Skip to main content
Mathematics LibreTexts

11.3: Solving Equations of the Form x + a = b and x - a = b

  • Page ID
    48901
  • \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)

    \( \newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\)

    ( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\)

    \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)

    \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\)

    \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)

    \( \newcommand{\Span}{\mathrm{span}}\)

    \( \newcommand{\id}{\mathrm{id}}\)

    \( \newcommand{\Span}{\mathrm{span}}\)

    \( \newcommand{\kernel}{\mathrm{null}\,}\)

    \( \newcommand{\range}{\mathrm{range}\,}\)

    \( \newcommand{\RealPart}{\mathrm{Re}}\)

    \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)

    \( \newcommand{\Argument}{\mathrm{Arg}}\)

    \( \newcommand{\norm}[1]{\| #1 \|}\)

    \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)

    \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\AA}{\unicode[.8,0]{x212B}}\)

    \( \newcommand{\vectorA}[1]{\vec{#1}}      % arrow\)

    \( \newcommand{\vectorAt}[1]{\vec{\text{#1}}}      % arrow\)

    \( \newcommand{\vectorB}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vectorC}[1]{\textbf{#1}} \)

    \( \newcommand{\vectorD}[1]{\overrightarrow{#1}} \)

    \( \newcommand{\vectorDt}[1]{\overrightarrow{\text{#1}}} \)

    \( \newcommand{\vectE}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{\mathbf {#1}}}} \)

    \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)

    \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)

    Learning Objectives

    • understand the meaning and function of an equation
    • understand what is meant by the solution to an equation
    • be able to solve equations of the form \(x + a = b\) and \(x - a = b\)

    Equations

    Equation
    An equation is a statement that two algebraic expressions are equal.

    The following are examples of equations:

    \(\begin{array} {c} {\underbrace{x + 6}_{\text{This}}} & = & {\underbrace{10}_{\text{This}}} \\ {^\text{expression}} & ^= & {^\text{expression}} \end{array}\) \(\begin{array} {c} {\underbrace{x - 4}_{\text{This}}} & = & {\underbrace{-11}_{\text{This}}} \\ {^\text{expression}} & ^= & {^\text{expression}} \end{array}\) \(\begin{array} {c} {\underbrace{3y - 5}_{\text{This}}} & = & {\underbrace{-2 + 2y}_{\text{This}}} \\ {^\text{expression}} & ^= & {^\text{expression}} \end{array}\)

    Notice that \(x + 6\), \(x - 4\), and \(3y - 5\) are not equations. They are expressions. They are not equations because there is no statement that each of these expressions is equal to another expression.

    Solutions and Equivalent Equations

    Conditional Equations
    The truth of some equations is conditional upon the value chosen for the variable. Such equations are called conditional equations. There are two additional types of equations. They are examined in courses in algebra, so we will not consider them now.

    Solutions and Solving an Equation
    The set of values that, when substituted for the variables, make the equation true, are called the solutions of the equation.
    An equation has been solved when all its solutions have been found.

    Sample Set A

    Verify that 3 is a solution to \(x + 7 = 10\).

    Solution

    When \(x = 3\),

    becomes \(\begin{array} {rcll} {x + 7} & = & {10} & {} \\ {3 + 7} & = & {10} & {} \\ {10} & = & {10} & {\text{which is a } true \text{ statement, verifying that}} \\ {} & & {} & {\text{3 is a solution to } x + 7 = 10} \end{array}\)

    Sample Set A

    Verify that -6 is a solution to \(5y + 8 = -22\).

    Solution

    When \(y = -6\),

    becomes \(\begin{array} {rcll} {5y + 8} & = & {-22} & {} \\ {5(-6) + 8} & = & {-22} & {} \\ {-30 + 8} & = & {-22} & {} \\ {-22} & = & {-22} & {\text{which is a } true \text{ statement, verifying that}} \\ {} & & {} & {\text{-6 is a solution to } 5y + 8 = -22} \end{array}\)

    Sample Set A

    Verify that 5 is not a solution to \(a - 1 = 2a + 3\).

