2.1.1: Exercises 2.1
- Page ID
- 62898
\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)
\( \newcommand{\dsum}{\displaystyle\sum\limits} \)
\( \newcommand{\dint}{\displaystyle\int\limits} \)
\( \newcommand{\dlim}{\displaystyle\lim\limits} \)
\( \newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\)
( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\)
\( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)
\( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\)
\( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)
\( \newcommand{\Span}{\mathrm{span}}\)
\( \newcommand{\id}{\mathrm{id}}\)
\( \newcommand{\Span}{\mathrm{span}}\)
\( \newcommand{\kernel}{\mathrm{null}\,}\)
\( \newcommand{\range}{\mathrm{range}\,}\)
\( \newcommand{\RealPart}{\mathrm{Re}}\)
\( \newcommand{\ImaginaryPart}{\mathrm{Im}}\)
\( \newcommand{\Argument}{\mathrm{Arg}}\)
\( \newcommand{\norm}[1]{\| #1 \|}\)
\( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\)
\( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\AA}{\unicode[.8,0]{x212B}}\)
\( \newcommand{\vectorA}[1]{\vec{#1}} % arrow\)
\( \newcommand{\vectorAt}[1]{\vec{\text{#1}}} % arrow\)
\( \newcommand{\vectorB}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\( \newcommand{\vectorC}[1]{\textbf{#1}} \)
\( \newcommand{\vectorD}[1]{\overrightarrow{#1}} \)
\( \newcommand{\vectorDt}[1]{\overrightarrow{\text{#1}}} \)
\( \newcommand{\vectE}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{\mathbf {#1}}}} \)
\( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}} } \)
\(\newcommand{\longvect}{\overrightarrow}\)
\( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash {#1}}} \)
\(\newcommand{\ket}[1]{\left| #1 \right>}\)
\(\newcommand{\bra}[1]{\left< #1 \right|}\)
\(\newcommand{\braket}[2]{\left< #1 \vphantom{#2} \right| \left. #2 \vphantom{#1} \right>}\)
\(\newcommand{\braopket}[3]{\left< #1 \vphantom{#2}\vphantom{#3} \right| #2 \vphantom{#1}\vphantom{#3} \left| #3 \vphantom{#1}\vphantom{#2} \right>}\)
\(\newcommand{\qmvec}[1]{\mathbf{\vec{#1}}}\)
\(\newcommand{\op}[1]{\hat{\mathbf{#1}}}\)
\(\newcommand{\expect}[1]{\langle #1 \rangle}\)
\(\newcommand{\dfn}[1]{\emph{\textbf{#1}}}\)
Terms and Concepts
Exercise \(\PageIndex{1}\)
Explain the difference between point-slope form and slope-intercept form.
- Answer
-
Answers will vary.
Exercise \(\PageIndex{2}\)
To uniquely determine a line, what information do you need?
- Answer
-
A point and a slope, or two points
Exercise \(\PageIndex{3}\)
What is the slope of a horizontal line?
- Answer
-
\(m=0\)
Exercise \(\PageIndex{4}\)
A line goes through the point \((0,6)\). Is this the y-intercept of the line or the x-intercept of the line? Explain.
- Answer
-
This is the y-intercept because \(x=0\) so it is where the line crosses the y-axis.
Exercise \(\PageIndex{5}\)
Line 1 has a slope of \(m_1=2\). If line 2 is parallel to line 1, what is \(m_2\)?
- Answer
-
\(m_2=2\)
Exercise \(\PageIndex{6}\)
Line 1 has a slope of \(m_1=-4\). If line 2 is perpendicular to line 1, what is \(m_2\)?
- Answer
-
\(m_2=\frac{1}{4}\)
Problems
In exercises \(\PageIndex{7}\) - \(\PageIndex{16}\), write an equation for each line in the indicated form.
Exercise \(\PageIndex{7}\)
Write the equation in point-slope form for the line that passes through \((1,2)\) and is parallel to the line \(2x+y=5\).
- Answer
-
\(y-2=-2(x-1)\)
Exercise \(\PageIndex{8}\)
Write the equation of the line in slope-intercept form passing through the points \((1,2)\) and \((-1,4)\).
- Answer
-
\(y=-x+3\)
Exercise \(\PageIndex{9}\)
Write the equation in point-slope form for the line that passes through \((0,4)\) and is perpendicular to the line \(x-2y=6\).
- Answer
-
\(y-4=-2(x-0)\)
Exercise \(\PageIndex{10}\)
Write the equation of the line in slope-intercept form passing through the points \((-1,0)\) and \((3,6)\).
- Answer
-
\(y=\frac{3}{2}x + \frac{3}{2}\)
Exercise \(\PageIndex{11}\)
Write the equation of the line in slope-intercept form passing through the points \((-2,1)\) and \((2,7)\).
- Answer
-
\(y=\frac{3}{2}x + 4\)
Exercise \(\PageIndex{12}\)
Consider the linear function \(f(x)=2x-8\). What is the value of the function when \(x=0.1\)?
- Answer
-
\(-7.8\)
Exercise \(\PageIndex{13}\)
Write the equation in slope-intercept form for the line that passes through \((-2,2)\) and is perpendicular to the line \(x+3y=8\).
- Answer
-
\(y=3x+8\)
Exercise \(\PageIndex{14}\)
Write the equation in point-slope form of the line that passing through the points \((3,6)\) and \((7,4)\).
- Answer
-
\(y-4=\frac{1}{2}(x-7)\), or \(y-6=-\frac{1}{2}(x-3)\)
Exercise \(\PageIndex{15}\)
Write the equation of the line passing through the points \((-4,4)\) and \((0,-4)\) in slope-intercept form.
- Answer
-
\(y=-2x-4\)
Exercise \(\PageIndex{16}\)
Write the equation of the line parallel to \(y=6x+4\) that has a y-intercept of \(2\) in point-slope form.
- Answer
-
\(y-2=6(x-0)\)
In exercises \(\PageIndex{17}\) - \(\PageIndex{20}\), answer each question about the properties of the given line(s).
Exercise \(\PageIndex{17}\)
Consider the linear function \(g(x)=-4x+5\). What is the slope of the function when \(x=4\)?
- Answer
-
\(m=-4\)
Exercise \(\PageIndex{18}\)
Determine the x-intercept of the line \(y=4x-8\).
- Answer
-
\((2,0)\)
Exercise \(\PageIndex{19}\)
Determine the y-intercept of the line \(y=4x-8\).
- Answer
-
\((0,-8)\)
Exercise \(\PageIndex{20}\)
Which line has a steeper slope: \(y=5x+10\) or the line passing through the points \((-5,0)\) and \((0,11)\)?
- Answer
-
The line \(y=5x+10\) has a steeper slope.


