2\\ -1\\ 3 \end{array} \right] +t \left[ \begin{array}{r} 3\\ 1\\ 0 \end{array} \right]\) -
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 3\\ 1\\ -1 \end{array} \right] +s \left[ \begin{array}{r} 1\\ 1\\ -1 \end{array} \right];\)
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 1\\ 2\\ 0 \end{array} \right] +t \left[ \begin{array}{r} 1\\ 0\\ 2 \end{array} \right]\) -
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 1\\ 2\\ 3 \end{array} \right] +s \left[ \begin{array}{r} 2\\ 0\\ -1 \end{array} \right];\)
\(\left[ \begin{array}{r} x\\ y\\ z \end{array} \right] = \left[ \begin{array}{r} 3\\ -1\\ 0 \end{array} \right] +t \left[ \begin{array}{r} 1\\ 1\\ 0 \end{array} \right]\)
- \(\frac{\sqrt{14}}{2}\), \(A(3, 1, 2)\), \(B(\frac{7}{2}, -\frac{1}{2}, 3)\)
- \(\frac{\sqrt{6}}{6}\), \(A(\frac{19}{3}, 2, \frac{1}{3})\), \(B(\frac{37}{6}, \frac{13}{6}, 0)\)
Show that two lines in the plane with slopes \(m_{1}\) and \(m_{2}\) are perpendicular if and only if
\(m_{1}m_{2} = -1\). [Hint: Example [exa:011343].]
- Show that, of the four diagonals of a cube, no pair is perpendicular.
- Show that each diagonal is perpendicular to the face diagonals it does not meet.
- Consider the diagonal \(\mathbf{d} = \left[ \begin{array}{r} a\\ a\\ a \end{array} \right]\) The six face diagonals in question are \(\pm\left[ \begin{array}{r} a\\ 0\\ -a \end{array} \right]\), \(\pm\left[ \begin{array}{r} 0\\ a\\ -a \end{array} \right]\), \(\pm\left[ \begin{array}{r} a\\ -a\\ 0 \end{array} \right]\). All of these are orthogonal to \(\mathbf{d}\). The result works for the other diagonals by symmetry.
Given a rectangular solid with sides of lengths \(1\), \(1\), and \(\sqrt{2}\), find the angle between a diagonal and one of the longest sides.
Consider a rectangular solid with sides of lengths \(a\), \(b\), and \(c\). Show that it has two orthogonal diagonals if and only if the sum of two of \(a^{2}\), \(b^{2}\), and \(c^{2}\) equals the third.
The four diagonals are \((a, b, c)\), \((-a, b, c)\), \((a, -b, c)\) and \((a, b, -c)\) or their negatives. The dot products are \(\pm(-a^{2} + b^{2} + c^{2})\), \(\pm(a^{2} - b^{2} + c^{2})\), and \(\pm(a^{2} + b^{2} - c^{2})\).
Let \(A\), \(B\), and \(C(2, -1, 1)\) be the vertices of a triangle where \(\longvect{AB}\) is parallel to \(\left[ \begin{array}{r} 1\\ -1\\ 1 \end{array} \right]\), \(\longvect{AC}\) is parallel to \(\left[ \begin{array}{r} 2\\ 0\\ -1 \end{array} \right]\), and angle \(C = 90^\circ\). Find the equation of the line through \(B\) and \(C\).
If the diagonals of a parallelogram have equal length, show that the parallelogram is a rectangle.
Given \(\mathbf{v} = \left[ \begin{array}{r} x\\ y\\ z \end{array} \right]\) in component form, show that the projections of \(\mathbf{v}\) on \(\mathbf{i}\), \(\mathbf{j}\), and \(\mathbf{k}\) are \(x\mathbf{i}\), \(y\mathbf{j}\), and \(z\mathbf{k}\), respectively.
- Can \(\mathbf{u}\bullet \mathbf{v} = -7\) if \(\|\mathbf{u}\| = 3\) and \(\|\mathbf{v}\| = 2\)? Defend your answer.