    Solution

    When \(a = 5\),

    becomes \(\begin{array} {rcll} {a - 1} & = & {2a + 3} & {} \\ {5 - 1} & = & {2 \cdot 5 + 3} & {} \\ {5 - 1} & = & {10 + 3} & {} \\ {4} & = & {13} & {\text{a } false \text{ statement, verifying that 5}} \\ {} & & {} & {\text{is not a solution to } a - 1 = 2a + 3} \end{array}\)

    Sample Set A

    Verify that -2 is a solution to \(3m - 2 = -4m - 16\).

    Solution

    When \(m = -2\),

    becomes \(\begin{array} {rcll} {3m - 2} & = & {-4m - 16} & {} \\ {3(-2) - 2} & = & {-4(-2) - 16} & {} \\ {-6 - 2} & = & {8 - 16} & {} \\ {-8} & = & {-8} & {\text{which is a } true \text{ statement, verifying that}} \\ {} & & {} & {\text{-2 is a solution to } 3m - 2 = -4m - 16} \end{array}\)

    Practice Set A

    Verify that 5 is a solution to \(m + 6 = 11\).

    Answer

    Substitute 5 into \(m + 6 = 11\).

    Does 5 plus 6 equal 11? Yes.

    Thus, 5 is a solution.

    Practice Set A

    Verify that −5 is a solution to \(2m - 4 = -14\).

    Answer

    Substitute -5 into \(2m - 4 = -14\).

    does 2 time negative 5 minus 4 equal negative 14? Yes.

    Thus, -5 is a solution.

    Practice Set A

    Verify that 0 is a solution to \(5x + 1 = 1\).

    Answer

    Substitute 0 into \(5x + 1 = 1\).

    Does 5 times zero plus one equal 1? Yes.

    Thus, 0 is a solution.

    Practice Set A

    Verify that 3 is not a solution to \(-3y + 1 = 4y + 5\).

    Answer

    Substitute 3 into \(-3y + 1 = 4y + 5\).

    Does negative 3 times 3 plus 1 equal 4 times 3 plus 5? No.

    Thus, 3 is not a solution.

    Practice Set A

    Verify that -1 is a solution to \(6m - 5 + 2m = 7m - 6\).

    Answer

    Substitute -1 into \(6m - 5 + 2m = 7m - 6\).

    Does 6 times negative 1 minus 5 plus 2 times negative 1 equal 7 times negative 1 minus 6? Yes.

    Thus, -1 is a solution.

    Equivalent Equations
    Some equations have precisely the same collection of solutions. Such equations are called equivalent equations. For example, \(x - 5 = -1, x + 7 = 11,\) and \(x = 4\) are all equivalent equations since the only solution to each is \(x = 4\). (Can you verify this?)

    Solving Equations

    We know that the equal sign of an equation indicates that the number represented by the expression on the left side is the same as the number represented by the expression on the right side.

    This number is the same as this number
    \(\downarrow\) \(\downarrow\) \(\downarrow\)
    \(x\) = 4
    \(x + 7\) = 11
    \(x - 5\) = -1

    Addition/Subtraction Property of Equality
    From this, we can suggest the addition/subtraction property of equality.
    Given any equation,

    1. We can obtain an equivalent equation by adding the same number to both sides of the equation.
    2. We can obtain an equivalent equation by subtracting the same number from both sides of the equation.

    The Idea Behind Equation Solving
    The idea behind equation solving is to isolate the variable on one side of the equation. Signs of operation (+, -, \(\cdot\), \(\div\)) are used to associate two numbers. For example, in the expression \(5 + 3\), the numbers 5 and 3 are associated by addition. An association can be undone by performing the opposite operation. The addition/subtraction property of equality can be used to undo an association that is made by addition or subtraction.

    Subtraction is used to undo an addition.

    Addition is used to undo a subtraction.

    The procedure is illustrated in the problems of [link].

