3.8: Supplements - Subspaces
- Page ID
- 45605
\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)
\( \newcommand{\dsum}{\displaystyle\sum\limits} \)
\( \newcommand{\dint}{\displaystyle\int\limits} \)
\( \newcommand{\dlim}{\displaystyle\lim\limits} \)
\( \newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\)
( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\)
\( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)
\( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\)
\( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)
\( \newcommand{\Span}{\mathrm{span}}\)
\( \newcommand{\id}{\mathrm{id}}\)
\( \newcommand{\Span}{\mathrm{span}}\)
\( \newcommand{\kernel}{\mathrm{null}\,}\)
\( \newcommand{\range}{\mathrm{range}\,}\)
\( \newcommand{\RealPart}{\mathrm{Re}}\)
\( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)
\( \newcommand{\Argument}{\mathrm{Arg}}\)
\( \newcommand{\norm}[1]{\| #1 \|}\)
\( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)
\( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\AA}{\unicode[.8,0]{x212B}}\)
\( \newcommand{\vectorA}[1]{\vec{#1}} % arrow\)
\( \newcommand{\vectorAt}[1]{\vec{\text{#1}}} % arrow\)
\( \newcommand{\vectorB}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\( \newcommand{\vectorC}[1]{\textbf{#1}} \)
\( \newcommand{\vectorD}[1]{\overrightarrow{#1}} \)
\( \newcommand{\vectorDt}[1]{\overrightarrow{\text{#1}}} \)
\( \newcommand{\vectE}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{\mathbf {#1}}}} \)
\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\(\newcommand{\longvect}{\overrightarrow}\)
\( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)
\(\newcommand{\ket}[1]{\left| #1 \right>}\)
\(\newcommand{\bra}[1]{\left< #1 \right|}\)
\(\newcommand{\braket}[2]{\left< #1 \vphantom{#2} \right| \left. #2 \vphantom{#1} \right>}\)
\(\newcommand{\braopket}[3]{\left< #1 \vphantom{#2}\vphantom{#3} \right| #2 \vphantom{#1}\vphantom{#3} \left| #3 \vphantom{#1}\vphantom{#2} \right>}\)
\(\newcommand{\qmvec}[1]{\mathbf{\vec{#1}}}\)
\(\newcommand{\op}[1]{\hat{\mathbf{#1}}}\)
\(\newcommand{\expect}[1]{\langle #1 \rangle}\)
\(\newcommand{\dfn}[1]{\emph{\textbf{#1}}}\)
Subspace
A subspace is a subset of a vector space that is itself a vector space. The simplest example is a line through the origin in the plane. For the line is definitely a subset and if we add any two vectors on the line we remain on the line and if we multiply any vector on the line by a scalar we remain on the line. The same could be said for a line or plane through the origin in 3 space. As we shall be travelling in spaces with many many dimensions it pays to have a general definition.
A subset \(S\) of a vector space \(V\) is a subspace of \(V\) when
- if \(x\) and \(y\) belong to \(S\) then so does \(x+y\)
- if \(x\) belongs to \(S\) and \(t\) is real then \(tx\) belong to \(S\)
As these are oftentimes unwieldy objects it pays to look for a handful of vectors from which the entire subset may be generated. For example, the set of \(x\) for which \(x_{1}+x_{2}+x_{3}+x_{4} = 0\) constitutes a subspace of \(\mathbb{R}^{4}\). Can you 'see' this set? Do you 'see' that
\[\begin{pmatrix} {-1}\\ {1}\\ {0}\\ {0} \end{pmatrix} \nonumber\]
and
\[\begin{pmatrix} {-1}\\ {0}\\ {1}\\ {0} \end{pmatrix} \nonumber\]
and
\[\begin{pmatrix} {-1}\\ {0}\\ {0}\\ {1} \end{pmatrix} \nonumber\]
not only belong to a set but in fact generate all possible elements? More precisely, we say that these vectors span the subspace of all possible solutions.
A finite collection \(\{s_{1}, s_{2}, \cdots, s_{n}\}\) of vectors in the subspace \(S\) is said to span \(S\) if each element of \(S\) can be written as a linear combination of these vectors. That is, if for each \(s \in S\) there exist nn reals \(\{x_{1}, x_{2}, \cdots, x_{n}\}\) such that \(s = x_{1}s_{1}+x_{2}s_{2}+ \cdots +x_{n}s_{n}\).
When attempting to generate a subspace as the span of a handful of vectors it is natural to ask what is the fewest number possible. The notion of linear independence helps us clarify this issue.
A finite collection \(\{s_{1}, s_{2}, \cdots, s_{n}\}\) of vectors is said to be linearly independent when the only reals, \(\{x_{1}, x_{2}, \cdots, x_{n}\}\) for which \(x_{1}+x_{2} + \cdots+x_{n} = 0\) are \(x_{1} = x_{2} = \cdots = x_{n} = 0\) In other words, when the null space of the matrix whose columns are \(\{s_{1}, s_{2}, \cdots, s_{n}\}\) contains only the zero vector.
Combining these definitions, we arrive at the precise notion of a 'generating set.'
Any linearly independent spanning set of a subspace \(S\) is called a basis of \(S\)
Though a subspace may have many bases they all have one thing in common:
The dimension of a subspace is the number of elements in its basis.