- Find \(\mathbf{u}\bullet \mathbf{v}\) if \(\mathbf{u} = \left[ \begin{array}{r} 2\\ -1\\ 2 \end{array} \right]\), \(\| \mathbf{v} \| = 6\), and the angle between \(\mathbf{u}\) and \(\mathbf{v}\) is \(\frac{2\pi}{3}\).
Show \((\mathbf{u} + \mathbf{v})\bullet (\mathbf{u} - \mathbf{v}) = \|\mathbf{u}\|^{2} - \|\mathbf{v}\|^{2}\) for any vectors \(\mathbf{u}\) and \(\mathbf{v}\).
- Show \(\|\mathbf{u} + \mathbf{v}\|^{2} + \|\mathbf{u} - \mathbf{v}\|^{2} = 2(\|\mathbf{u}\|^{2} + \|\mathbf{v}\|^{2})\) for any vectors \(\mathbf{u}\) and \(\mathbf{v}\).
- What does this say about parallelograms?
- The sum of the squares of the lengths of the diagonals equals the sum of the squares of the lengths of the four sides.
Show that if the diagonals of a parallelogram are perpendicular, it is necessarily a rhombus. [Hint: Example [exa:011899].]
Let \(A\) and \(B\) be the end points of a diameter of a circle (see the diagram). If \(C\) is any point on the circle, show that \(AC\) and \(BC\) are perpendicular. [Hint: Express \(\longvect{AB}\bullet (\longvect{AB} \times \longvect{AC}) = 0\) and \(\longvect{BC}\) in terms of \(\mathbf{u} = \longvect{OA}\) and \(\mathbf{v} = \longvect{OC}\), where \(O\) is the centre.]
Show that \(\mathbf{u}\) and \(\mathbf{v}\) are orthogonal, if and only if \(\|\mathbf{u} + \mathbf{v}\|^{2} = \|\mathbf{u}\|^{2} + \|\mathbf{v}\|^{2}\).
Let \(\mathbf{u}\), \(\mathbf{v}\), and \(\mathbf{w}\) be pairwise orthogonal vectors.
- Show that \(\|\mathbf{u} + \mathbf{v} + \mathbf{w}\|^{2} = \|\mathbf{u}\|^{2} + \|\mathbf{v}\|^{2} + \|\mathbf{w}\|^{2}\).
- If \(\mathbf{u}\), \(\mathbf{v}\), and \(\mathbf{w}\) are all the same length, show that they all make the same angle with \(\mathbf{u} + \mathbf{v} + \mathbf{w}\).
- The angle \(\theta\) between \(\mathbf{u}\) and \((\mathbf{u} + \mathbf{v} + \mathbf{w})\) is given by \(\cos\theta = \frac{\mathbf{u}\bullet (\mathbf{u} + \mathbf{v} + \mathbf{w})}{\| \mathbf{u} \| \| \mathbf{u} + \mathbf{v} + \mathbf{w} \|} = \frac{\| \mathbf{u} \|}{\sqrt{\| \mathbf{u} \|^2 + \| \mathbf{v} \|^2 + \| \mathbf{w} \|^2}} = \frac{1}{\sqrt{3}}\) because \(\| \mathbf{u} \| = \| \mathbf{v} \| = \| \mathbf{w} \|\). Similar remarks apply to the other angles.
- Show that \(\mathbf{n} = \left[ \begin{array}{r} a\\ b \end{array} \right]\) is orthogonal to every vector along the line \(ax + by + c = 0\).
- [Hint: If \(P_{1}\) is on the line, project \(\mathbf{u} = \longvect{P_{1}P}_{0}\) on \(\mathbf{n}\).]