    Sample Set B

    Use the addition/subtraction property of equality to solve each equation.

    \(x + 4 = 6\).

    Solution

    4 is associated with \(x\) by addition. Undo the association by subtracting 4 from both sides.

    \(x + 4 - 4 = 6 - 4\)

    \(x + 0 =2\)

    \(x = 2\)

    Check: When \(x = 2\), \(x + 4\) becomes

    Does 2 + 4 = 6? Yes.

    The solution to \(x + 4 = 6\) is \(x = 2\).

    Sample Set B

    \(m - 8 = 5\).

    Solution

    8 is associated with \(m\) by subtraction. Undo the association by adding 8 to both sides.

    \(m - 8 + 8 = 5 + 8\)

    \(m + 0 = 13\)

    \(m = 13\)

    Check: When \(m = 13\),

    becomes

    m - 8 = 5. After substituting, does 13 - 8 = 5? Yes.
    a true statement.

    The solution to \(m - 8 = 5\) is \(m = 13\).

    Sample Set B

    \(-3 - 5 = y - 2 + 8\).

    Solution

    Before we use the addition/subtraction property, we should simplify as much as possible.

    \(-3 - 5 = y - 2 + 8\).

    \(-8 = y + 6\)

    6 is associated with \(y\) by addition. Undo the association by subtracting 6 from both sides.

    \(-8 - 6 = y + 6 - 6\)

    \(-14 = y + 0\)

    \(-14 = y\)

    This is equivalent to \(y = -14\).

    Check: When \(y = -14\),

    \(-3 - 5 = y - 2 + 8\)

    becomes

    Does negative 3 minus 5 equal negative 14 minus 2 plus 8? Yes.

    a true statement.

    The solution to \(-3 - 5 = y - 2 + 8\) is \(y = -14\).

    Sample Set B

    \(-5a + 1 + 6a = -2\).

    Solution

    Begin by simplifying the left side of the equation.

    \(\underbrace{-5a + 1 + 6a}_{-5 + 6 = 1} = -2\)

    \(a + 1 = -2\) 1 is associated with aa by addition. Undo the association by subtracting 1 from both sides.

    \(a + 1 - 1 = -2 - 1\)

    \(a + 0 = -3\)

    \(a = -3\)

    Check: When \(a = -3\),

    \(-5a + 1 + 6a = -2\)

    becomes

    Does negative 5 times negative 3 plus 1 plus 6 times negative 3 equal negative 2? Yes.
    a true statement.

    The solution to \(-5a + 1 + 6a = -2\) is \(a = -3\).

    Sample Set B

    \(7k - 4 = 6k + 1\).

    Solution

    In this equation, the variable appears on both sides. We need to isolate it on one side. Although we can choose either side, it will be more convenient to choose the side with the larger coefficient. Since 8 is greater than 6, we’ll isolate \(k\) on the left side.

    \(7 k - 4 = 6k + 1\) Since \(6k\) represents \(+6k\), subtract \(6k\) from each side.

    \(\underbrace{7 k - 4 - 6k}_{7 - 6 = 1} = \underbrace{6k + 1 - 6k}_{6 - 6 = 0}\)

    \(k - 4 = 1\) 4 is associated with \(k\) by subtraction. Undo the association by adding 4 to both sides.

    \(k - 4 + 4 = 1 + 4\0

    \(k = 5\)

    Check: When \(k = 5\).

    \(7k - 4 = 6k + 1\)

    becomes

    Does 7 times 5 minus 4 equal 6 times 5 plus 1? Yes.

    a true statement.

    The solution to \(7k - 4 = 6k + 1\) is \(k = 5\)

    Sample Set B

    \(-8 + x = 5\).

    Solution

    -8 is associated with \(x\) by addition. Undo the by subtracting -8 from both sides. Subtracting -8 we get \(-(-8) = +8\). We actually add 8 to both sides.