- Let \(\mathbf{p}_{0}\), \(\mathbf{p}_{1}\) be the vectors of \(P_{0}\), \(P_{1}\), so \(\mathbf{u} = \mathbf{p}_{0} - \mathbf{p}_{1}\). Then \(\mathbf{u} \cdot \mathbf{n} = \mathbf{p}_{0} \cdot \mathbf{n}\) – \(\mathbf{p}_{1} \cdot \mathbf{n} = (ax_{0} + by_{0}) - (ax_{1} + by_{1}) = ax_{0} + by_{0} + c\). Hence the distance is
\[\left\| \left( \frac{\mathbf{u}\bullet \mathbf{n}}{\| \mathbf{n} \|^2}\right)\mathbf{n} \right\| = \frac{|\mathbf{u}\bullet \mathbf{n}|}{\| \mathbf{n} \|} \nonumber \]
Assume \(\mathbf{u}\) and \(\mathbf{v}\) are nonzero vectors that are not parallel. Show that \(\mathbf{w} = \|\mathbf{u}\|\mathbf{v} + \|\mathbf{v}\|\mathbf{u}\) is a nonzero vector that bisects the angle between \(\mathbf{u}\) and \(\mathbf{v}\).
Let \(\alpha\), \(\beta\), and \(\gamma\) be the angles a vector \(\mathbf{v} \neq \mathbf{0}\) makes with the positive \(x\), \(y\), and \(z\) axes, respectively. Then \(\cos \alpha\), \(\cos \beta\), and \(\cos \gamma\) are called the direction cosines of the vector \(\mathbf{v}\).
- If \(\mathbf{v} = \left[ \begin{array}{r} a\\ b\\ c \end{array} \right]\), show that \(\cos\alpha = \frac{a}{\| \mathbf{v} \|}\), \(\cos\beta = \frac{b}{\| \mathbf{v} \|}\), and \(\cos\gamma= \frac{c}{\| \mathbf{v} \|}\).
- Show that \(\cos^{2} \alpha + \cos^2 \beta + \cos^2 \gamma = 1\).
- This follows from (a) because \(\|\mathbf{v}\|^{2} = a^{2} + b^{2} + c^{2}\).
Let \(\mathbf{v} \neq \mathbf{0}\) be any nonzero vector and suppose that a vector \(\mathbf{u}\) can be written as \(\mathbf{u} = \mathbf{p} + \mathbf{q}\), where \(\mathbf{p}\) is parallel to \(\mathbf{v}\) and \(\mathbf{q}\) is orthogonal to \(\mathbf{v}\). Show that \(\mathbf{p}\) must equal the projection of \(\mathbf{u}\) on \(\mathbf{v}\). [Hint: Argue as in the proof of Theorem [thm:011958].]
Let \(\mathbf{v} \neq \mathbf{0}\) be a nonzero vector and let \(a \neq 0\) be a scalar. If \(\mathbf{u}\) is any vector, show that the projection of \(\mathbf{u}\) on \(\mathbf{v}\) equals the projection of \(\mathbf{u}\) on \(a\mathbf{v}\).
- Show that the Cauchy-Schwarz inequality \(|\mathbf{u}\bullet \mathbf{v}| \leq \|\mathbf{u}\|\|\mathbf{v}\|\) holds for all vectors \(\mathbf{u}\) and \(\mathbf{v}\). [Hint: \(|\cos \theta| \leq 1\) for all angles \(\theta\).]
- [Hint: When is \(\cos \theta = \pm 1\)?]
- holds for all numbers \(x_{1}\), \(x_{2}\), \(y_{1}\), \(y_{2}\), \(z_{1}\), and \(z_{2}\).
- Show that \(|xy + yz + zx| \leq x^{2} + y^{2} + z^{2}\) for all \(x\), \(y\), and \(z\).
- Show that \((x + y + z)^{2} \leq 3(x^{2} + y^{2} + z^{2})\) holds for all \(x\), \(y\), and \(z\).
- Take \(\left[ \begin{array}{c} x_{1}\\ y_{1}\\ z_{1} \end{array} \right] = \left[ \begin{array}{c} x\\ y\\ z \end{array} \right]\) and \(\left[ \begin{array}{c} x_{2}\\ y_{2}\\ z_{2} \end{array} \right] = \left[ \begin{array}{c} y\\ z\\ x \end{array} \right]\) in (c).
Prove that the triangle inequality \(\| \mathbf{u} + \mathbf{v} \| \leq \|\mathbf{u}\| + \|\mathbf{v}\|\) holds for all vectors \(\mathbf{u}\) and \(\mathbf{v}\). [Hint: Consider the triangle with \(\mathbf{u}\) and \(\mathbf{v}\) as two sides.]