    \(-8 + x + 8 = 5 + 8\)

    \(x = 13\)

    Check: When \(x = 13\)

    \(-8 + x = 5\)

    becomes

    Does negative 8 plus 13 equal 5? Yes.

    a true statement.

    The solution to \(-8 + x = 5\) is \(x = 13\).

    Practice Set B

    \(y + 9 = 4\)

    Answer

    \(y = -5\)

    Practice Set B

    \(a - 4 = 11\)

    Answer

    \(a = 15\)

    Practice Set B

    \(-1 + 7 = x + 3\)

    Answer

    \(x = 3\)

    Practice Set B

    \(8m + 4 - 7m = (-2) (-3)\)

    Answer

    \(m = 2\)

    Practice Set B

    \(12k - 4 = 9k - 6 + 2k\)

    Answer

    \(k = -2\)

    Practice Set B

    \(-3 + a = -4\)

    Answer

    \(a = -1\)

    Exercises

    For the following 10 problems, verify that each given value is a solution to the given equation.

    Exercise \(\PageIndex{1}\)

    \(x - 11 = 5\), \(x = 16\)

    Answer

    Substitue \(x = 4\) into the equation \(4x - 11 = 5\).

    \(16 - 11 = 5\)

    \(5 = 5\)

    \(x = 4\) is a solution

    Exercise \(\PageIndex{2}\)

    \(y - 4 = -6\), \(y = -2\)

    Exercise \(\PageIndex{3}\)

    \(2m - 1 = 1\), \(m = 1\)

    Answer

    Substitue \(m = 1\) into the equation \(2m - 1 = 1\).

    Does 2 minus 1 equal 1? Yes.

    \(m = 1\) is a solution.

    Exercise \(\PageIndex{4}\)

    \(5y + 6 = -14\), \(y = -4\)

    Exercise \(\PageIndex{5}\)

    \(3x + 2 - 7x = -5x - 6\), \(x = -8\)

    Answer

    Substitue \(x = -8\) into the equation \(3x + 2 - 7 = -5x - 6\).

    Does negative 24 plus 2 minus 7 equal 40 minus 6? Yes.

    \(x = -8\) is a solution.

    Exercise \(\PageIndex{6}\)

    \(-6a + 3 + 3a = 4a + 7 - 3a\), \(a = -1\)

    Exercise \(\PageIndex{7}\)

    \(-8 + x = -8\), \(x = 0\)

    Answer

    Substitue \(x = 0\) into the equation \(-8 + x = -8\).

    Does negative 8 plus 0 equal negative 8? Yes.

    \(x = 0\) is a solution.

    Exercise \(\PageIndex{8}\)

    \(8b + 6 = 6 - 5b\), \(b = 0\)

    Exercise \(\PageIndex{9}\)

    \(4x - 5 = 6x - 20\), \(x = \dfrac{15}{2}\)

    Answer

    Substitue \(x = \dfrac{15}{2}\) into the equation \(4x - 5 = 6x - 20\).

    Does 30 minus 5 equal 45 minus 20? Yes.

    \(x = \dfrac{15}{2}\) is a solution

    Exercise \(\PageIndex{10}\)

    \(-3y + 7 = 2y - 15\), \(y = \dfrac{22}{5}\)

    Solve each equation. Be sure to check each result.

    Exercise \(\PageIndex{11}\)

    \(y - 6 = 5\)

    Answer

    \(y = 11\)

    Exercise \(\PageIndex{12}\)

    \(m + 8 = 4\)

    Exercise \(\PageIndex{13}\)

    \(k - 1 = 4\)

    Answer

    \(k = 5\)

    Exercise \(\PageIndex{14}\)

    \(h - 9 = 1\)

    Exercise \(\PageIndex{15}\)

    \(a + 5 = -4\)

    Answer

    \(a = -9\)

    Exercise \(\PageIndex{16}\)

    \(b - 7 = -1\)

    Exercise \(\PageIndex{17}\)

    \(x + 4 - 9 = 6\)

    Answer

    \(x = 11\)

    Exercise \(\PageIndex{18}\)

    \(y - 8 + 10 = 2\)

    Exercise \(\PageIndex{19}\)

    \(z + 6 = 6\)

    Answer

    \(z = 0\)

    Exercise \(\PageIndex{20}\)

    \(w - 4 = -4\)

    Exercise \(\PageIndex{21}\)

    \(x + 7 - 9 = 6\)

    Answer

    \(x = 8\)

    Exercise \(\PageIndex{22}\)

    \(y - 2 + 5 = 4\)

    Exercise \(\PageIndex{23}\)

    \(m + 3 - 8 = -6 + 2\)

    Answer

    \(m = 1\)

    Exercise \(\PageIndex{24}\)

    \(z + 10 - 8 = -8 + 10\)

    Exercise \(\PageIndex{25}\)

    \(2 + 9 = k - 8\)

    Answer

    \(k = 19\)

    Exercise \(\PageIndex{26}\)

    \(-5 + 3 = h - 4\)

    Exercise \(\PageIndex{27}\)

    \(3m - 4 = 2m + 6\)

    Answer

    \(m = 10\)

    Exercise \(\PageIndex{28}\)

    \(5a + 6 = 4a - 8\)

    Exercise \(\PageIndex{29}\)

    \(8b + 6 + 2b = 3b - 7 + 6b - 8\)

    Answer

    \(b = -21\)

    Exercise \(\PageIndex{30}\)

    \(12h - 1 - 3 - 5h = 2h + 5h + 3(-4)\)

    Exercise \(\PageIndex{31}\)

    \(-4a + 5 - 2a = -3a - 11 - 2a\)

    Answer

    \(a = 16\)

    Exercise \(\PageIndex{32}\)

    \(-9n - 2 - 6 + 5n = 3n - (2) (-5) - 6n\)

    Calculator Exercises

    Exercise \(\PageIndex{33}\)

    \(y - 2.161 = 6.063\)

    Answer

    \(y = 7.224\)

    Exercise \(\PageIndex{34}\)

    \(a - 44.0014 = -21.1625\)

    Exercise \(\PageIndex{35}\)

    \(-0.362 - 0.416 = 5.63m - 4.63m\)

    Answer

    \(m = -0.778\)

    Exercise \(\PageIndex{36}\)

    \(8.078 - 9.112 = 2.106y - 1.106y\)

    Exercise \(\PageIndex{37}\)

    \(4.23k + 3.18 = 3.23k - 5.83\)

    Answer

    \(k = -9.01\)

    Exercise \(\PageIndex{38}\)

    \(6.1185x - 4.0031 = 5.1185x - 0.0058\)

    Exercise \(\PageIndex{39}\)

    \(21.63y + 12.40 - 5.09y = 6.11y - 15.66 + 9.43y\)

    Answer

    \(y = -28.06\)

    Exercise \(\PageIndex{40}\)

    \(0.029a - 0.013 - 0.034 -0.057 = -0.038 + 0.56 + 1.01a\)

    Exercises for Review

    Exercise \(\PageIndex{41}\)

    Is \(\dfrac{\text{7 calculators}}{\text{12 students}}\) an example of a ratio or a rate?

    Answer

    rate

    Exercise \(\PageIndex{42}\)

    Convert \(\dfrac{3}{8}\)% to a decimal

    Exercise \(\PageIndex{43}\)

    0.4% of what number is 0.014?

    Answer

    3.5

    Exercise \(\PageIndex{44}\)

    Use the clustering method to estimate the sum: \(89 + 93 + 206 + 198 + 91\)

    Exercise \(\PageIndex{45}\)

    Combine like terms: \(4x + 8y + 12y + 9x - 2y\).

    Answer

    \(13x + 18y\)


    This page titled 11.3: Solving Equations of the Form x + a = b and x - a = b is shared under a CC BY license and was authored, remixed, and/or curated by Denny Burzynski & Wade Ellis, Jr. (OpenStax CNX) .